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ma_m = na_n
m[a + (m - 1)d] = n [a + (n - 1)d]
{tex} \Rightarrow {/tex} ma + m²d - md = na + n²d - nd
{tex} \Rightarrow {/tex} a(m - n) + (m² - n²)d - md + nd = 0
{tex} \Rightarrow {/tex} a(m - n) + (m - n) (m + n)d - (m - n)d = 0
{tex} \Rightarrow {/tex} (m - n) [a + (m + n - 1)d] = 0
{tex} \Rightarrow {/tex} a + (m + n - 1)d = 0
{tex} \Rightarrow {/tex} a_m+n = 0
Hence proved.

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ANSWER

LCM×HCF=product of two nombers

Posted by Karan Sharma 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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If triangle ABC~ triangle RPQ,AB=3,BC=5,AC=6,RP=6 and find PQ =10 then find QR.

Posted by Sachin Kumar 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Sankalp Kumar 7 years, 9 months ago

QR = 12

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If x=3 is one root of the quadratic of x x -2k -6=0 then find the value of k

Posted by Vishesh Basoya 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Given quadratic equation is x² - 2kx - 6 = 0
If x = 3 is one root of the equation,
then (3)² - 2k(3) - 6 = 0
{tex}\therefore{/tex} 9 - 6k - 6 = 0
{tex}\Rightarrow{/tex}-6k = -3
{tex}\Rightarrow{/tex} k = {tex}\frac{1}{2}{/tex}

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In an AP the common difference (d) and seventh term is 4 then find first term

Posted by Sunny Rexwal 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Sankalp Kumar 7 years, 9 months ago

A = -20

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HCF and LCM of 404 and 96 and verify that HCF ×LCM = product of two no.

Posted by Ankit Jakhar 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Prime factorisation of 404 and 96 is:
404 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 101
404 = 2² {tex}\times{/tex} 101
96 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 3
96 = 2⁵ {tex}\times{/tex} 3
{tex}\therefore{/tex} HCF(404,96 )= 2² = 4
LCM(404, 96 ) = 101 {tex}\times{/tex} 2⁵ {tex}\times{/tex} 3
LCM( 404, 96) = 9696
now we have to verify that,
HCF(404, 96) {tex}\times{/tex}LCM(404, 96) = 404{tex}\times{/tex}96
Hence,
LHS = HCF {tex}\times{/tex} LCM
= 4 {tex}\times{/tex} 9696
= 38784
RHS= Product of numbers
=404 {tex}\times{/tex} 96 = 38784

Since, LHS=RHS
i.e. HCF {tex}\times{/tex} LCM = Product of 404 and 96.
hence verified

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If sin (A-B)=1/2 and sin (A+B)=1 ,then find the value of A&B

Posted by Harsh Sharma 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Rekha Varshini 7 years, 9 months ago

A =60°, B = 30°

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If x-3 is one of the root of the equation of x2+2kx-6 then find the value of k

Posted by Karan Arora 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Kajal Vaishnav 7 years, 9 months ago

K=1/2 x-3=0 X=3

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What is the formula of minor segment, major segment, sectors, major sector, minor sector

Posted by Harsh Sharma 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Given √2 is irrational number prove (5+3√3)is an irrational number

Posted by Karan Sharma 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

HCF and LCM of 404 and 96 and verify that HCF ×LCM =product of two no

Posted by Ankit Jakhar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Prime factorisation of 404 and 96 is:
404 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 101
404 = 2² {tex}\times{/tex} 101
96 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 3
96 = 2⁵ {tex}\times{/tex} 3
{tex}\therefore{/tex} HCF(404,96 )= 2² = 4
LCM(404, 96 ) = 101 {tex}\times{/tex} 2⁵ {tex}\times{/tex} 3
LCM( 404, 96) = 9696
now we have to verify that,
HCF(404, 96) {tex}\times{/tex}LCM(404, 96) = 404{tex}\times{/tex}96
Hence,
LHS = HCF {tex}\times{/tex} LCM
= 4 {tex}\times{/tex} 9696 = 38784
RHS= Product of numbers =404 {tex}\times{/tex} 96 = 38784
Since, LHS=RHS
i.e. HCF {tex}\times{/tex} LCM = Product of 404 and 96.
hence verified

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ANSWER

Given triangle ABC or triangle PQR of AB/PQ=1/3 then find arABC/arPQR

Posted by Karan Sharma 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Karan Sharma 7 years, 9 months ago

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Find the ratio in which p(4,m)divided the lime segment joining the points A(2,3)and B(6,-3)him find m

Posted by Monu Chauhan 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Nyayir Riba 7 years, 9 months ago

m1=2,m2=2 and m=0

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Gagan Ahuja 7 years, 9 months ago

Ratio is 1:1 and m=0

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let p be a prime number . if p I'd divisible a2 the p divides a where a Is a positive integer.

Posted by Sujit Gore 7 years, 9 months ago

CBSE > Class 10 > Mathematics

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Two different dice are tossed together. Find the probability: 1. Of getting a doublet,2. Of getting a sum of 10 the number less on the two dice

Posted by Deepanshi Goyal 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Total number of possible outcomes = 36

Doublet are { (1, 1) (2, 2) (3, 3) (4, 4) (5, 5) (6, 6)}.
Total number of doublets = 6
{tex}\therefore{/tex} Prob (getting a doublet) = {tex}\frac{6}{36}{/tex}={tex}\frac{1}{6}{/tex}
Outcome whose sum of digits is 10 ={(4, 6) (5, 5) (6, 4)}.
Number of favorable outcomes =3
{tex}\therefore{/tex} Prob (getting a sum 10) = {tex}\frac{3}{36}{/tex} ={tex}\frac{1}{12}{/tex}