CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

If area is equal then the square of ratios of similar part will be equal to one and hence all similar parts will be equal and bySSS congruency ....they will be congruent

2Thank You

Nikhil Soni 7 years, 9 months ago

Kya question pucha h whaaa

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guys plss help krdo btado yrr answers plss...i will be so thankful to u

Posted by Yukku Malik 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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In an ap the common difference is D and 7 term (a7)154,then find the first term

Posted by Kumkum Gupta 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Nyayir Riba 7 years, 9 months ago

a=-770

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Nikhil Soni 7 years, 9 months ago

First term is 22?

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ANSWER

Prove that the tangent at the extermities of any chord make equal angles with the chord

Posted by Nikhil Soni 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Let AB be a chord of a circle with centre O, and let AP and BP be the tangents at A and B respectively. Let the two tangents AP and BP meets at P.
Now Join OP. Suppose OP meets AB at C and the chord AB=AC+BC.
We have to prove that {tex}\angle P A C = \angle P B C{/tex}
In two triangles PCA and PCB, we have
PA = PB [{tex} \because{/tex}Tangents from an external point are equal]
{tex}\angle A P C = \angle B P C{/tex} [{tex} \because {/tex} PA and PB are equally inclined to OP]
and, PC = PC [Common]
So, by SAS-criterion of congruence, we obtain
{tex}\Delta P A C \cong \Delta P B C{/tex}
{tex}\Rightarrow \quad \angle P A C = \angle P B C{/tex}

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sum of 4 consecutive numbers of an ap is 37 &ratio of product og 1st & last term to the product of the two middle terms is 7:15 thn find the numbers

Posted by Yukku Malik 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Kuchh important question batau dosto

Posted by Teerth Raj Chaudhary 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Teerth Raj Chaudhary 7 years, 9 months ago

Ha thanks

1Thank You

Khushbu . 7 years, 9 months ago

k ki value find krne wala 4 chapter se aur surface area and volume se questions 7,8,9of exercise 13.3

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the diameter of the lower and upper ends of a buckets in the form of a frustum of cone are 10cm and 30cm respectively its hegiht is 24cm find the area of the metal sheet used to make the bucket

Posted by Ayush Raj 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Yukku Malik 7 years, 9 months ago

kha se mila yeh ques same as mine

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ANSWER

the diameter of a lower and upper ends of a bucket in the form of a frustum of a cone are 10 cm and 30 cm . if heighr is 24 then find the area if metal sheet used in making bucket ?

Posted by Yukku Malik 7 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Nyayir Riba 7 years, 9 months ago

Phle height se slant height nikal lejiye formula[l=root h²+(r1-r2)] Ar of metal sheet =c.s.a of frustom +base of lower end(circle) pie(r1+r2)slant height + pie×r2². 22/7(15+5)2root194+22/7×5×5. 22/7[20×2root194+25]. 22/7[40root194+25]. 22/7×40root194 + 22/7×25. (880root194+550)/7 cm²

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Yukku Malik 7 years, 9 months ago

thanks but pls someone tell me complete ans

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Nyayir Riba 7 years, 9 months ago

May be (880root194+550÷7)not sure and slant height =root776

1Thank You

ANSWER

Best of luck to all of you for maths exam I wish you all do well

Posted by Sahil Godara 7 years, 9 months ago

CBSE > Class 10 > Mathematics

4 answers

Charu Vatsal 7 years, 9 months ago

Thanks and same 2 u

1Thank You

Nyayir Riba 7 years, 9 months ago

Thnk n same to you...

2Thank You

Aisha Singh 7 years, 9 months ago

Same to you dear....????

1Thank You

Kanika Bareja 7 years, 9 months ago

Haa shayad apki dua hii kaam krr jae thnk uu for wishing???

1Thank You

ANSWER

What is hcf of smallest prime number and smallest composite number

Posted by Satyam Raj 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If the area of two similar triangles are equal prove that they are congruent

Posted by Garima Rana 7 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Abhijeet Singh 7 years, 9 months ago

Hope i was able to make you understand....

1Thank You

Abhijeet Singh 7 years, 9 months ago

You can do so by equating the ratio of the two triangles with the square of the ratios of the two corresponding sides. From there you can find that those sides will come out ti be equal as the areas of two triangles were equal so they will cancel out each other. Likewise you can prove for other sides too. Then, by using the sss criterion of congruence, you can prove them congruent

1Thank You

Abhishek Sharma 7 years, 9 months ago

Yes

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Cos2 67-sin2 23

Posted by Ajay Sha 7 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Nyayir Riba 7 years, 9 months ago

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Abhishek Sharma 7 years, 9 months ago

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ANSWER

Find the value of c for which the pair of linear equations cx-y=2 and 6x-2y=3 will have infinitely manu solutions

Posted by Ayush Arora 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Kavya Sharma 7 years, 9 months ago

a1/a2=b1/b2=c1/c2 for infinite many solution so value of c is 1 or 4

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Best of luck All of you

Posted by Shreyash Srivastava 7 years, 9 months ago

CBSE > Class 10 > Mathematics

5 answers

♥️Bhavika Naik?? 7 years, 9 months ago

Thanks

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Aisha Singh 7 years, 9 months ago

Same to you and thank you

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Teerth Raj Chaudhary 7 years, 9 months ago

Same to you

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Nikhil Soni 7 years, 9 months ago

Thanks

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Kanika Bareja 7 years, 9 months ago

Thnkuu soo vala much??

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What is the value of cos square 67°-sin square23°

Posted by Mansi Gupta 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

cos² 67° - sin² 23°

= cos² 67° - sin² (90°- 67°)

= cos² 67° - cos² 67° [since, sin(90^o-a) = cos a]

= 0

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show that n, n+1,n+2,n+3 is divisible by 3

Posted by Neha Kumari 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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If an appointment the common difference K and seventh term a7= 134 then find the first term

Posted by Ayushi Sharma 7 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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If x=3 is one root of the quadratib of x2-2kx-6=0

Posted by Diya Singh 7 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Teerth Raj Chaudhary 7 years, 9 months ago

1/2

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This time for class 10th result will come in cgpa or percentage or grading system

Posted by Rajat Raj 7 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Someone ?? 7 years, 9 months ago

1Thank You

Kanika Bareja 7 years, 9 months ago

Percentage

2Thank You

Kushal Vaghela 7 years, 9 months ago

Percentage

1Thank You

ANSWER

Find the distance of a point p(x,y) from the origin

Posted by Kamran Qureshi 7 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Nikhil Soni 7 years, 9 months ago

Open pg no. 172 of ncert book and read summary point no. 2

1Thank You

Nikhil Soni 7 years, 9 months ago

√x2+y2

2Thank You

Anmol Sharma 7 years, 9 months ago

Root(x^2+y^2)

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ANSWER

4 tan q =3 evaluate (4 sin q- cos q+1)/(4sin q+cos q-1)

Posted by Ajay Yadav 7 years, 9 months ago

CBSE > Class 10 > Mathematics

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If one diagonal if trapezium cuts the other diaganol in the ratio 1:3

Posted by Ann Maria 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

DE = EB = 1:3
In {tex}\triangle{/tex}AEB and {tex}\triangle{/tex}CED, {tex}\angle 1 = \angle 2{/tex} (alternate angles)

{tex}\angle 3 = \angle 4{/tex} (Vertically opposite angles.)
{tex}\therefore \quad \Delta \mathrm { AEB } \sim \Delta \mathrm { CED }{/tex}
{tex}\Rightarrow \quad \frac { \mathrm { AB } } { \mathrm { CD } } = \frac { \mathrm { BE } } { \mathrm { DE } } \Rightarrow \frac { \mathrm { AB } } { \mathrm { CD } } = \frac { 3 } { 1 }{/tex} [{tex}\because {/tex} DE: BE = 1:3]
{tex}\Rightarrow{/tex} AB = 3CD

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Show that only one of n, n+2,n+4. Is divisible by 3

Posted by Madhav Khurana 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Let the number be (3q + r)
{tex}n = 3 q + r \quad 0 \leq r < 3{/tex}
{tex}\text { or } 3 q , 3 q + 1,3 q + 2{/tex}
{tex}\text { If } n = 3 q \text { then, numbers are } 3 q , ( 3 q + 1 ) , ( 3 q + 2 ){/tex}
{tex}3 q \text { is divisible by } 3{/tex}.
{tex}\text { If } n = 3 q + 1 \text { then, numbers are } ( 3 q + 1 ) , ( 3 q + 3 ) , ( 3 q + 4 ){/tex}
{tex}( 3 q + 3 ) \text { is divisible by } 3{/tex}.
{tex}\text { If } n = 3 q + 2 \text { then, numbers are } ( 3 q + 2 ) , ( 3 q + 4 ) , ( 3 q + 6 ){/tex}
{tex}( 3 q + 6 ) \text { is divisible by } 3{/tex}.
{tex}\therefore \text { out of } n , ( n + 2 ) \text { and } ( n + 4 ) \text { only one is divisible by } 3{/tex}.