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  • 1 answers

Sia ? 4 years, 1 month ago

Complete your question.

  • 2 answers

Khushi Kulshrestha 4 years, 1 month ago

Means 8 square is 64 and 6 square is 36 add both . 100 will come take the square root of it , the ans is 10

Khushi Kulshrestha 4 years, 1 month ago

U can use a trick here.which is that take the square root of squares of radii.
  • 3 answers

Priya . 4 years ago

2

Arshdeep Kataria 4 years, 1 month ago

Thankyou

Kaviya Sudhan 4 years, 1 month ago

Hence any integer is of one of the form 2q, 2q+1. Hence n(n+1) = 2((2q+1)(q+1)), which is even. Hence n(n+1) is always even. Hence the product of two consecutive integers is always divisible by 2.
  • 1 answers

Sia ? 4 years, 1 month ago

1.A cut out of a geometrical figure such as a triangle is made and placed on a rectangular sheet of paper marked with X and Y-axis.

2.The co-ordinates of the vertices of the triangle and its centroid are noted.

3.The triangular cut out is displaced(along x-axis, along y-axis or along any other direction.)

4.The new co-ordinates of the vertices and the centroid are noted again.

5.The procedure is repeated, this time by rotating the triangle as well as displacing it. The new co-ordinate of vertices and centroid are noted again. Displacement and rotation of a geometrical figure.

6.Using the distance formula, distance between the vertices of the triangle are obtained for the triangle in original position and in various displaced and noted positions.

7.Using the new coordinates of the vertices and the centroids, students will obtain the ratio in which the centroid divides the medians for various displaced and rotated positions of the triangles.

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Vansh Kumawat 4 years, 1 month ago

x=4 , y=3 by substitution method
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  • 1 answers

Divyanshi Saxena 4 years, 1 month ago

Let α,β be the other zeros of the given polynomial x 3 +ax 2 +bx +c Sum of the zeros = coefficient of x 3 −coefficient of x 2 ​ ⇒−1+α+β= 1 −a ​ =−a ⇒α+β=−a+1 (i) Again, (−1)α+αβ+(−1)β= coefficient of x 3 −coefficient of x ​ ⇒−α+αβ−β= 1 b ​ =αβ=b+α+β α+β=−a+1 , from (i)) =b−a+1
  • 2 answers

Shayam Sahani 4 years, 1 month ago

Sare answer

Nitesh Meena 4 years, 1 month ago

Bhio
  • 1 answers

Sumit Yadav 4 years, 1 month ago

p(x) = 16x2 - 25 = 4x2 - 52 = ( 4x - 5 ) ( 4x + 5 ) 4x - 5 = 0 4x = 5 x = 5 / 4 or alpha = 5 / 4 4x + 5 = 0 4x = -5 x = -5 / 4 or beta = -5/ 4 !st relation, ax2 + bx +c a = 16 , b = 0 and c = -25 alpha + beta = - b / a LHS = RHS 5 / 4+ - 5 / 4 = - 0 / 16 0 = 0 L.H.S = R.H.S 2nd relationship Alpha x beta = c / a LHS = RHS 5 / 4 x - 5/ 4 = - 25 / 16 -25 / 16 L.H.S = R.H.S
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Sumit Yadav 4 years, 1 month ago

(v) (cos A – sin A + 1) / (cos A + sin A – 1) = cosec A + cot A using the identity cosec2A = 1 + cot2A Solving LHS Multiplying numerator and denominator by (cot A – 1 + cosec A) = (cot2A + 1 + cosec2A – 2*cot A – 2*cosec A + 2*cot A*cosec A) / (cot2A – (1 + cosec2A – 2*cosec A)) = (2*cosec2A – 2*cot A – 2*cosec A + 2*cot A*cosec A) / (cot2A – 1 – cosec2A + 2*cosec A)  = (2* cosec A *(cosec A + cot A) – 2*(cosec A + cot A)) / (cot2A – 1 – cosec2A + 2*cosec A) = ((cosec A + cot A) * (2*cosec A – 2 )) / (2*cosec A – 2)  = cosec A + cot A = RHS Hence Proved
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Chahak Nashine 4 years, 1 month ago

Q1 (i) similar (ii) similar (iii) equilateral Q2 (i) 2 equilateral triangles of length 2&4 cms. 2 squares of length 1&2 cms. (ii) trapezium & square Triangle & rectriangle. Q3 They are not similar as their corresponding sides are proportional i.e 1:2 but their corresponding angles are not equal.

Agrim Mishra 4 years, 1 month ago

Lin
  • 1 answers

Sia ? 4 years, 1 month ago

Let the given number when divided by 143 give q as quotient and 31 as remainder. Then, number = 143q + 31 { 13×11q+13×2+5)=13×(11q+2)+5
So , the same number when divided by 13 gives 5 as remiander.

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Rohan Kumar Thakur 4 years, 1 month ago

SecA -1+SecA+1=SecA+SecA=2SecA
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C.J.Ramiya Krishna 4 years, 1 month ago

Consistent

Harshika Yadav 4 years, 1 month ago

consistent

Mishty Panchal 4 years, 1 month ago

Consistent
  • 4 answers

Khushi Kulshrestha 4 years, 1 month ago

1 rupee coins -25 &2 rupee coins -25

Harshika Yadav 4 years, 1 month ago

Let number of Re.1 coin =x Number of Re. 2 coin =y A/q, x+y=50 ..............................(i) x+2y=75 ..............................(ii) On Solving eqn. (i) and (ii), we get x=25 and y=25

Anmol B 4 years, 1 month ago

GIVEN: Total no. of coins = 50 Total amount of money = ₹75 TO FIND: No. of ₹1 and ₹2 coins. SOLUTION: Let the no. of ₹1 coins be x and ₹2 coins be y. So, 1(no. of ₹1 coins)+2(no. of ₹2 coins) = Total money 1x+2y=75 --------(1) Now, No. of ₹1 coins + No. of ₹2 coins = Total no. of coins x+y=50 ----------(2) Subtracting eq.(2) from eq.(1) (x+2y)-(x+y)=75-50 x+2y-x-y=25 y=25 Now, From eq.(2) x+y=50 x+25=50 x=50-25 x=25 Therefore, there are 25 no. of ₹1 coins and 25 no. of ₹2 coins.

Niyati Sharma 4 years, 1 month ago

1rupee coins- 25, 2rupeecoins- 25
  • 1 answers

Sia ? 4 years ago

In the first case:

Height of slide= 1.5 m and angle of elevation = 30°
Now,
{tex}\sin \theta=\frac{p}{h}{/tex}
where p = perpendicular, i.e. height of the slide and h = hypotenuse, i.e. length of the slide and {tex}\theta{/tex} is the angle of elevation
{tex}\sin 30^{\circ}=\frac{1.5}{h}{/tex}
{tex}\frac{1}{2}=\frac{1.5}{h}{/tex}
Hence, h = 3 m
In the second case:

Height of slide, = 3 m, angle of elevation = 60°
{tex}\sin \theta=\frac{p}{h}{/tex}
{tex}\sin 60^{\circ}=\frac{3}{h}{/tex}
{tex}\frac{\sqrt{3}}{2}=\frac{3}{h}{/tex}
Hence, h = {tex}2{\sqrt{3}}{/tex} m
Therefore, the length of the slide in the first and the second case are 3 m and {tex}2{\sqrt{3}}{/tex} m respectively.

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Niyati Sharma 4 years, 1 month ago

Not defined
  • 2 answers

Sia ? 4 years, 1 month ago

A consistent system of equations has at least one solution, and an inconsistent system has no solution.

Saksham Mishra 4 years, 1 month ago

Consistent means there is 1 or more solution to any equation Ex. Coincident and intersecting lines Inconsistent means there is no solution to any quadratic equation Ex. Parallel line
  • 1 answers

Abhi Shek 4 years ago

cosec theta + cot theta

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