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Find the zeros of a polynomial …

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Find the zeros of a polynomial 16 X square - 25 and verify the relationship between the zeros and the cofficient
  • 1 answers

Sumit Yadav 2 years, 6 months ago

p(x) = 16x2 - 25 = 4x2 - 52 = ( 4x - 5 ) ( 4x + 5 ) 4x - 5 = 0 4x = 5 x = 5 / 4 or alpha = 5 / 4 4x + 5 = 0 4x = -5 x = -5 / 4 or beta = -5/ 4 !st relation, ax2 + bx +c a = 16 , b = 0 and c = -25 alpha + beta = - b / a LHS = RHS 5 / 4+ - 5 / 4 = - 0 / 16 0 = 0 L.H.S = R.H.S 2nd relationship Alpha x beta = c / a LHS = RHS 5 / 4 x - 5/ 4 = - 25 / 16 -25 / 16 L.H.S = R.H.S
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