A no when divided by 143 …
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Sia ? 2 years, 6 months ago
Let the given number when divided by 143 give q as quotient and 31 as remainder. Then, number = 143q + 31 { 13×11q+13×2+5)=13×(11q+2)+5
So , the same number when divided by 13 gives 5 as remiander.
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