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According to the question _ 70 - 5 = 60 and 125 - 8 = 117 Hcf of 60 and 117 = 13 Therefore the largest number which divides 70 125 leaving remainder 5 and 8 is 13

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Sneha Swami 4 years ago

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Find the zeroes of the cubic polynomials p(m)=m³-8m²+19.-12

Posted by Aalim Malik 4 years ago

CBSE > Class 10 > Mathematics

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A chord of circle of radius 12 cm subtends an angle of 120° at centre. Find the corresponding segment of the circle. (Use π=3.14 and √3=1.73.)

Posted by Ankita Patel 4 years ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years ago

r = 12 cm, {tex}\theta{/tex} = 120^o
{tex}\therefore{/tex} Area of the corresponding sector of the circle = {tex}\frac\theta{360^\circ}\mathrm{πr}^2\;=\;\frac{\displaystyle120}{\displaystyle360^\circ}\times3.14\;\times12\times12\;{/tex}= 150.72 cm²
Area of {tex}\triangle{/tex}AOB
Draw OM {tex}\perp{/tex} AB
In right triangle OMA and OMB,
OA = OB ....... Radii of the same circle
OM = OM ........ Common side
{tex}\therefore{/tex} {tex}\triangle{/tex}OMA {tex}\cong{/tex} {tex}\triangle{/tex}OMB ........RHS congruence criterion
{tex}\therefore{/tex} AM = BM ....... CPCT
{tex}\Rightarrow{/tex} AM = BM = {tex}\frac 12{/tex}AB
and {tex}\angle{/tex}AOM = {tex}\angle{/tex}BOM [CPCT]
{tex}\Rightarrow{/tex} {tex}\angle{/tex}AOM = {tex}\angle{/tex}BOM = {tex}\frac 12{/tex}{tex}\angle{/tex}AOB
= {tex}\frac 12{/tex} {tex}\times{/tex} 120^o = 60^o
{tex}\therefore{/tex} In right triangle OMA,
cos60^o = {tex}\frac {OM}{OA}{/tex}
{tex}\Rightarrow{/tex} {tex}\frac 12{/tex}= {tex}\frac {OM}{12}{/tex}
{tex}\Rightarrow{/tex} OM = 6 cm
sin60^o = {tex}\frac {AM}{OA}{/tex}
{tex}\Rightarrow{/tex} {tex}\frac{\sqrt3}2{/tex}= {tex}\frac {AM}{12}{/tex}
{tex}\Rightarrow{/tex} AM = 6{tex}\sqrt3{/tex} cm
{tex}\Rightarrow{/tex} 2AM = 12{tex}\sqrt3{/tex} cm
{tex}\Rightarrow{/tex} AB =12{tex}\sqrt3{/tex} cm
{tex}\therefore{/tex} Area of {tex}\triangle{/tex}AOB ={tex}\frac 12{/tex} {tex}\times{/tex} AB {tex}\times{/tex} OM
= {tex}\frac 12{/tex} {tex}\times{/tex} 12{tex}\sqrt3{/tex} {tex}\times{/tex} 6 = 36{tex}\sqrt3{/tex} cm²
= 36 {tex}\times{/tex} 1.73 cm² = 62.28 cm²
So, Area of the corresponding segment of the circle = Area of the correspoding sector of circle - Area of {tex}\triangle{/tex}AOB
= 150.72 - 62.28 = 88.44 cm²

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Find the maximum value of the polynomial-> -x²+x+2

Posted by Sameer Var 4 years ago

CBSE > Class 10 > Mathematics

1 answers

Somansh Sarvesh 4 years ago

Infinite

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A statue, 1.6m tall, stands on the top of a pedestal. From a point on the ground, the angles of elevation of the top of the statue is 60 and from the same point the angle of elevation of the top of the pedestal is 45. Find the height of the pedestal.

Posted by Taniya Dandriyal 4 years ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

202-302

Posted by Ziya Saifi 4 years ago

CBSE > Class 10 > Mathematics

4 answers

Shree Singh 4 years ago

-100??

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Sania? Parveen? 4 years ago

202 -302 _____ -100 _____

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Anmol Preet 4 years ago

- 100

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Sanket ... 4 years ago

-100 ?

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Two hotels are at the ground level on either side of a mountain. On moving a certain distance towards the top of the mountain two huts are situated as shown in the figure. The ratio between the distance from hotel B to hut-2 to that of hut-2 to mountain top is 3:7. (1)The distance between the hotel A and hut-1 is a. 2.5 miles b. 4.29 miles c. 29 miles d. 1.5 miles

Posted by Mansi Jangra 4 years ago

CBSE > Class 10 > Mathematics

0 answers

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HCF of 306 and 1314

Posted by Saloni 10A 4 years ago

CBSE > Class 10 > Mathematics

3 answers

Saubhagya Sharma 4 years ago

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Pawandeep Kaur 4 years ago

1Thank You

Aadarsh Shrivastav 4 years ago

18 is your answer

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Probability of an event can not be

Posted by Minakshi Dhillon 4 years ago

CBSE > Class 10 > Mathematics

5 answers

Anshpreet Kaur 4 years ago

Less than 0 and cannot be more than 1

1Thank You

Anmol Preet 4 years ago

Less than 0

1Thank You

Swara Mishra 4 years ago

Probability of an event cannot be less than 0 and more than 1.

2Thank You

Aadarsh Shrivastav 4 years ago

Less than 0

2Thank You

Aditya Gupta 4 years ago

in negative

4Thank You

ANSWER

Aftab tells his daughter. "Seven years ago, I was seven times as old as you were then, Also, three years from now. I shall be three times as old as you will be (Isn't this interesting?) Represent this situation algebraically and graphically

Posted by Lokesh Lokesh 4 years ago

CBSE > Class 10 > Mathematics

1 answers

Lokesh Lokesh 4 years ago

Answer: Let the present age of Aftab bex And, present age of his daughter-y Seven years ago, Age of Aftab=X-7 Age of his daughter-y-7 According to the question, (x-7)=7(y-7) x-7=7y-49 x-7y=-42 (1) Three years hence. Age of Aftab = x+3 Age of his daughter-y+3 According to the question, (x+3)=3(y+3) x+3 =3y+9 x-3y=6 (2) Therefore, the algebraic representation is x-7y=-42 x-3y=6 For *-7y=-42 x=-42+7y

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Tan A=4/3 and a is acute then sin a is

Posted by Akash Buttar 4 years ago

CBSE > Class 10 > Mathematics

2 answers

Aadarsh Shrivastav 4 years ago

Sin a is equal to 4/5

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Durga Sharan Jha 4 years ago

Tan A=4/3 and a is acute then sin a is tanA=4/3=p/b. Here,p=4 and b=3 By Pythagoras theorm, h^2 =p^2 + b^2 . =4^2 + 3^2 =16 + 9 = 25 h= 5 ( 5^2 = 25 ) now sin A = p/h sin A = 4/5

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2 f(x)=6x. -3-7x

Posted by Sai Ram 4 years ago

CBSE > Class 10 > Mathematics

1 answers

Vyash S 4 years ago

X=0

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Find the value of k for which the system of linear equations x + ky = 0, 2x - y = 0 has unique solution.

Posted by Dilveer Brar 4 years ago

CBSE > Class 10 > Mathematics

2 answers

Swara Mishra 4 years ago

Should not be equal to 0.5

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Dhairya Sharma? 4 years ago

0Thank You

ANSWER

Chapter 14 ex14. 1 qu 5

Posted by Nitin Rao 4 years ago

CBSE > Class 10 > Mathematics

0 answers

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What will be the height of an equilateral triangle having each side 6 CM

Posted by Rashmika Singh ?? 4 years ago

CBSE > Class 10 > Mathematics

3 answers

Mahira Srivastava 4 years ago

3root3

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Karan Deep 4 years ago

Duck ?

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Shreyans Jain 4 years ago

In a equilateral triangle all sides are equal We construct a median which is a perpendicular only in equilateral triangle And by Pythagoras theorem We get √18 OR 3√2

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ANSWER

The shadow of a 5 metre long pole is 2 m long at the same time delay in the shadow of a 12.5 metre high building (in m) is

Posted by Rashmika Singh ?? 4 years ago

CBSE > Class 10 > Mathematics

2 answers

Sia ? 4 years ago

5.0

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Jaya Kanwar 4 years ago

1.25

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The degree of the polynomial t⁸-3t⁷+2t⁵-6t²/t²

Posted by Satyam Sharma 4 years ago

CBSE > Class 10 > Mathematics

4 answers

Anshpreet Kaur 4 years ago

0Thank You

Dhairya Sharma? 4 years ago

8??‍♂️

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Supriya Ronanki 4 years ago

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Darakhshan Shaikh 4 years ago

The degree of the polynomial is 8

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The diagram shows a sketch of the curve y= 36-x`2 . The curve crisses the axes at H, K, L. O is the origin. 1. The area of the triangle OHK is-- 2.the area of the rectangle pqrs is given by-- 3. the non zero value of x for which a equal to zero is --- 4. the length of line segment HK is -- 5. the value of A at X equal to 3 is--

Posted by Jubilee Dutta 4 years ago

CBSE > Class 10 > Mathematics

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For what value of k, -2 is a zero of the polynomial 3xsquare+4x+2k?

Posted by Ikra Rangoonwala 4 years ago

CBSE > Class 10 > Mathematics

2 answers

Swara Mishra 4 years ago

Answer is -2

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S. Netra 4 years ago

-2

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From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are 45 and 60 respectively. Find the height of the tower

Posted by Taniya Dandriyal 4 years ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years ago

Let the height of the building is BC, the height of the transmission tower which is fixed at the top of the building be AB.

D is the point on the ground from where the angles of elevation of the bottom B and the top A of the transmission tower AB are 45° and 60° respectively.

The distance of the point of observation D from the base of the building C is CD.

Combined height of the building and tower = AC = AB + BC

Trigonometric ratio involving sides AC, BC, CD, and ∠D (45° and 60°) is tan θ.

In ΔBCD,

tan 45° = BC/CD

1 = 20/CD

CD = 20

In ΔACD,

tan 60° = AC/CD

√3 = AC/20

AC = 20√3

Height of the tower, AB = AC - BC

AB = 20√3 - 20 m

= 20 (√3 - 1) m

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ANSWER

What is the ratio of smallest 2 digit prime no and smallest composite no

Posted by Shreya Singh 4 years ago

CBSE > Class 10 > Mathematics

3 answers

Someshwar . M 4 years ago

11is the the smallest 2digit prime no and 4 is smallest composite no so ratio is 11:4

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Dhairya Sharma? 4 years ago

Smallest Two digit Prime Number - 11 and smallest Composite Number - 4 Ratio = 11/4 = 11:4

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Bhupendra Singh 4 years ago

11is the the smallest 2digit prime no and 4 is smallest composite no so ratio is 11:4

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ANSWER

If a=2^3×3,b=2×3×5,c=3^n×5 and LCM (a,b,c)=2^3×3^2×5,than n=?

Posted by Anuj Kumar 4 years ago

CBSE > Class 10 > Mathematics

4 answers

Bhupendra Singh 4 years ago

3 as it's the highest power

2Thank You

Ansuiya Rathi 4 years ago

2Thank You

Nipun Aggarwal 4 years ago

3Thank You

Akshay Ahlawat 4 years ago

2Thank You

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Chennai sahodaya common pre board paper

Posted by Bhuvanraj Rajesh 4 years ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Chapter 12, exercise=12.3, Question7

Posted by Harshit Darji 4 years ago

CBSE > Class 10 > Mathematics

3 answers

Jaya Kanwar 4 years ago

Area of square - Area of circle

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Dayanand Prajapati 4 years ago

42cm²

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Abdullah Sarim 4 years ago

Area of square-area of 4sector

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A man is known to speak truth 3 out of 4 times.He throws a die and number other that six comes up. Find the probability that he reports it is six

Posted by Kaleshwari .P 4 years ago

CBSE > Class 10 > Mathematics

1 answers

Bhavya Kushwah 4 years ago

1/4

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ANSWER

Sec^4A - Sec^2 A is equal to ?

Posted by Vaibhav Sahu 4 years ago

CBSE > Class 10 > Mathematics

2 answers

Priya . 4 years ago

Since all the options involve the trigonometric ratio tan θ, so we use the identity 1 + tan2θ = sec2θ. To find: sec4A – sec2A Consider sec4A – sec2A = (sec2A)2 – sec2A Now, as sec2A = 1 + tan2A ⇒ sec4A – sec2A = (sec2A)2 – sec2A = (1 + tan2A)2 – (1 + tan2A) = 1 + tan4A + 2 tan2A – 1 – tan2A = tan4A + tan2A

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Devduti Verma 4 years ago

Sec^4A-sec^2A = tan^4A+tan^2

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ANSWER

In the equation ax2+bx+c, if curve passes through (0,0), (-3,-4), (3,-4) then the value of a, b and c is a = 0, b =, c = 0 a = 0, b = 0, c = a =, b = 0, c = 0 a = , b = 0, c =

Posted by Parushi Agarwal 2 years, 5 months ago

CBSE > Class 10 > Mathematics

0 answers

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A box contain cards numbered 6 to 50 . A card is drawn at random from the box the probability that the drawn card has a number which is a perfect square like 4,9 is ?

Posted by Komal Kabdal 4 years ago

CBSE > Class 10 > Mathematics

2 answers

Vishal Prajapat 4 years ago

1/9

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Md Aftab Alam 4 years ago

Possible outcome = 50 - 5 =45 Favourably outcome = 9 ,16,25, 36 ,49 P( getting a perfect square ) = PO/ FO = 5 /45 = 1 / 9

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ANSWER

Thedecimalexpansionoftherationalnumber14587/250willterminate after:

Posted by Mary Muannunsang 4 years ago

CBSE > Class 10 > Mathematics

1 answers

Abhi Shek 4 years ago

IT WILL TERMINATE AFTER 3 DECIMAL PLACES.IF U WRITE THE DENOMINATOR IN THE product of the primes 2 and 5 then it would become , 250 = 2*5*5*5,which is equal to 2*5^3,so it would terminate after 3 decimal places.

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