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Posted by Rajeev Samantaray 7 years, 7 months ago
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Posted by Aman Tiwari 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
Prime factorisation of 404 and 96 is:
404 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 101
404 = 22 {tex}\times{/tex} 101
96 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 {tex}\times{/tex} 3
96 = 25 {tex}\times{/tex} 3
{tex}\therefore{/tex} HCF(404,96 )= 22 = 4
LCM(404, 96 ) = 101 {tex}\times{/tex} 25 {tex}\times{/tex} 3
LCM( 404, 96) = 9696
now we have to verify that,
HCF(404, 96) {tex}\times{/tex}LCM(404, 96) = 404{tex}\times{/tex}96
Hence,
LHS = HCF {tex}\times{/tex} LCM
= 4 {tex}\times{/tex} 9696
= 38784
RHS= Product of numbers
=404 {tex}\times{/tex} 96 = 38784
Since, LHS=RHS
i.e. HCF {tex}\times{/tex} LCM = Product of 404 and 96.
hence verified
Posted by Yash Kumar 7 years, 7 months ago
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Sia ? 6 years, 6 months ago
The given system of equations may be written as
x + y = a - b
So, x + y -(a - b)=0 ......... (i)
and ax - by = a2 + b2
So, ax - by -(a2 + b2)=0 ........ (ii)
By cross-multiplication, using (i) and (ii) , we have
{tex}\frac { x } { - \left( a ^ { 2 } + b ^ { 2 } \right) - b ( a - b ) } = \frac { y } { - a ( a - b ) + \left( a ^ { 2 } + b ^ { 2 } \right) } = \frac { 1 } { - b - a }{/tex}
{tex}\Rightarrow \quad \frac { x } { - a ^ { 2 } - a b } = \frac { y } { a b + b ^ { 2 } } = \frac { 1 } { - b - a }{/tex}
{tex}\Rightarrow \quad \frac { x } { - a ( a + b ) } = \frac { y } { b ( a + b ) } = \frac { 1 } { - ( a + b ) }{/tex}
{tex}\Rightarrow \quad x = \frac { - a ( a + b ) } { - ( a + b ) } = a \text { and } y = \frac { b ( a + b ) } { - ( a + b ) } = - b{/tex}
Hence, x = a, y = -b is the solution of the given system of equations.
Posted by Pratistha Saxena 7 years, 7 months ago
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Sia ? 6 years, 6 months ago
Get NCERT solutions here: <a href="https://mycbseguide.com/ncert-solutions.html">https://mycbseguide.com/ncert-solutions.html</a>
Posted by Harshal Bansal 7 years, 7 months ago
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Posted by Het Shah 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Let the speed of the stream be x km/hr.
Speed of boat upstream = (5 - x) km/hr.
Speed of boat downstream = (5 + x) km/hr.
Time taken to go upstream = {tex} \frac { 5.25 } { 5 - x }{/tex} hours.
Time taken to go downstream = {tex} \frac { 5.25 } { 5 + x }{/tex} hours.
According to question,
{tex} \therefore \quad \frac { 5.25 } { 5 - x } - \frac { 5.25 } { 5 + x } = 1{/tex}
{tex} \Rightarrow \quad 5.25 [ \frac { 1 } { 5 - x } - \frac { 1 } { 5 + x } ] = 1{/tex}
{tex} \Rightarrow \quad \frac { 21 } { 4 } [ \frac { 5 + x - 5 + x } { ( 5 - x ) ( 5 + x ) } ] = 1{/tex}
{tex} \Rightarrow \quad \frac { 21 } { 4 } \times \frac { 2 x } { 25 - x ^ { 2 } } = 1{/tex}
{tex} \Rightarrow \quad 21 x = 50 - 2 x ^ { 2 }{/tex}
{tex} \Rightarrow{/tex} 2x2 + 21x - 50 = 0
{tex}\Rightarrow{/tex} 2x2 + 25x - 4x - 50 = 0
{tex} \Rightarrow \quad x ( 2 x + 25 ) - 2 ( 2 x + 25 ) = 0{/tex}
{tex} \Rightarrow{/tex} (2x + 25) (x - 2) = 0
{tex} \Rightarrow{/tex} x - 2 = 0, 2x + 25 = 0
{tex} \Rightarrow{/tex} x = 2 {tex} \left[ \because x \neq - \frac { 25 } { 2 } \text { as } x > 0 \right]{/tex}
Hence, the speed of the stream is 2 km/hr.
Posted by Deepak Meena 7 years, 7 months ago
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Sia ? 6 years, 6 months ago
Get NCERT solutions here : https://mycbseguide.com/ncert-solutions.html
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Sia ? 6 years, 6 months ago
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