CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

According to the question,we are given that,
{tex}P Q \| B C{/tex}
Therefore, by thales theorem,
We have,
{tex}\frac { A P } { P B } = \frac { A Q } { Q C }{/tex}
{tex}\frac { 2.4 } { P B } = \frac { 2 } { 3 }{/tex}
{tex}\Rightarrow P B = \frac { 3 \times 2.4 } { 2 }{/tex}
{tex}= \frac { 3 \times 24 } { 20 }{/tex}
{tex}= \frac { 3 \times 6 } { 5 }{/tex}
{tex}= \frac { 18 } { 5 }{/tex}
{tex}\Rightarrow{/tex} PB = 3.6 cm
Now, AB = AP + PB
= 2.4 + 3.6
= 6 cm
In {tex}\triangle {/tex}APQ and {tex}\triangle{/tex}ABC
{tex}\angle A = \angle A{/tex} [Common]
{tex}\angle A P Q = \angle A B C{/tex} [{tex}\because{/tex} PQ || BC {tex}\Rightarrow{/tex} Corresponding angles are equal]
{tex}\Rightarrow \triangle A P Q \sim \triangle A B C{/tex} [By AA criteria]
{tex}\Rightarrow \frac { A B } { A P } = \frac { B C } { P Q }{/tex} [Corresponding sides of similar triangles are proportional]
{tex}\Rightarrow \frac { 6 } { 2.4 } = \frac { 6 } { P Q }{/tex}
{tex}\Rightarrow P Q = \frac { 6 \times 2.4 } { 6 }{/tex}
{tex}\Rightarrow{/tex} PQ = 2.4 cm
Hence, AB = 6 cm and PQ = 2.4 cm

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If the polynomial (6x)4+(8x)3+(17x)2+

Posted by Tarun Yadav 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

On long division of 6x⁴ + 8x³ + 17x² + 21x + 7 by 3x² + 4x + 1 we get

Quotient = 2x² + 5, remainder = x + 2

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x square - 8x +27= 0

Posted by Kunal Zinjade 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

1/x-3 -1/x-5 =1/6 where x is not equal to 3,-5

Posted by Kunal Zinjade 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Father of maths

Posted by Senthil Balusamy 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Fizza Hussain 7 years, 7 months ago

Euclid... (BABA)?????

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Uttkarsh Mishra 7 years, 7 months ago

Hi shayad

1Thank You

Uttkarsh Mishra 7 years, 7 months ago

S bhatacharya

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if one zero of polynomial (a^2 +9)x^2 +13x +6a is reciprocal of the other ,fimd the value of a

Posted by Shriya ?? 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Unnati Pragya 7 years, 7 months ago

Other zero=1/a product of zero= 1/a*a=1 But product of zero= 6a/a^2+9 1=6a/a^2+9 a^2+9=6a a^2-6a+9=0 a^2 - 3a-3a+9=0 a(a-3)-3(a-3) = 0 (a-3) ( a-3)=0 Hence,a=3

1Thank You

Adarsh Sharma 7 years, 7 months ago

a is 3

1Thank You

Aaditya Kumar 7 years, 7 months ago

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A BOAT GOES 12KM UPSTREAM AND 40KM DOWNSTREAM IN 8HRS .IT CAN GO 16KM UPSTERAM AND 32KM DOWNSTREAM IN THE SAME TIME FIND THE SPEED OF THE BOAT IN STILL WATER AND THE SPEDD OF THE STREAM

Posted by Ayush Raj 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let the speed of the boat in still water be x km/hr and speed of the stream be y km/hr.
Then,
Speed of the boat while going upstream = (x - y)km/hr
Speed of the boat while going downstream = (x + y) km/hr

Also we know that, time taken to cover ' d ' Km with speed ' s ' Km/hr is {tex} \frac ds{/tex}

Hence,Time taken by the boat to cover 12 km upstream = {tex}\frac{12}{x-y}{/tex}hrs
And,Time taken by the boat to cover 40 km downstream = {tex}\frac{40}{x+y}{/tex}hrs
According to the question, Total time taken = 8 hrs
{tex}\therefore \frac { 12 } { x - y } + \frac { 40 } { x + y } = 8{/tex}.........(1)
Again, time taken by the boat to cover 16 km upstream = {tex}\frac{16}{x-y}{/tex}
And,Time taken by the boat to cover 32 km downstream = {tex}\frac{32}{x+y}{/tex}
According to the question,Total time taken = 8 hrs
{tex}\therefore\frac { 16 } { ( x - y ) } + \frac { 32 } { ( x + y ) } = 8{/tex}.........(2)
Putting {tex}\frac { 1 } { ( x - y ) } = u{/tex} and {tex}\frac { 1 } {( x + y ) } = v{/tex} in equation (1) & equation (2), so that we may get linear equations in the variables u & v as following :-
12u + 40v = 8
{tex}\Rightarrow{/tex} 3u + 10v = 2........(3)
and
16u + 32v = 8
{tex}\Rightarrow{/tex}2u + 4v = 1.........(4)
Multiplying equation (3) by 4 and equation (4) by 10, we get ;
12u + 40v = 8..........(5)
20u + 40v = 10........(6)
Subtracting equation (5) from equation (6), we get
{tex}8u = 2 \Rightarrow u = \frac { 1 } { 4 }{/tex}
Putting u = {tex}\frac 14{/tex} in equation (3), we get
{tex}3 \times \frac { 1 } { 4 } + 10 v = 2 \Rightarrow 10 v = \frac { 5 } { 4 } \Rightarrow v = \frac { 1 } { 8 }{/tex}
{tex}u = \frac { 1 } { 4 } \Rightarrow \frac { 1 } { x - y } = \frac { 1 } { 4 } \Rightarrow x - y = 4{/tex}.....(7)
{tex}v = \frac { 1 } { 8 } \Rightarrow \frac { 1 } { x + y } = \frac { 1 } { 8 } \Rightarrow x + y = 8{/tex}......(8)
On adding (7) and (8), we get
2x = 12
{tex}\Rightarrow{/tex}x = 6
Putting x = 6 in (8), we get
6 + y = 8
{tex}\Rightarrow{/tex}y = 8 - 6 = 2
{tex}\therefore{/tex} x = 6, y = 2
Hence, the speed of the boat in still water = 6 km/hr and speed of the stream = 2 km/hr

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if a is a square matrix of order 3 such that adj a=64 find (a)

Posted by Arjun Arjun 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We know that, for a square matrix of order n,
|adj (A) |= |A|^n-1
Here, the order of A is 3{tex}\times {/tex}3 ,therefore n = 3
Now, |adj (A) | =|A|{tex}^{3-1}{/tex} = |A|²
Given, |adj (A)|= 64,

Therefore,64 =|A|²
{tex}\Rightarrow{/tex} (8)² =|A|²
{tex}\Rightarrow{/tex} |A|= ± 8 [taking square root]

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definition of trigonometry

Posted by Mohd Hussain 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Himesh Baraik 7 years, 7 months ago

Trigonometry is a branch of mathematics that deals with angles allied problems.

1Thank You

ANSWER

Find zeros of polynomial xsquare -1

Posted by Jagseer Singh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Aayush Gautam 7 years, 7 months ago

Use identitity xsquare-y square then by applying identity apply midle term spiliting

0Thank You

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Sir class 10th in percentage or cgpa

Posted by Rakshitha Rakshitha 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Tarun Anand 7 years, 7 months ago

Percentage

1Thank You

Abhinav Sharma 7 years, 7 months ago

It is a score based on your performance compared to your batchmates. This is how CGPA is generally calculated in my institute. So, overall students are graded based on this scale which is relative to other student's performances. Whereas, percentage is absolute based on your own performance.

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Sin 30/cos45 + cot 45/sec 60 - sin 60/ tan 45 + coa 30/sin 90

Posted by Aakriti Sah 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Sakshi Naphade 7 years, 7 months ago

1+√2÷4

1Thank You

Sakshi Naphade 7 years, 7 months ago

Ans: 1+√2 ---------- 4

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ANSWER

Class 9th 10th all fourmula

Posted by Vivek Kumar 5 years, 8 months ago

CBSE > Class 10 > Mathematics

2 answers

Vivek Kumar 7 years, 7 months ago

0Thank You

Tarun Anand 7 years, 7 months ago

Search it on google it is nit possible to write all formula here.??

2Thank You

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Factorise:x2 +2x+180

Posted by Archana Rani 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Common Debbarma 7 years, 7 months ago

Simplyfying X+2x+2x=180 Combine like terms x+2x=3x 3x+2x=180 Combine like term 3x+2x =5x 5x=180 Solving for veriable 'x' Move all term containing x to the left ,all other term to the right. Divide each side by '5' Simplyfying X=36

3Thank You

Navin Raj 7 years, 7 months ago

2x+20x+18x+180 2x (x+10)+18(x+10) (X+10)(2x+18)

1Thank You

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What is ment by consistent

Posted by K J 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Silviya Malik 7 years, 7 months ago

Acting or done in the same way over time.

1Thank You

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Find the roots of quadratic equations by the method of completing the square: 4x²+4√3x+3

Posted by Pallavi Jha 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

We have, {tex}4x^2 + 4 \sqrt3 x + 3 = 0{/tex}

{tex}\implies (2x)^2 + 2 (2x) (\sqrt3) + (\sqrt3)^2 = 0{/tex}

{tex}\implies (2x + \sqrt3)^2 = 0{/tex}

{tex}\implies 2x + \sqrt3 = 0,\, 2x + \sqrt3 = 0{/tex}

{tex}\implies x = -{\sqrt3 \over 2},\, -{\sqrt3 \over2}{/tex}

{tex}\therefore x = -{\sqrt3 \over 2},\, -{\sqrt3 \over2}{/tex} are the required roots.

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Lcm of 2/5 ,3/10/6/25

Posted by Lalit Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Mansi - 7 years, 7 months ago

I don' t know that answer is write but i tell 2/5 , 3/10,6/25 Take lcm of 5 ,10,15 Then we have lcm 50 20+15+12/50 means 20/50 ,15/50,12/50 So,the denominator is same then take lcm of 20,15,12 We have lcm is 60, then write 60/50 or 6/5

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What is meant by lemma

Posted by Kaushal Joshi 7 years, 7 months ago

CBSE > Class 10 > Mathematics

6 answers

Unnati Pragya 7 years, 7 months ago

Alima is a proven statement used for proving another statement

0Thank You

Sattwik Chetan 7 years, 7 months ago

Any statement which can not be proved

0Thank You

@Jay Bunkar 7 years, 7 months ago

It is theromof maths . Find hcf

3Thank You

Mansi - 7 years, 7 months ago

Yes write answer good job

4Thank You

Chetan Sharma 7 years, 7 months ago

Use find hcf

2Thank You

Chetan Sharma 7 years, 7 months ago

Thorem of euclid divison lemma

2Thank You

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All formulas for class 10

Posted by Sanjana Sharma 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

What is logarithm

Posted by Siddhi Dube 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

The logarithm is the inverse function to exponentiation.

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prove the product of three cosecutive positive integers is divisible by 6

Posted by Shreya Prasad 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Rajveer Singh 7 years, 7 months ago

I34

3Thank You

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Prove under root 2 is irrational

Posted by Ritik Kumar Singh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Pallavi Jha 7 years, 7 months ago

Let us assume, to the contrary, that √2 is rational. So integers r and s ≠ 0 such that √2 =r/s. Suppose r and s have a common factor other than 1. Then we divide by the common factor to get √2=a/b, where a and b are coprime. So b√2=a. Squaring on both the sides and rearranging,2b²=a². Therefore,2 divides a². Now, by the theorem 1.3, 2 divides a. So, a=2c for some integer c. Substituting for a, we get 2b²=4c,i.e.,b²=2c². This means that 2 divides b² and so 2 divides b. Therefore,a and b have at least 2 as a common factor. But this contradicts the fact that a and b have no common factors other than 1. This contradiction has arisen because of our incorrect assumption that √2 is rational. So, we conclude that √2 is irrational.

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Mansi - 7 years, 7 months ago

I tell answer of this question tommoro because time is 9 :53

1Thank You

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Show that the polynomial f(x) = x^4+4x^2+6 has no zero

Posted by Unnati Pragya 6 years, 4 months ago

CBSE > Class 10 > Mathematics