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2X+3y=7, 3x-2y=7

Posted by Santosh Patel 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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(1+cot +tan)(sin -cos)=?

Posted by Jaspreet Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

(1 + cot A + tan A)(sin A - cos A)
= sin A - cos A + cot A sin A - cot A cos A + tan A sin A - tan A cos A
=sin A - cos A + {tex}\frac{cos A}{sin A}{/tex} {tex}\times{/tex} sin A - cot A cos A + tan A sin A - {tex}\frac{sin A}{cos A}{/tex} {tex}\times{/tex} cos A
=sin A - cos A + cos A - cot A cos A + tan A sin A - sin A
=sin A tan A - cot A cos A

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If a and n are two odd positive integers such that a>b,then prove that one of the two numbera a+b÷2 and a-b÷2 is odd and the other is even

Posted by Fahad Naseem 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

If a and b are odd numbers then it should be in 2q+1 or 2q+3 form where q is a positive integer.

Let a = 2q + 3 , b = 2q + 1 and a > b
Now, {tex}\frac{a + b } {2} = \frac{ 2q + 3 + 2q + 1}{2}{/tex}
{tex}= \frac { 4 q + 4 } { 2 }{/tex}
= 2q + 2
{tex}\frac{a+b}{2}{/tex}=2(q+1) = an even number..........(1)
Now

{tex}\frac { a - b } { 2 } = \frac { ( 2 q + 3 ) - ( 2 q + 1 ) } { 2 }{/tex}
{tex}= \frac { 2 q + 3 - 2 q - 1 } { 2 }{/tex}
{tex}\frac{a-b}{2}= \frac { 2 } { 2 }{/tex} = 1 = an odd number..........(2)
Hence From (1) and (2) {tex}\frac{a+b}{2}{/tex} and {tex}\frac{a-b}{2}{/tex} are even and odd numbers respectively

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Give 10 extra sums of mean and mode of class 10

Posted by Deesha 3 ...... 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Evaluate: sec50° sin40° + cos40° cosec50°

Posted by Kanak Patidar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Root 5

Posted by Manan Khan 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Deeksha Kalyan 7 years, 7 months ago

2.23

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Kanak Patidar 7 years, 7 months ago

2.236?

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Find the HCF of 408 and 1032 is expressible in the form 65x+117y

Posted by Gurkaran Randhawa 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Tan 20/cosec 70+

Posted by Pranjal Trivedi 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Pawan Kumar 7 years, 7 months ago

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A circular field has a circumference of 360 km to cyclist Kapil and Ramu started together and can cycle at speeds of 12 km per hour and 15 km per hour respectively around the circular field after how many hours will they meet again at starting point

Posted by Hemant Rana 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Find the smallest number which when divides 28 &32leaves a remainder 8

Posted by Tushar Saini 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Sattwik Chetan 7 years, 7 months ago

(28-8) & (32-8) and HCF of both number

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Avisha Chandak 7 years, 7 months ago

subtract 28 and 32 by 8 and then take out the HCF u will get your answer

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Sin=

Posted by Ankit Kashyap 7 years, 7 months ago

CBSE > Class 10 > Mathematics

6 answers

Prince Panday 7 years, 7 months ago

Perpendicular /hypotenuse

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Kanak Patidar 7 years, 7 months ago

Sin=p/h or sin= 1/cosec

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Unnati Pragya 7 years, 7 months ago

p/h

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Pawan Kumar 7 years, 7 months ago

???? Sintheta=p/h

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Himesh Baraik 7 years, 7 months ago

P/h

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Himesh Baraik 7 years, 7 months ago

1/cosec

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A pole has to be erected at a point on the boundry Of a circular park of diameter 13 m in such a way that the difference of its distances from two diametrically opposite fixed gates A and B on the boundary is 7 m. At what distances from the two gates should the pole be erected?

Posted by Prince Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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If n is an odd integer , then show that n² - 1 is an odd integer

Posted by Mansi - 7 years, 7 months ago

CBSE > Class 10 > Mathematics

6 answers

Mansi - 7 years, 7 months ago

No , i can't write wrong question but i can check this question from my friends

1Thank You

Unnati Pragya 7 years, 7 months ago

I think u write wrong questions please check it

0Thank You

Mansi - 7 years, 7 months ago

What i do

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Mansi - 7 years, 7 months ago

This question is in my holiday homework

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..... ...... 7 years, 7 months ago

Please check your question Mansi, it seems wrong.??

1Thank You

Ashutosh Kesarwani 7 years, 7 months ago

Yes

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Solution of RS agrawal class 10

Posted by Hardik Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Koi toh Bata do result lab aayega class 10 ka

Posted by Diksha Gyamnani 7 years, 7 months ago

CBSE > Class 10 > Mathematics

5 answers

Diksha Gyamnani 7 years, 7 months ago

Ohhh thanks purnima and pawan

0Thank You

Pawan Kumar 7 years, 7 months ago

Perhaps Last week of may and first week of june

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Purnima Garg 7 years, 7 months ago

Yes, conform date hain .Actually maine google par CBSE 10th class result search kiya to vahan par likha tha ki 30 may result date hain

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Diksha Gyamnani 7 years, 7 months ago

Confirm date h or apko kaha se pata chala

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Purnima Garg 7 years, 7 months ago

30 may ko

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Show that any positive integer is of the form 2q and every positive odd integer is of the form 2q+1where q is some integet.

Posted by Anushka Jaiswal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Himesh Baraik 7 years, 7 months ago

Google Baba kyon hai

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Mansi - 7 years, 7 months ago

I know answer of this question

2Thank You

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Ring middle term split

Posted by Dishant Rawal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Kanak Patidar 7 years, 7 months ago

I think ur Q is wrong

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√3sin x = cos x(find the value of)

Posted by Kanak Patidar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

..... ...... 7 years, 7 months ago

√3 Sin x= cos x Or Tan x = 1/√3 Or, Tan x = Tan 30° Therefor x = 30°.☺☺?

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Examine whether (240)n can end with the digit 5 for any n€N

Posted by Adarsh Mishra 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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If alpha and beta are zeroes of polynomial p(x)=x2+px+2 so find the value of p

Posted by Jahir Sheikh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Using Euclid division algorithm to find HCF 1190 and 1445 express the HCF. In the form 1190m and 1445m

Posted by Akash Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Kon chapter

Posted by Rahul Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Write 98 as product of its prime numbers

Posted by Allys S 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Deepanjali Gautam 7 years, 7 months ago

2×7^2

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A man is employed to count Rs.10710.He counts at the rate Of Rs.180 per minute for half an hour .After this he counts at the rate of Rs.3 less every minute than the preceding minute. Find the time taken by him to count the entire amount.

Posted by Himanshi Jain 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Show that one and only one out of n ,n+4,n+8,n+12,n+16 is divisible by 5 where n is any positive integers

Posted by Charmi Patrl 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Bavneet Kaur Saini 7 years, 7 months ago

Then you will get only one and only out of n n+4 n+8 n+12 n+16 divisible by 5

2Thank You

Bavneet Kaur Saini 7 years, 7 months ago

R =0,1,2,3,4,5 by Euclid division lemma a=bq +r a=n put values of a bc in equation a=bq+r start squaring both sides

3Thank You

Bavneet Kaur Saini 7 years, 7 months ago

Let b =5

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Given the HCF (150,100)=50. FindLCM

Posted by Sohel Shek 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Rhythm Dhingra 7 years, 7 months ago

a×b=LCM × HCF 150×100=LCM × 50 LCM=15000÷50 LCM=300

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X |2_y|9=6 X|7+y|3=5

Posted by Kailash Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Expree150 as a product of its primes

Posted by Sohel Shek 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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If α and β are the zeros of the quadratic polynomial f(x)=2x^2-5x+7. Find a polynomial whose zeros are 2α+3β and 3α+2β.

Posted by Mayank Parauha 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Misha Jain 7 years, 7 months ago

Alpha + beta = 5/2 Alpha× beta = 7/2 For new polynomial we have zeroes 2alpha + 3 beta and 3alpha+2beta S= sum of zeroes = 2alpha+3beta+3alpha+2beta = 5alpha + 5beta = 5 ( alpha + beta ) = 5 (5/2) = 25/2 P = product of zeroes = (2alpha+3beta)(3alpha+2beta) = 6alpha ^2 + 4 alpha× beta +9 alpha × beta +6 beta^2 = 6 (alpha^2+beta^2) + 13 alpha × beta = 6 (( alpha +beta)^2 -2 alpha×beta ) +13 alpha × beta = 6 ( alpha+ beta )^2 -12 alpha×beta+13alpha×beta =6 ( alpha+ beta )^2 + alpha ×beta = 6(5/2)^2 +7/2 =6 (25/4) +7/2 = 75/2 +7/2 =82/2=41 Required quadtratic polynomial us given by x^2-sx+px = x^2 -(25/2)x +41 =2x^2+25x+82

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If alpha and betta are two zeros of polynomial =4x^2-5x-1,find the value of alpha square betta plus alpha betta square

Posted by Aisha Biswas 7 years, 7 months ago

CBSE > Class 10 > Mathematics