CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let take a polynomial ax² + bx + c Then ,we have sum of zeroes -3 as we know that sum of zeroes = -coefficient of x / coefficient of x²= -b/a= -3/1 And product of zeroes = 2 = coefficient of constant / coefficient of x²= c/a= 2/1 Then we have ,a=1,b=-3,c=2 We have polynomial= 1x² - 3x + 2

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Vansh Bhardwaj 7 years, 7 months ago

Ytrrr

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Unnati Pragya 7 years, 7 months ago

x^2+3x+2

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How we can represent 2-root 3 on the no.line?

Posted by Chandan Pandey 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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Inan A.P. 19th term is 52 and 38th term is 128 find sumof first 56 term

Posted by Abhi Jawarkar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Charu Sharma 7 years, 7 months ago

Answer is 5040,abhi

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Abhi Jawarkar 5 years, 8 months ago

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Abhi Jawarkar 7 years, 7 months ago

Ans

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What is pass maske

Posted by Goutam Patidar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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5÷x+y-2÷x-y =-1 by elimination method

Posted by Yashika Mittal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Mehul Vaidya 7 years, 7 months ago

Let p=1/x and q=1/y. Substitute 1/x and 1/y with p and q then continue normally

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What is calculus

Posted by Abhitesh Kumar Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Calculus is the mathematical study of continuous change, in the same way that geometry is the study of shape and algebra is the study of generalizations of arithmetic operations.

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In quadratic expression

Posted by Lucky Lucky 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Tanvi Jindal 7 years, 7 months ago

What is question?

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H. C. F. of x and 48 is 3 and their L. C. M. Is 240. Find the value of x

Posted by Anureet Kaur Saroaye 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Md Soyeb 7 years, 7 months ago

LCM × HCF=PRODUCT OF TWO NUMBERS 240×3=48×X 720/48=X X=15

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Jatin Tomar 7 years, 7 months ago

lcm x hcf = product of two numbers 240*3=48*x 240*3÷48=x 720÷48=x x=10

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Prajwal Dhiman 7 years, 7 months ago

15????

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Find cos75 by using the formula cos(A+B)=cosAcosB-SinAsinB

Posted by Rahul Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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X+1-2x

Posted by Vivekpratap Maurya 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Charu Sharma 7 years, 7 months ago

X=1

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Priyanshu Kumar 7 years, 7 months ago

X=1

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Prove 1+cosA/sinA = sinA/1-cosA

Posted by Dev Sapariya 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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Find L.C.M & H.C.F of 8/9 ;10/27 &16/81 .

Posted by Sushmita Majhi 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

{tex}\mathrm { HCF } \left( \frac { 8 } { 9 } , \frac { 10 } { 27 } , \frac { 16 } { 81 } \right){/tex} {tex}= \frac { \mathrm { HCF } \text { of the numerators } } { \mathrm { LCM } \text { of the denominators } }{/tex} {tex}= \frac { H C F ( 8,10,16 ) } { L C M ( 9,27,81 ) }{/tex}
and {tex}\operatorname { LCM } \left( \frac { 8 } { 9 } , \frac { 10 } { 27 } , \frac { 16 } { 81 } \right){/tex} {tex}= \frac { L C M \text { of the numerators } } { \text { HCF of the denominators } }{/tex} {tex}= \frac { L C M ( 8,10,16 ) } { H C F ( 9,27,81 ) }{/tex}
Consider,
8 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2 = 2³
10 = 2 {tex}\times{/tex}5
16 = 2 {tex}\times{/tex} 2 {tex}\times{/tex} 2{tex}\times{/tex} 2 = 2⁴
So, the HCF{tex} (8, 10, 16){/tex} = 2 and LCM {tex}(8, 10, 16){/tex} {tex}= 2 ^ { 4 } \times 5 = 80{/tex}
9 = 3 {tex}\times{/tex}3 = 3²
27 =3 {tex}\times{/tex} 3 {tex}\times{/tex} 3 = 3³
81 = 3 {tex}\times{/tex} 3 {tex}\times{/tex} 3 {tex}\times{/tex} 3 = 3⁴
So, the HCF (9, 27, 81) = 3² = 9 and LCM (9, 27, 81) = 3⁴ = 81
{tex}\Rightarrow \text { HCF } \left( \frac { 8 } { 9 } , \frac { 10 } { 27 } , \frac { 16 } { 81 } \right) = \frac { 2 } { 81 }{/tex} and {tex}\operatorname { LCM } \left( \frac { 8 } { 9 } , \frac { 10 } { 27 } , \frac { 16 } { 81 } \right) = \frac { 80 } { 9 }{/tex}

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Explain why 571 is a prime number

Posted by Anton Pasidu 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Anton Pasidu 7 years, 7 months ago

571 is a prime number because it have I and 571 as their factor

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a2+b2=

Posted by Sanat Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

3 answers

Tanvi Jindal 7 years, 7 months ago

a²+b²=(a+b)²=a²+b²+2ab

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Aadharshini Sudha 7 years, 7 months ago

(a+b)(a^2-ab+b^2) or (a+b)^2-2ab

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Sanjit Ragunathan 7 years, 7 months ago

a2+b2=c2.

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Show that one and only one out of N, N + 2 or n + 6 is divisible by 3 Where n is any positive integer

Posted by Sohail Shaikh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Sanjit Ragunathan 7 years, 7 months ago

Yes I agree with Gaurav .

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Gaurav Rawat 7 years, 7 months ago

Yes

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find a polynomial whose zeros are square of the zeroes of the polynomial 3xsqrare+6x-9

Posted by Shubh Sarraf 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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Prove root 2 i s irrational

Posted by Pratisha Kar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Suppose {tex}\sqrt2{/tex} is a rational number. That is , {tex}\sqrt2{/tex} = {tex}\frac{p}{q}{/tex} for some p{tex}\in{/tex}Z and q {tex}\in{/tex}Z. We can assume the fraction is in lowest fraction, That is p and q shares no common factors.

Then {tex}\sqrt2q=p{/tex}

Squaring both side we get,

{tex}2q^2=p^2{/tex}

So {tex}p^2{/tex} is a multiple of 2,

let's assume {tex}p=2m{/tex}

Then, {tex}2q^2=\left(2m\right)^2{/tex}

{tex}2q^2=4m^2{/tex}
Or {tex}q^2=2m^2{/tex}
So {tex}q^2{/tex} is a multiple of 2,
{tex}\therefore{/tex} q is multiple of 2
Thus p and q shares a common factor.This is contradiction.
{tex}\Rightarrow {/tex}{tex}\sqrt { 2 }{/tex} is an irrational number.

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{A+b}2

Posted by Nilesh Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics