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if cost of 5 1/4 kgof mangoes is rs 231.At what rate per kg being sold

Posted by Khushmeet Kaur 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Muky Thakur 7 years, 7 months ago

At 18.11

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2÷x-1 3÷y-1

Posted by Ramprakash Karishma 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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(x+y-8)÷2=(x+2y-14)÷2 (x+2y-14)÷8=(3x+y-12)÷11 Solve this equations in pair of linear equation in two variables

Posted by Anantha Lakshmi 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

The given equations are:
{tex}\frac { x + y - 8 } { 2 } = \frac { x + 2 y - 14 } { 3 } = \frac { 3 x + y - 12 } { 11 }{/tex}
Therefore, we have
{tex}\frac { x + y - 8 } { 2 } = \frac { 3 x + y - 12 } { 11 }{/tex}
By cross multiplication,we get
{tex}11x + 11y - 88 = 6x + 2y - 24{/tex}
{tex}11x - 6x + 11y -2y = -24 + 88{/tex}
{tex}5x + 9y = 64 {/tex}..........(i)

and {tex}\frac { x + 2 y - 14 } { 3 } = \frac { 3 x + y - 12 } { 11 }{/tex}
By cross multiplication,we get
{tex}11x + 22y -154 = 9x + 3y - 36{/tex}
{tex}11x - 9x + 22y -3y = -36 + 154{/tex}
{tex}2x + 19y = 118{/tex}.........(ii)

Multiplying (i) by 19 and (ii) by 9, we get
{tex}95x + 171y = 1216{/tex} .......(iii)
{tex}18x + 171y = 1062{/tex} .......(iv)
Subtracting (iv) from (iii),we get
{tex}77 x = 154 \Rightarrow x = 2{/tex}

Substituting x = 2 in (i),we get
{tex}5 \times 2 + 9 y = 64 \Rightarrow 9 y - 54{/tex}
{tex}\therefore{/tex} Solution is x = 2, y = 6

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Give the answer of exercise 14.1 1st sum in step derivation method of class 10?

Posted by Aanchal Sharma 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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Posted by Rachit Dwivedi 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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A triangle ABC B=90, A=45 find C.

Posted by Ankit Boss 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Yashika Upadhyay 7 years, 7 months ago

C=45°

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Ankit Boss 7 years, 7 months ago

C=45

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In figure point T is in the interior of rectangle PQRS prove that TS2 + TQ2 = TP2 + TR2

Posted by Anil Shrungare 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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x/a+y/b=2 ax-by=a2-b2

Posted by Xy Z 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

{tex}\frac { x } { a } + \frac { y } { b } = 2{/tex}
{tex}\frac { b x + a y } { a b } = 2{/tex}
{tex}bx + ay = 2ab{/tex}........(i)
{tex}ax - by = (a^2 - b^2){/tex}...(ii)
Multiplying (i) by b and (ii) by a
{tex}b^2x + bay = 2ab^2{/tex}.............(iii)
{tex}a^2x - bay = a(a^2 - b^2){/tex}........(iv)
Adding (iii) and (iv),we get
{tex}b^2x + a^2x = 2ab^2 + a^3 - ab^2{/tex}
{tex}x(b^2 + a^2) = 2ab^2 + a^3 - ab^2{/tex}
{tex}x(b^2 + a^2) = ab^2 + a^3{/tex}
{tex}x(b^2 + a^2) =a(b^2 + a^2){/tex}
{tex}x = \frac { a \left( b ^ { 2 } + a ^ { 2 } \right) } { \left( b ^ { 2 } + a ^ { 2 } \right) } = a{/tex}
Putting x = a in (i),we get
{tex}b \times a + a y = 2 a b{/tex}
{tex}a y = 2 a b - a b \Rightarrow a y = a b{/tex} or y = b
{tex}\therefore{/tex} solution is x = a, y = b

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prove that sin2A+cos2A=1

Posted by Mudit Singh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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Define line

Posted by Vikash Kumar 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Nivedita Gupta 7 years, 7 months ago

Line is the collection of infinite points.,which. Is infinite in length and it has no specific end.

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7 hundreds and 3 tens together make

Posted by Rajshwa Pal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashu Sharma 7 years, 7 months ago

730

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Largest natural number which have name

Posted by Dhan Jeet 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashu Sharma 7 years, 7 months ago

Largest natural number does not exist because every natural number has its successor

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What is alpha and beta

Posted by Amirtharaj . 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Nivedita Gupta 5 years, 8 months ago

Alpha and Beta are the two zeros of any quadratic polynomial

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Arshita Patidar 7 years, 7 months ago

Alpha and bits are taken as zeores for polynomials

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Write 100 × 5

Posted by Pauly Varghese 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Nivedita Gupta 7 years, 7 months ago

500

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Chapter 1 ex 1.3 1question

Posted by Akif Israr 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Yashika Upadhyay 7 years, 7 months ago

Suppose root 5 is a rational number Therefore root 5= p/ , p,q are integers, & q is not equals to 0 On reducing-- root 5= a/b , a & b are coprime no. => b root 5= a Squaring both sides 5b^2= a^2 ------------(i) => b^2 = a^2 /5 Since 5 divides a^2 Therefore 5 will also divide a (by theorem 1.3) ----(ii) => a/5= c => a= 5c => a^2 = 25c^2 => 5b^2 = 25c^2 (by eq.^n (i)) => b^2= 5c^2 => b^2 /5= c^2 Therefore 5 divides b^2 Therefore 5 will also divide b (by theorem 1.3) -----(iii) From eq.^n (ii) & (iii) 5 divides a & b both Therefore 5 is common factor of a & b But this contradict the fact that a & b are coprime Therefore this is due to our wrong assumption that root 5 is rational. Therefore we conclude that root 5 is rational.

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Using the formula, tan 2A =2tan A/1- tan square A' find the value of tan 60º,it being given thattan 30º =1/root 3 .

Posted by Mohit Yadav 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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If 2 and 1/2 are the zeros of qx2+5x+r,then prove that q=r

Posted by Satyaveer Singh 7 years, 7 months ago

CBSE > Class 10 > Mathematics

0 answers

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Exercise-8.1

Posted by Uchhab Hati 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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tanA +secA=what

Posted by Gokul Chawla 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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integration of sin^2x

Posted by Aditya Srivastava 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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Pt.that _/3 +2_/5 is irrational plz?

Posted by Dharshini G.S.Dora 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Nivedita Gupta 7 years, 7 months ago

To prove this you need to prove that root 3 and root 5 are irrational. You can do this by long Method. Okk now then in last you can say that if irrational get added to rational always an irrational no. Comes And sorry I can't write whole answer. But It will be helpful for you. Thanks

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When n is a odd integer than show that n square-1 is divided by 8

Posted by Sid Siddharth 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Unnati Pragya 7 years, 7 months ago

We know that 4q + 1,4q+3 odd positive integer If n=4q+1 n^2-1= 16q^2+8+1-1 n^2-1=8(2q^2+1) n^2-1 is divisible by 8 If n=4q+3 n^2-1=16q^2+24q+9-1 n^2-1= 8(2q^2+3q+1) n^2-1 is divisible by 8 Hence,n^2 -1 is divisible by 8

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What are those 15 question related to CBSE board of chapter number 6 co-ordinate geometry from RD Sharma

Posted by Little Star 7 years, 7 months ago

CBSE > Class 10 > Mathematics

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Differentiate Between numbers and digits

Posted by Sumit Pal 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Md.Mehwar Ansari 7 years, 7 months ago

0-9 is single so it is called digit .after it 10-infinity it means group of digit is called number. Hope it will helpful

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Write the condition for rational number which can have a terminat ing decimal expansion

Posted by Sohel Shek 7 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Nivedita Gupta 7 years, 7 months ago

If the denominator is In the form of multiple of 2 and 5 then it is said to be a terminating decimal. Thank you hope it would be useful for you

1Thank You

Dharshini G.S.Dora 7 years, 7 months ago

Sohel shek r u a student of kvs . ok the ans is: the denominator of the rational no. should have the prime factors 2^ m or 5^m or 2^m.5^n .

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If alpha and beta are zeros of x2-px+q prove that alpha2/beta2+ beta2/alpha2=p4/q2-4p2/q+2

Posted by Khushi Singh 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Here α and β are the zeros of polynomial f(x) = x² - px + q
So a=1,b=-p,c=q
Sum of the zeroes α + β={tex}-\frac ba{/tex} = p
Product of the zeroes αβ=q
{tex}\frac{{{\alpha ^2}}}{{{\beta ^2}}} + \frac{{{\beta ^2}}}{{{\alpha ^2}}}{/tex}
{tex}= \frac{{{\alpha ^4} + {\beta ^4}}}{{{\alpha ^2}{\beta ^2}}}{/tex}
{tex}=\frac{\left(\mathrm\alpha^2+\mathrm\beta^2\right)^2-2\left(\mathrm{αβ}\right)^2}{\left(\mathrm{αβ}\right)^2}=\frac{\{(\mathrm\alpha+\mathrm\beta)^2-2\mathrm{αβ}\}^2-2\left(\mathrm{αβ}\right)^2}{\left(\mathrm{αβ}\right)^2}{/tex}

{tex}=\frac{(\mathrm p^2-2\mathrm q)^2-2\mathrm q^2}{\mathrm q^2}=\frac{\mathrm p^4+4\mathrm q^2-4\mathrm p^2\mathrm q-2\mathrm q^2}{\mathrm q^2}=\frac{\mathrm p^4+2\mathrm q^2-4\mathrm p^2\mathrm q}{\mathrm q^2}{/tex}

{tex}=\frac{\mathrm p4}{\mathrm q^2}-\frac{4\mathrm p^2\mathrm q}{\mathrm q^2}+\frac{2\mathrm q^2}{\mathrm q^2}=\frac{\mathrm p4}{\mathrm q^2}-\frac{4\mathrm p^2}{\mathrm q}+2=\mathrm{RHS}{/tex}
Hence, proved.

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If Triangle Abc is isosceles with AB=AC. Prove that tangent at A to the circumcirle of triangle ABC is parallel to BC

Posted by Sahith Panga 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Draw AD {tex}\perp{/tex} BC

In {tex} ADB \ and \ ADC {/tex}
{tex}AB = AC{/tex} [Given]
{tex}AD = AD{/tex}
{tex}ADB = ADC [Each \ 90^o]{/tex}
{tex}\therefore{/tex} {tex}\triangle \mathrm { ADB } \cong \triangle \mathrm { ADC }{/tex}
{tex}\Rightarrow{/tex} {tex}BD = CD{/tex}
{tex}\therefore{/tex} AC passes through O,centre of the circle
{tex}\therefore{/tex} Perpendicular bisector of the chord passes through the centre of the circle
Now OA {tex}\perp{/tex} PQ (radius through the point of contact)
{tex}\therefore{/tex} {tex}\angle{/tex}PAO = 90^o
Also {tex} ADB = 90^o{/tex}
{tex}\therefore{/tex} {tex}\angle \mathrm { PAO } + \angle \mathrm { ADB } = 180 ^ { \circ }{/tex}
{tex}\therefore{/tex} AP||BC

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Prove root5 - root3 as irrational

Posted by Siddhant Waghmare 7 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sahith Panga 4 years, 10 months ago

Let us assume that root5-root3 is not an irrational number So root5-root3 is rational number Therefore root5-root3=a/b b=a/root5-root3=a/root5-root3*root5+root3/root5+root3=a(root5+root 3) /2 b=a(root5+root 3)/2 It is impossible since rational number b is equal to irrational number a(root5+root 3)/2 So our assumption is wrong Therefore root 5-root 3is irrational number

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Find the HCF of highest two digit number and highest three digit number using Euclid Lemma.
Show that every even positive integer can be expressed as 6q+1, 6q+3, and 6q+5.
Prove that square of a positive integer can be expressed in the form 3n or 3n+1.
Prove that <m:omath><m:rad><m:radpr><m:deghide m:val="on"><m:ctrlpr></m:ctrlpr></m:deghide></m:radpr><m:deg></m:deg><m:e><m:r>3</m:r></m:e></m:rad></m:omath> is an irrational number.
Find whether the decimal representation of <m:omath><m:f><m:fpr><m:ctrlpr></m:ctrlpr></m:fpr><m:num><m:r>310</m:r></m:num><m:den><m:r>775×8</m:r></m:den></m:f></m:omath> is terminating or not? If terminating, write its decimal form.
In a cinema hall there are three types of classes, I, II and balcony. Number of seats in each class is 225, 315 and 135 respectively. The management wanted to put equal and maximum number of chairs in each row. Find the number of chairs in each row?
Prove that 2 – 5<m:omath><m:rad><m:radpr><m:deghide m:val="on"><m:ctrlpr></m:ctrlpr></m:deghide></m:radpr><m:deg></m:deg><m:e><m:r>3</m:r></m:e></m:rad></m:omath> is an irrational number.
Find the value of “n” so that 6ⁿ ends with zero? Justify your answer.
Find whether the number 2x3x5x7x11 + 5 a prime or composite? Justify your answer.
Find the GCD of the numbers 215, 135 and 725 using Euclid algorithm.
Factorize each of the numbers 2304 and 1296 and hence find LCM and GCD.
Find three integral solutions of the linear equation 2x + 3y = 5.
Write as linear equation: the cost of 5 kg sugar and 3 kg oil is ` 440.
Express as Linear equations: The total strength of a class is 56, and twice the number of boys is equal to 5 times the number of girls.
Draw the graph of the following pair of linear equations:
(i) 2x + y = 5, x + 2y = 4

(ii) 3x – 2y = 7, 2x + 3y = –4