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  • 1 answers

Sia ? 6 years, 4 months ago

f(x) =4x2- 8kx + 8x - 9
= 4x2+ (8- 8k)x - 9
Let one zero = {tex}\alpha{/tex}
{tex}\therefore{/tex}other zero = -{tex}\alpha{/tex}[A.T.Q.]
Now Sum of zeroes ={tex}​​\frac { - b } { a }{/tex}
{tex}\Rightarrow \quad \alpha + ( - \alpha ) = \frac { - ( 8 - 8 k ) } { 4 }{/tex}{tex}\Rightarrow 0 = \frac { - 8 + 8 k } { 4 }{/tex}
{tex}\Rightarrow{/tex}-8 + 8k = 0 {tex}\Rightarrow{/tex}k = 1
Polynomial p(x) = kx2 + 3kx + 2
becomes p(x) ={tex}1 \times x ^ { 2 } + 3 \times x + 2{/tex} [Using k = 1]
= x2 + 3x + 2
For zeroes of p(x),x2 + 3x + 2 = 0
{tex}\Rightarrow{/tex} (x + 2)(x + 1) = 0
{tex}\Rightarrow{/tex} x = - 2,x = - 1

  • 1 answers

Amaira Desai 7 years, 7 months ago

0
  • 1 answers

Sia ? 6 years, 4 months ago

Let the number of right answers and wrong answers be x and y respectively.
According to the question,
{tex}3x - y = 40{/tex} ...(i)
{tex}4x - 2y = 50​​​​​​​{/tex}
{tex}\Rightarrow{/tex} {tex}2x - y = 25{/tex} ...(ii)
Subtracting equation (ii) from equation (i), we obtain:
{tex}x = 15{/tex}
Substituting the value of x in equation (ii), we obtain:
{tex}30 - y = 25{/tex}
{tex}y = 5{/tex}
Thus, the number of right answers and the number of wrong answers is 15 and 5 respectively. Therefore the total number of questions is 20.

  • 1 answers

Aisha Jain 7 years, 7 months ago

Which question ??
  • 1 answers

Sia ? 6 years, 4 months ago

Check syllabus here : https://mycbseguide.com/cbse-syllabus.html

  • 0 answers
  • 3 answers

Jinat Yashmin 7 years, 7 months ago

Non terminating decimal

Harshit Mehta 7 years, 7 months ago

No,it is not terminating . It is non-terminating

Shivraj Sah 7 years, 7 months ago

Terminating decimal
  • 0 answers
  • 2 answers

Riyam Arora 7 years, 7 months ago

-2

Avinash Kumar 7 years, 7 months ago

-2
  • 3 answers

Shailesh Gurjar 7 years, 7 months ago

Irrational no

Harshit Mehta 7 years, 7 months ago

3+2√5=P/Q 2√5=P/Q-3 2√5=P-3Q/Q √5=P-3Q/2Q So,it is irrational

Manish Chaurasiya 7 years, 7 months ago

IrrAtional
  • 1 answers

Riyam Arora 7 years, 7 months ago

The equation will be tm + n +tm -n Plus n or -n cancel Because of opposite sign Then answer remains 2tm
  • 1 answers

Abhiyash Rajput 7 years, 7 months ago

6= 2 x 3 20= 2 x 2 x 5 H.C.F=2 L.C.M= 120
  • 0 answers
  • 1 answers

Yuvraj Tak 7 years, 7 months ago

5184
  • 0 answers
  • 2 answers

Riyam Arora 7 years, 7 months ago

Value of c divided by a

Riyam Arora 7 years, 7 months ago

C _ A
  • 0 answers
  • 0 answers
  • 3 answers

Amaira Desai 7 years, 7 months ago

B^2-4ac. If b^2 - 4ac =0 or greater than 0 then roots exist otherwise not exist.

Varun Punia 7 years, 7 months ago

Ax²+bx+c

Kamalbhan Singh 7 years, 7 months ago

2
  • 1 answers

Shikha Kaushiik 7 years, 7 months ago

Using a=bq +r Put the value of r 1,2 A =2q +0 A= 2q+1 Now squaring both sides A^2=2×2 =2m (q =m) In 2nd case A =2q+1 Squaring both sides A^2=(2q +1)^2 A^2 =4q^ + 1 + 4q (a+b)^2 =2(2q+2q)+1 (2q+2q)=m =2m+1

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