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  • 1 answers

Shahareyar Anjum Kha Sufiyan 7 years, 6 months ago

-6
  • 1 answers

Sia ? 6 years, 4 months ago

Let p(x) = ax3 + 4x2 + 3x - 4 and q(x) = x3 - 4x + a be the given polynomials. The remainders when p(x) and q(x) are divided by (x - 3) are p(3) and q(3) respectively.
By the given condition, we have
p(3) = q(3)
{tex}\Rightarrow{/tex} a {tex}\times{/tex}33 + 4 {tex}\times{/tex}32 + 3 {tex}\times{/tex}3 - 4 = 33 - 4 {tex}\times{/tex}3 + a
{tex}\Rightarrow{/tex} 27a + 36 + 9 - 4 = 27 - 12 + a
{tex}\Rightarrow{/tex} 26a + 26 = 0 {tex}\Rightarrow{/tex} 26a = -26 {tex}\Rightarrow{/tex} a = -1

  • 0 answers
  • 3 answers

Charu Sharma 7 years, 6 months ago

Formic acid is released by ant. It is also known as simple carboxylic acid...

Mohd Hussain 7 years, 6 months ago

ethanoic acid

N N 7 years, 6 months ago

Formic acid or ethanoic acid
  • 1 answers

Sia ? 6 years, 4 months ago

Let N = 5q + 1
{tex}\therefore{/tex} N2 = (5q + 1)2
{tex}\Rightarrow{/tex} N= 25q2 + 10q + 1
N2= 5(5q2 + 2q) + 1
= 5m + 1, where q is soqe integer
Hence, the square of any positive integer of the form 5m + 1 will leave a remainder 1 when divided by 5 for some integer m .

  • 1 answers

Sia ? 6 years, 4 months ago

117 = 13 {tex}\times{/tex} 3 {tex}\times{/tex} 3
65 = 13 {tex}\times{/tex} 5
HCF (117, 65) = 13
LCM(117,65) = 13 {tex}\times{/tex} 5 {tex}\times{/tex} 3 {tex}\times{/tex} 3 = 585

Here is given that:
{tex}HCF =65m-117{/tex}

{tex}13=65m-117{/tex}

{tex}65m=130{/tex}
m = {tex}\frac { 130 } { 6 5 } ={/tex}2

  • 1 answers

Sia ? 6 years, 4 months ago

We have,  x = 4 and x = -3.
Then,
x - 4 = 0 and x + 3 = 0
{tex}\Rightarrow{/tex} (x - 4)(x + 3) = 0
{tex}\Rightarrow{/tex} x2 + 3x - 4x - 12 = 0
{tex}\Rightarrow{/tex} x2 - x - 12 = 0

This is the required quadratic equation

  • 1 answers

Nipun Goyal 7 years, 6 months ago

By multiplying 1st and last digits and find those two numbers whose sum is the middle term and their product is the product of 1st and last digits.
  • 1 answers

Sia ? 6 years, 4 months ago

Check last year papers here  : https://mycbseguide.com/cbse-question-papers.html

  • 1 answers

Kannu Kranti Yadav 7 years, 6 months ago

May be 30 may
  • 4 answers

Nipun Goyal 7 years, 6 months ago

0

Navin Raj 7 years, 6 months ago

0

Jiya Bhargava 7 years, 6 months ago

1

Amaira Desai 7 years, 6 months ago

1
  • 1 answers

Sia ? 6 years, 4 months ago

sin(135)
= sin (90 + 45) // sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
= sin(90)cos(45) + cos(90)sin(45)
= ( 1 x 1/√2) + (0 x 1/√2)
= 1/√2
= (√2)/2

  • 6 answers

Nipun Goyal 7 years, 6 months ago

Infinity

Amaira Desai 7 years, 6 months ago

Infinity

Jiya Bhargava 7 years, 6 months ago

It's not defined or we can say infinity

Ashtrix Official 7 years, 6 months ago

Nope buddy !! 0÷1 = 0 , but 1÷0 = infinity

Kanwaldeep Singh 7 years, 6 months ago

0

Ashtrix Official 7 years, 6 months ago

It's infinity .
  • 2 answers

Sarthak Gupta 7 years, 6 months ago

It can be form in p/q & q is not equal to 0 For example- 2/5

Ashtrix Official 7 years, 6 months ago

It is terminating and repeating ( nonterminating )
  • 1 answers

Jiya Bhargava 7 years, 6 months ago

Answer is 5/6 you should put the values of trigonometric ratios and then evaluate it then you will get the answer
  • 2 answers

Jiya Bhargava 7 years, 6 months ago

Thank you so much sir for your answer but then also i didnot understand if you can then it will be a great pleasure

Amit Kumar 7 years, 6 months ago

Let (x+2y) be p and ( 3x- 2y) be q 1/2p+5/3q=-3/2 Solve it 5/4p-3/5q=61/60 Solve it We'll get 6p+10q=(-18)............1 75p-36q=61...........2 Multiply eq1 by36 and eq2 by 10 We'll get next eq and eliminate them
  • 1 answers

Amit Kumar 7 years, 6 months ago

11x-7y=xy.............1 9x-4y=6xy............2 Multiply by 4 eq1 and by 7 eq2 We get 44x-28y=4xy........3 63x-28y=42xy............4 Eliminating eq4 and eq3, we get 19x=38xy Y=2, put value of y in any eq we'll get the value ofx.
  • 0 answers
  • 1 answers

Om Zankat 7 years, 6 months ago

Ax + By + C = 0 Where A, B, C are a real no.
  • 0 answers
  • 2 answers

Amit Kumar 7 years, 6 months ago

Alpha +beta + gama = 1/2 Alpha beta + beta gama + alpha gama= 1/3 Alpha beta gama= 1/4 {X cube -(alpha+ beta+ gama) x square+ (alpha beta + beta gama +alpha gama)x + (alpha beta gama)} Put values we'll get the polynomial

Mohammad Amaan 7 years, 6 months ago

24x^3+26x^2+9x+1
  • 1 answers

Kannu Kranti Yadav 7 years, 6 months ago

But where is the polynomial ?
  • 0 answers
  • 1 answers

Amit Kumar 7 years, 6 months ago

Zeros are -2 and -1. Thus ( x-2)=0, (x -1)=0 We get (x+2)and (x+1) Multiply both, we get X square + 3x + 2, now divide it with f(x) We get 2x square -5x - 3,now factorise it ,we get (x -3) (2x+1) (X-3)=0, (2x+1)=0, Solve it, we get X=3 and x= -1/2
  • 1 answers

Kannu Kranti Yadav 7 years, 6 months ago

I don't get ur que

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