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Ask QuestionPosted by Vaishali Dungahu 7 years, 6 months ago
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Posted by Rajesh Bhaskar 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
x - y = 1 {tex}\Rightarrow{/tex} x = 1 + y
<th scope="row">x</th> <th scope="row">y</th>| 2 | 3 | 4 |
| 1 | 2 | 3 |
2x + y = 8 {tex}\Rightarrow{/tex} x = {tex}\frac{8-y}{2}{/tex}
<th scope="row">x</th> <th scope="row">y</th>| 3 | 2 | 1 |
| 2 | 4 | 6 |
Posted by Gaurav Chaudhry 7 years, 6 months ago
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Posted by Sohel Shek 7 years, 6 months ago
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Posted by Aman Gurjar 7 years, 6 months ago
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Lipsa Rani 7 years, 6 months ago
Posted by Anshpreet Singh 7 years, 6 months ago
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Posted by Anmol Anand 7 years, 6 months ago
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Posted by Vansh Wadhwa 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
Let the income of X be Rs. 8x and the income of Y be Rs, 7x.
Further, let the expenditures of x and y be 19y and 16y respectively. Then,
Saving of X = {tex}8x - 19y{/tex}
Saving of Y = {tex}7x - 16y{/tex}
{tex}\therefore{/tex} {tex}8x - 19y = 1250{/tex} .....(i)
and, {tex}7x - 16y = 1250{/tex} .....(ii)
Multiplying equation (i) by 7, and equation (ii) by 8, we get
{tex}56x - 133y = 8750{/tex} ...(iii)
{tex}56x - 128y = 10000{/tex} ....(iv)
Subtracting equation (iv) from equation (iii), we get
{tex}-133y + 128y = 8750 - 10000{/tex}
{tex}\Rightarrow{/tex} {tex}-5y = -1250{/tex}
{tex}\Rightarrow y = \frac{{ - 1250}}{{ - 5}} = 250{/tex}
Putting y = 250 in equation (i), we get
{tex}8x - 19\times 250 = 1250{/tex}
{tex}\Rightarrow{/tex} {tex}8x - 4750 = 1250{/tex}
{tex}\Rightarrow{/tex} {tex}8x = 1250 + 4750{/tex}
{tex}\Rightarrow x = \frac{{6000}}{8} = 750{/tex}
Thus, X's income = 8x = 8 {tex}\times{/tex} 750 = Rs.6000
Y's income = 7x = 7 {tex}\times{/tex} 750 = Rs.5250.
Posted by Anmol Anand 7 years, 6 months ago
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Posted by Devanshi Dhuria 7 years, 6 months ago
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Posted by Soumitra Agrawal 7 years, 6 months ago
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Posted by Soumitra Agrawal 7 years, 6 months ago
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Kunal Rajour 7 years, 6 months ago
Posted by Rano Majhi 7 years, 6 months ago
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Posted by Vasundhra Sharma 7 years, 6 months ago
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Posted by Pratibha Kumari 7 years, 6 months ago
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Posted by Sanjeev Gupta 7 years, 6 months ago
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Posted by Drashti Vaish 7 years, 6 months ago
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Posted by Aryan Pandey 7 years, 6 months ago
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Posted by Shivam Kumar 7 years, 6 months ago
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Posted by Abhishek Kumar 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
Let the ten's digit of required number be x and its unit digit be y respectively.
Required number = 10x + y
According to the question, it is given that a number consisting of two digits is 7 times the sum of its digits.
{tex}\therefore{/tex} 10x + y = 7(x + y)
10x + y = 7x + 7y
10x - 7x - 7y + y = 0
3x - 6y = 0.............(i)
when 27 is subtracted from the number the digits are reversed.
After reversing the digits, the number = 10y + x
{tex}\therefore{/tex}(10x + y) - 27 = 10y + x
10x - x + y - 10y = 27
9x - 9y = 27
x - y = 3.............(ii)
Multiplying (i) by 1 and (ii) by 6, we get
3x - 6y = 0........(iii)
6x - 6y = 18.......(iv)
Subtracting (iii) from (iv), we get
3x = 18
{tex}x = \frac { 18 } { 3 } = 6{/tex}
Put the value of x = 6 in equation (i), we get
3 {tex}\times{/tex} 6 - 6y = 0
18 - 6y = 0
{tex}- 6 y = - 18 \Rightarrow y = \frac { - 18 } { - 6 } = 3{/tex}
Number = 10x + y
= 10 {tex}\times{/tex} 6 + 3
= 60 + 3
= 63
Hence the number is 63.
Posted by Ananthu At 7 years, 6 months ago
- 3 answers
Kannu Kranti Yadav 7 years, 6 months ago
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