CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

suppose that a is any positive integer then it is divided by 4 then we get q as a quotient and r as a remainder then by euclid's division lemma we get that a=4q + r where 0<= 4<r then r= 0,1,2,3 when r = 0 then a=4q = 2*2q (let 2q = p) = 2p which is an even when r=1 then a= 4q+1 which is an odd when r= 2 then a= 4q+2 = 2(2q+1) (let 2q+1 = p) = 2p which is an even when r=3 then a= 4q+3 = 4q+2+1 = 2(2q+1) +1 (let 2q+1 =p) = 2p+1 which is an odd. hence, we can say that every positive integer is of the form 4q+1 or 4q+3. proved.

1Thank You

ANSWER

In the following figuer PQ and PR are tangents at Q and R respectively. If SQR=38 then find QPR, PRQ, QSR and PQR

Posted by Pauel Gupta 7 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Write a rational number between √2 and √3

Posted by Dheeraj Chander 7 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Dheeraj Chander 7 years, 6 months ago

Bro i can't find it plzz give space between and write once more

0Thank You

Harsimran Singh 7 years, 6 months ago

√2 and √3 1/2*(√2+√3) (√2+√3)/2 (√2+√3)/√2+√2 2=√2+√2 √2 and √2 cancelled so √3/√2 answer

1Thank You

Harsimran Singh 7 years, 6 months ago

1Thank You

ANSWER

Express 150 as a product of its prime factors

Posted by Dheeraj Chander 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Ankit Kumar 7 years, 6 months ago

2*3*5²

1Thank You

ANSWER

In an ap, a3 =15, s10 =125, find d and a10

Posted by Chhavi Agarwal 7 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Anjani Kumar Singh 7 years, 6 months ago

d. -10 and a10.8

0Thank You

Pranay Vitekar 7 years, 6 months ago

How 125

0Thank You

Nafeesathul Misriya 7 years, 6 months ago

125

0Thank You

ANSWER

®2-1/3

Posted by Ravi Bhaskar 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Ullas B 7 years, 6 months ago

2/1 - 1/3 6/3-1/3 5/3

2Thank You

ANSWER

Find the value of k so that the following system of equations has infinitely many solutions 4x-y=3 and 3x+2y=5k

Posted by Account Deleted 7 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Chhavi Agarwal 7 years, 6 months ago

Instead of÷ you may put/ . Sorry for the mistake

0Thank You

Chhavi Agarwal 7 years, 6 months ago

ATQ a1÷a2=b1÷b2=c1÷c2. Now, 4÷3=-1÷2=3÷5k . now by cross multiplication , 8-(-3)=-5k-6. 11=-5k-6 . 11+6 =-5k . -17÷5 =k

2Thank You

ANSWER

A boat goes 64 km upstream and 72 km in 14 hours. It goes 80 km upstream and 90 km downstream in 18 hours. Find the speed of boat in still water and also the speed of stream.

Posted by Account Deleted 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Ullas B 7 years, 6 months ago

It is ncert text book

1Thank You

ANSWER

Ifx+1/x=3, find the value of x2+1/4x

Posted by Kannu Kranti Yadav 7 years, 6 months ago

CBSE > Class 10 > Mathematics

2 answers

Kannu Kranti Yadav 7 years, 6 months ago

Solve it

0Thank You

Jin Kazama 7 years, 6 months ago

5/4

1Thank You

ANSWER

Irrational +irrational =?

Posted by Anu Thakur 7 years, 6 months ago

CBSE > Class 10 > Mathematics

3 answers

Bibek Muduli 7 years, 6 months ago

"The sum of two irrational numbers is SOMETIMES irrational." The sum of two irrational numbers, in some cases, will be irrational. However, if the irrational parts of the numbers have a zero sum (cancel each other out), it will rational

3Thank You

Pratysh Padhan 7 years, 6 months ago

irrational

0Thank You

Siddhant Singh 7 years, 6 months ago

Maybe rational or irrational

1Thank You

ANSWER

If sec theta=5\7,show that 2(cos theta-sin theta)/cot theta -tan theta =12/7

Posted by Toshan Naik 7 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Shubham Kumar 7 years, 6 months ago

It can't be possible bro because we know sec theta=h/b then,here 'b' is greater than 'h' which can't be possible.

2Thank You

ANSWER

Explain why 11×13×15×17+47 is a composite numbera

Posted by Alok Tomar 7 years, 6 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Solve for x:-12abx2 -(9a2 - 8b2)x - 6ab

Posted by Rahul Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

12 abx² - (9a² - 8b²)x - 6ab = 0
Comparing with Ax² + Bx + C = 0, we get
A = 12 ab, B = -(9a² - 8b²), C = -6 ab
Using the quadratic formula, {tex}\mathrm { x } = \frac { - \mathrm { B } \pm \sqrt { \mathrm { B } ^ { 2 } - 4 \mathrm { AC } } } { 2 \mathrm { A } }{/tex}
we get {tex}\Rightarrow x = - \left( - \left( 9 a ^ { 2 } - 8 b ^ { 2 } \right) \right\}{/tex}
{tex}\frac { \pm \sqrt { \left( - \left( 9 a ^ { 2 } - 8 b ^ { 2 } \right) \right) ^ { 2 } - 4 ( 12 a b ) ( - 6 a b ) } } { 2 ( 12 a b ) }{/tex}
{tex}= \frac { 9 a ^ { 2 } - 8 b ^ { 2 } \pm \sqrt { 81 a ^ { 4 } + 64 b ^ { 4 } - 144 a ^ { 2 } b ^ { 2 } + 288 a ^ { 2 } b ^ { 2 } } } { 24 a h }{/tex}

{tex}= \frac { 9 a ^ { 2 } - 8 b ^ { 2 } \pm \sqrt { \left( 9 a ^ { 2 } + 8 b ^ { 2 } \right) ^ { 2 } } } { 24 a b }{/tex}
{tex}= \frac { 9 a ^ { 2 } - 8 b ^ { 2 } \pm \left( 9 a ^ { 2 } + 8 b ^ { 2 } \right) } { 24 a b }{/tex}
{tex}= \frac { 9 a ^ { 2 } - 8 b ^ { 2 } + 9 a ^ { 2 } + 8 b ^ { 2 } } { 24 a b }{/tex}
{tex}= \frac { 9 a ^ { 2 } - 8 b ^ { 2 } - 9 a ^ { 2 } - 8 b ^ { 2 } } { 24 a b }{/tex}
{tex}= \frac { 18 a ^ { 2 } } { 24 a b } , \frac { - 16 b ^ { 2 } } { 24 a b } = \frac { 3 a } { 4 b } , \frac { - 2 b } { 3 a }{/tex}
{tex}\therefore{/tex} the solution of the given equation are {tex}\frac { 3 a } { 4 b } \text { and } \frac { - 2 b } { 3 a }{/tex}.

0Thank You

ANSWER

Find hcf of 81and237 and express it as linear combination of 81 and 237

Posted by Neha Sharma 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Since, 237 > 81
On applying Euclid's division algorithm, we get
237 = 81 {tex}\times{/tex} 2 + 75 ..........(i)
81 = 75 {tex}\times{/tex} 1 + 6 ..........(ii)
75 = 6 {tex}\times{/tex} 12 + 3 .........(iii)
6 = 3 {tex}\times{/tex} 2 + 0 .............(iv)
Hence, HCF (81,237) = 3.
In order to write 3 in the form of 81x + 237y,
Now,
{tex}\style{font-family:Arial}{\begin{array}{l}3=75-6\times12(\;from(iii))\\=75-(81-75\times1)\times12\\=75-(81\times12-75\times12)\\=75-81\times12+75\times12\\=75(1+12)-81\times12\\=75\times13-81\times12\\=13\times(237-81\times2)-81\times12\;(\;Substuting\;75\;from(i))\\=13\times237-13\times81\times2-81\times12\\=237\times13-81\times(26+12)\\=81(-38)+237\times13\\=81x+237y\end{array}}{/tex}
Hence, x = -38 and y = 13