CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Let the digit at tens place be x and the digit at ones place be y. So, the no.is 10x+y Sum of its digits is x+y So, the divisor is x+y And, quotient is 7 And, remainder is 0 So, by euclid's division lemma, 10x+y=(x+y)×7+0 or, 10x+y=7x+7y or, 3x-6y=0 or, x-2y=0-------------------------------------------------(1) And, according to question, (10x+y)-27=10y+x or, 10x+y-27=10y+x or, 10x-x+y-10y=27 or, 9x-9y=27 or, x-y=3--------------------------------------------------(2) Subtracting (1) from( 2) x-y-x+2y=3-0 or, y=3 Putting y=3 in (2) x=6 So,. x=6 y=3. So, the no. is 63.

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usefulness of mathematics in the field of Defence

Posted by Hemant Kumar 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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usefulness of mathematics in the field of Aeronautics

Posted by Hemant Kumar 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Cosec2(90-theta)-tan2 theta/2(cos2 48+cos2 42)-2tan2 30 sec2 52 sin 2 38 /cosec2 70 -tan2 20

Posted by Jugal Jain 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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check graphically wheather the pair of equations 3x-2y+2=0 and 3/2x-y+3=0 , is consistent. also find the coordinates of the points where the graps of the equations meet the Y.axis

Posted by Dhansingh Chaudhary 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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If cotA + tanA =x And secA - cosA = y Prove that- (x²y)⅔ -(xy²)⅔=1

Posted by Gopika Chandran 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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68 is thewater term ofto AP 7,10,13.......

Posted by Manvith Devadiga 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Rupal ???? 7 years, 5 months ago

68 is not the term of given AP

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Mean find 37

Posted by Harvir Singh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Draw the graph of 2x + 3y=8 and x-2y=-3 shade the region bounded by these lines and y axis find the areavof the shaded region also find the co-ordinate of the triangle

Posted by Upadhyay Sir 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Find the number to be added to the polynomial xsqure -5x+4, so that 3is the zero of the polynomial

Posted by Aryan Vats 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Angel Chaubey 7 years, 5 months ago

If 2 is added to the polynomial..... x²-5x+4+2=x²-5x+6 x²-3x-2x+6 =x(x-3)-2(x-3) (x-3)(x-2) =x=3,2

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Prove that root 2 is irrational no.

Posted by Ayush Shivam 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Ankita ?? Arpita☺️ 7 years, 5 months ago

Please yogita prove √5 is an iirational

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Yogita Ingle 7 years, 5 months ago

Given √2 is irrational number.
Let √2 = a / b wher a,b are integers b ≠ 0
we also suppose that a / b is written in the simplest form
Now √2 = a / b
⇒ 2 = a² / b²
⇒ 2b² = a²
∴ 2b² is divisible by 2
⇒ a² is divisible by 2
⇒ a is divisible by 2
∴ let a = 2c
a² = 4c²
⇒ 2b² = 4c²
⇒ b² = 2c²
∴ 2c² is divisible by 2
∴ b² is divisible by 2
∴ b is divisible by 2
∴ a are b are divisible by 2 .
This contradicts our supposition that a/b is written in the simplest form.
Hence our supposition is wrong
∴ √2 is irrational number.

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Factorise x*2+5√2+12

Posted by Sathwik Vm 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Angel Chaubey 7 years, 5 months ago

(x+2√2)(x+3√2)

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Write coordinates of origion

Posted by Jaskaran Sandhu 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Factorization of 11x^2 -33X-368 ?

Posted by Eakasnh Meena 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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2x+5=0 x=

Posted by Ujjwal Kumar 7 years, 5 months ago

CBSE > Class 10 > Mathematics

6 answers

Aabith $ 7 years, 5 months ago

-5/2

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Diwakar Kumar 7 years, 5 months ago

-5/2

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Varsha Yadav 7 years, 5 months ago

-5/2

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Anchal Singh 7 years, 5 months ago

-2.5

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Pratima Bhagat 7 years, 5 months ago

-5/2

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G.Mani Kanta 7 years, 5 months ago

-5/2

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What is the hcf of first prime and composition no.

Posted by Navdep Ghosh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Pratibha K 7 years, 5 months ago

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If hcf of two number is 2and their product is 120 find their lcm

Posted by Charumathi Mathi 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Solve for x and y ax/b-by/a=a+b;ax-by=2ab

Posted by Ayush Singh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Can I will be able to score good marks even i am unable to attend school for 1 month ?

Posted by Kunal Singh 7 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Kannu Kranti Yadav 7 years, 5 months ago

Surely,by hard work and by taking less or no holiday

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Aryan Kaushik 7 years, 5 months ago

Yes.but dont take any holiday now onwards

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prove that root5+root3 and root3 is an irrational number

Posted by Amit Kumar 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

G.Mani Kanta 7 years, 5 months ago

We know that √5 and √3 and √2 are irrational numbers

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If m and n are the zeroes of the polynomial ax2+5x+c find the value of a and c if m+n+mn=10

Posted by Mahek Rawat 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Consistency

Posted by Logadharshini Logadharshini 7 years, 5 months ago

CBSE > Class 10 > Mathematics

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Sides AB and AC and median ADof a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR show that triangle ABC is similar to triangle PQR

Posted by Nachiketh Neelaraddi 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given : In {tex}\Delta A B C \text { and } \Delta P Q R{/tex} The AD and PM are their medians,
such that {tex}\frac { A B } { P Q } = \frac { A D } { P M } = \frac { A C } { P R }{/tex}
To prove : {tex}\Delta A B C \sim \Delta P Q R{/tex}
Construction : Produce AD to E such that AD = DE and produce PM to N such that PM = MN. Join CE and RN.
Proof : In {tex}\Delta A B D \text { and } \Delta E D C{/tex}
{tex}AD=DE{/tex}
{tex}\angle A D B = \angle E D C{/tex} (vertically opposite angles)
{tex}BD=DC\text{(as AD is a median)}{/tex}
{tex}\therefore \quad \Delta A B D \equiv \Delta E D C{/tex} (By SAS congruency)
or, {tex}AB=CE{/tex} (By CPCT)
Similarly, PQ = RN {tex}{/tex}
{tex}\frac { A B } { P Q } = \frac { A D } { P M } = \frac { A C } { P R }{/tex} (Given)
or, {tex}\frac { C E } { R N } = \frac { 2 A D } { 2 P M } = \frac { A C } { P R }{/tex}
or {tex}\frac{CE}{RN}=\frac{AE}{PN}=\frac{AC}{PR}{/tex}
So {tex}∆ACE \sim ∆PRN{/tex}
{tex}\angle 3=\angle 4{/tex}
Similarly {tex}\angle 1=\angle 2{/tex}
{tex}\angle 1+\angle3=\angle2+\angle4{/tex}
So {tex}\angle A=\angle P\text{ and}{/tex}
{tex}\frac{AB}{PQ}=\frac{AC}{PR}\text{(given)} {/tex}
Hence {tex}∆ABC\sim ∆PQR{/tex}

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Prove that ( 3+2 root 5 ) squareisan irrational no

Posted by Navjot Kaur 7 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

R T 7 years, 5 months ago

3+2√5=a/b 2√5=a/b-3 √5=a/2b-3 =RHS is rational Let us assume that √5 is rational Then √5=p/q Also P&q are co primes Squaring on both sides 5 divides p and q This contractions arises due to our wrong assumption that √5 is rational =√5 is rational

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All algebric identities

Posted by Sara Khan 7 years, 5 months ago

CBSE > Class 10 > Mathematics