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Ask QuestionPosted by Diwakar Kumar 7 years, 5 months ago
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Posted by Raj Tiwari 7 years, 5 months ago
- 2 answers
Nachiketh Neelaraddi 7 years, 5 months ago
Posted by Xyz Abc 7 years, 5 months ago
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Posted by Sai Vignesh 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
Let digit at unit’s place = x and digit at hundred’s place = y
{tex}\therefore{/tex} Middle digit ={tex} x + y + 1{/tex}
Number = {tex}100y + 10(x + y + 1) + x{/tex}
Number obtained by reversing the digits = {tex}100x + 10(x + y + 1) + y{/tex}
ATQ.,
{tex}x + y + (x + y + 1) = 17{/tex}
{tex}\Rightarrow{/tex} {tex}2x + 2y = 16{/tex} ..(i)
and {tex}100x + 10(x + y + 1) = x - 396{/tex} ..(ii)
{tex}\Rightarrow{/tex} {tex}99x - 99y = -396{/tex}
{tex}\Rightarrow{/tex} {tex}x - y = -4{/tex}
By Solving equation (i) and (ii), we get
x = 2, y = 6 and Number = 692
Posted by Chanchal Bhardwaj 7 years, 5 months ago
- 3 answers
Posted by Shafi Moznur Ahmed 7 years, 5 months ago
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Posted by Rahul Kumar 7 years, 5 months ago
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Posted by Aditya Kumar 7 years, 5 months ago
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Posted by Deepak Kesari 7 years, 5 months ago
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Posted by Bhoomi Garg 7 years, 5 months ago
- 3 answers
Anchal Singh 7 years, 5 months ago
Posted by Narendar Gupta 7 years, 5 months ago
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Posted by Ritika Thakur 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
We have,
{tex}(a + b)^2x^2 - 4abx - (a - b)^2 = 0{/tex}
In order to factorize {tex}(a + b)^2x^2 - 4abx - (a - b)^2{/tex}, we have to find two numbers 'l' and 'm' such that.
l + m = -4ab and lm = -(a + b)2(a - b)2
Clearly, (a - b)2 + [-(a + b)2] = -4ab and lm = -(a + b)2(a - b)2
l = (a - b)2 and m = -(a + b)2
Now,
{tex}(a + b)^2x^2 - 4abx - (a - b)^2 = 0{/tex}
{tex}\Rightarrow{/tex} {tex}(a + b)^2x^2 - (a + b)^2x + (a - b)^2x - (a - b)^2 = 0{/tex}
{tex}\Rightarrow{/tex} (a + b)2x [x - 1] + (a - b)2[x - 1] = 0
{tex}\Rightarrow{/tex} (x - 1)[(a + b)2x + (a - b)2] = 0
{tex}\Rightarrow{/tex} x - 1 = 0 or (a + b)2x + (a - b)2 = 0
{tex}\Rightarrow{/tex} x = 1 or {tex}x = - \frac{{{{(a - b)}^2}}}{{{{(a + b)}^2}}}{/tex}
Posted by Shuvanshu Rai 7 years, 5 months ago
- 4 answers
Posted by Akanksha Singh 7 years, 5 months ago
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Posted by Nikita Sontakke 7 years, 5 months ago
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Kushagra Kumar Ghai 7 years, 5 months ago
3x+5y+11=0.............eq2
now subtract eq2 from eq1
gives 3x+5y=-14.............eq 3
hat is not possible so i recommend u to recheck the question
Posted by Sujana Vemula 7 years, 5 months ago
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Posted by Pradeep Rajeshkumar 7 years, 5 months ago
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Posted by Rahul Soren 7 years, 5 months ago
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Posted by Shobhit Mittal 7 years, 5 months ago
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Posted by Shobhit Mittal 7 years, 5 months ago
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Mh Kamali 7 years, 5 months ago
Sohan Pavan 7 years, 5 months ago
Posted by Sneha Dubey 7 years, 5 months ago
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Posted by Sivani Jayanadh 7 years, 5 months ago
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Posted by Saurav Sharma 7 years, 5 months ago
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Sia ? 6 years, 6 months ago
Thales is credited with the following five theorems of geometry:
- A circle is bisected by its diameter.
- Angles at the base of any isosceles triangle are equal.
- If two straight lines intersect, the opposite angles formed are equal.
- If one triangle has two angles and one side equal to another triangle, the two triangles are equal in all respects. (See Congruence)
- Any angle inscribed in a semicircle is a right angle. This is known as Thales' Theorem.
Posted by Chetan Bhange 7 years, 5 months ago
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Posted by Richi Vaishnav 7 years, 5 months ago
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Shivani Lama 7 years, 5 months ago
2Thank You