CBSE > Class 10 > Mathematics | CBSE Board | Homework Help | myCBSEguide

No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question

4 x square + 40 x minus bracket a square minus b square bracket close

Posted by Ayaz Ahmad Pathan 7 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

In triABC Dand E arr points on AB andAC such that DEIIBC .if AD=24 &AE=20, DE=2 & BC =50. Find BD &CE

Posted by Jitesh Singh 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

We have,

DE || BC
Now, In {tex}\triangle{/tex}ADE and {tex}\triangle {/tex}ABC
{tex}\angle A = \angle A{/tex} [common]
{tex}\angle A D E = \angle A B C{/tex} [{tex}\because{/tex} DE || BC {tex}\Rightarrow{/tex} Corresponding angles are equal]
{tex}\Rightarrow \triangle A D E= \triangle A B C{/tex} [By AA criteria]
{tex}\Rightarrow \frac { A B } { B C } = \frac { A D } { D E }{/tex} [{tex}\because{/tex} Corresponding sides of similar triangles are proportional]
{tex}\Rightarrow \frac { A B } { 5 } = \frac { 2.4 } { 2 }{/tex}
{tex}\Rightarrow A B = \frac { 2.4 \times 5 } { 2 }{/tex}
{tex}\Rightarrow{/tex} AB = 1.2 {tex}\times{/tex} 5
= 6.0 cm
{tex}\Rightarrow{/tex} AB = 6 cm
{tex}\therefore{/tex} BD = AB - AD
= 6 - 2.4
= 3.6 cm
{tex}\Rightarrow{/tex} DB = 3.6 cm
Now,
{tex}\frac { A C } { B C } = \frac { A E } { D E }{/tex} [{tex}\because{/tex} Corresponding sides of similar triangles are equal]
{tex}\Rightarrow \frac { A C } { 5 } = \frac { 3.2 } { 2 }{/tex}
{tex}\Rightarrow A C = \frac { 3.2 \times 5 } { 2 }{/tex}
= 1.6 {tex}\times{/tex} 5
= 8.0 cm
{tex}\Rightarrow{/tex} AC = 8 cm
{tex}\therefore{/tex} CE = AC - AE
= 8 - 3.2
= 4.8 cm
Hence, BD = 3.6 cm and CE = 4.8 cm

ANSWER

A two digit no. Is such that the product of its digits is 15 if 8 is added to the no. The digit interchange their place find the no.

Posted by Lucky? Dangi 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Assume digit at ten’s place = x and digit at unit’s place = y
Therefore number = 10x + y
Also xy = 15 {tex}\Rightarrow{/tex} x = {tex}\frac{15}{y}{/tex} ...(i)
According to given situation we have,
10x + y + 18 = 10y + x
{tex}\Rightarrow{/tex}9x - 9y + 18 = 0
{tex}\Rightarrow{/tex}x - y + 2 = 0
{tex}\Rightarrow{/tex}{tex}\frac{15}{y}{/tex} - y + 2 = 0 (From (i))
{tex}\Rightarrow{/tex}15 - y² + 2y = 0
{tex}\Rightarrow{/tex}y² - 2y - 15 = 0

On factorizing the above quadratic equation we get
(y - 5) (y + 3) = 0
{tex}\Rightarrow{/tex}y = 5, y = -3 [ y = -3 is rejected]
Put the value of y = 5 in equation (i), we obtain
x = {tex}\frac{15}{5}{/tex} = 3
{tex}\therefore{/tex} Number = 3 {tex}\times{/tex} 10 + 5 = 35.

ANSWER

2xsquare-5x-3=0 by completing square method

Posted by Saurabh Bramhankar 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Niyati Gupta 7 years, 4 months ago

X: 3, -1/2

ANSWER

X×X + 250X - 37500 = 0

Posted by Yogendra Thakre 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Jiya Kardam 7 years, 4 months ago

X2 + 250x - 37500 X2 + 750x -500x - 37500 X(X + 750) - 500(X + 750) (X +750)(X-500)

ANSWER

If alpha and beta are the zeros of the quadratic polynomial P X equal to X square + bx + c then show that alpha + beta equal to minus b y e

Posted by Subodh Kumar Mahato 7 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Interior angle of a polygon are in AP if the smallest angle is 128° and common difference is 5 . Find the number of sides of polygon

Posted by Samriddh Sahu 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let the number of sides of polygon be The interior angles of the polygon form an A.P.

Here, a = 120^o and d = 5^o

Since Sum of interior angles of a polygon with n sides is {tex}( n - 2 ) \times 180 ^ { \circ }{/tex}

{tex}\therefore \mathrm { S } _ { n } = ( n - 2 ) \times 180 ^ { \circ }{/tex}

{tex}\Rightarrow \frac { n } { 2 } [ 2 \times 120 + ( n - 1 ) \times 5 ] = 180 n - 360{/tex}

{tex}\Rightarrow 120 n + \frac { 5 n ^ { 2 } - 5 n } { 2 } = 180 n - 360{/tex}

{tex}\Rightarrow{/tex} 240n + 5n² - 5n = 360n - 720

{tex}\Rightarrow{/tex} 5n² - 125n + 720 = 0

divide by 5, we get

{tex}\Rightarrow{/tex} n² - 25n + 144 = 0

{tex}\Rightarrow{/tex} (n - 16) (n - 9) = 0

{tex}\Rightarrow{/tex} n = 16 or n = 9

But n = 16 not possible because a₁₆ = a + 15d = 120 + 15 {tex}\times{/tex} 5 = 195^o > 180^o

Therefore, number of sides of the polygon are 9.

ANSWER

If the polynomial x4-6x3+16x2-25x+10 is divided by another polynomial x2-2x+k the remainder comes out to be x+a. Find the values of a and k.

Posted by Priyanahu Khandelwal 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

On dividing x⁴- 6x³ - 16x² - 25x + 10 by x² - 2x + k

{tex}\therefore{/tex} Remainder = (2k - 9)x - (8 - k)k + 10
But the remainder is given as x+a.
On comparing their coefficients,
2k - 9 = 1
{tex}\Rightarrow{/tex} k = 10
{tex}\Rightarrow{/tex} k = 5 and,
-(8 - k)k + 10 = a
{tex}\Rightarrow{/tex} a = -(8 - 5)5 + 10 = -15 + 10 = -5
Hence, k = 5 and a = -5

ANSWER

10x - 10y=52

Posted by Yash Ameriya 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 4 months ago

X=52/10+Y

ANSWER

0.5is even no. or odd no

Posted by Kuldeep Kuldeep Pal 7 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

The Devil Prince 7 years, 4 months ago

It is none of them because only whole numbers can be classified as even or odd. ?????

Kaushiki Singh 7 years, 4 months ago

Odd no.??

Alpna Suthar 7 years, 4 months ago

Odd

ANSWER

The degree of polynomial is _________________

Posted by Raja Yadav 7 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Elsa B 7 years, 4 months ago

Wow what a answer!!!

Rajat Ranjan 7 years, 4 months ago

The Degree (for a polynomial with one variable, like <i>x</i>) is:

the <a href="https://www.mathsisfun.com/exponent.html">largest exponent</a> of that variable.

ANSWER

X square + 5 x minus bracket a square plus b minus 6 is equal to zero

Posted by Bhanu Pratap Pratap 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Nisha Sangwan 7 years, 4 months ago

Write full questions whether we prove it or find value of anyone in this

ANSWER

Draw a flow chart on quadratic equations

Posted by Divya Borra 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 4 months ago

But how on here?

ANSWER

If m power n =32where m and n are positive integer then the value of m power m n is

Posted by Ankush Singh 7 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find 7429 prime factories

Posted by Dhara Singh Meena 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Govind Agrawal ??? 7 years, 4 months ago

17×19×23 are the prime factors of 7429

ANSWER

Find tha quadratic polynomial,sum of whose zeros is 8 and their product is 12 .Hence,find the zeros of polynomial.

Posted by Kundan Kumar 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Rahul Kumar 7 years, 4 months ago

Let the first zero is x And.other is 8-x (x)(8-x)=12

ANSWER

Determine the roots solution of the following equation using quadrate discriminant formula x+4 by 1 - x-7 by 1 = 11by 30 x = 4,7

Posted by Niktar Razza 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Niktar Razza 7 years, 4 months ago

Kya

ANSWER

2x square -x+1by 8= 0

Posted by Salman Khan 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 4 months ago

X=1/4,1/4

ANSWER

Find the roots of equation 1\x+4-1/x-7=11/30

Posted by Ayush Karagwal 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

{tex}\frac { 1 } { x + 4 } - \frac { 1 } { x - 7 } = \frac { 11 } { 30 }{/tex} where {tex}x \neq - 4,7{/tex}
{tex}\Rightarrow \frac { ( x - 7 ) - ( x + 4 ) } { ( x + 4 ) ( x - 7 ) } = \frac { 11 } { 30 }{/tex}
{tex}\Rightarrow \frac { - 11 } { ( x + 4 ) ( x - 7 ) } = \frac { 11 } { 30 }{/tex}
{tex}\Rightarrow{/tex} x²- 7x + 4x - 28 = -30
{tex}\Rightarrow{/tex} x² - 3x + 2= 0
Comparing equation x²- 3x + 2 = 0 with general form ax² + bx + c = 0,
We get a = 1, b = -3 and c = 2
Using quadratic formula {tex}x = {-b \pm \sqrt{b^2-4ac} \over 2a}{/tex}to solve equation,
{tex}x = \frac { 3 \pm \sqrt { ( - 3 ) ^ { 2 } - 4 ( 1 ) ( 2 ) } } { 2 \times 1 }{/tex}
{tex}\Rightarrow x = \frac { 3 \pm \sqrt { 1 } } { 2 }{/tex}
{tex}\Rightarrow x = \frac { 3 + \sqrt { 1 } } { 2 } , \frac { 3 - \sqrt { 1 } } { 2 }{/tex} {tex}\Rightarrow{/tex} x = 2, 1

ANSWER

S12=3(S8-S4) prove that

Posted by Abhay Raj 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Varun Biban 7 years, 4 months ago

varun

ANSWER

Hey can any one is of kv near korba

Posted by Shikayna Panday 7 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Shikayna Panday 7 years, 4 months ago

Ok fine

Elsa B 7 years, 4 months ago

Hi I am from KV but not korba.??

Shikayna Panday 7 years, 4 months ago

Hiii to all

ANSWER

Ask question

Posted by Harjot Kaur 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Kaushiki Singh 7 years, 4 months ago

What u mean?

ANSWER

Polynominals

Posted by Ramireddy Vyshanvi 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Ramireddy Vyshanvi 7 years, 4 months ago

2(4999)0+99988

ANSWER

Two cubes each two cubes each of volume 64 CM cubic are joined end to end find the surface area of the resulting cuboid

Posted by Meraj Khan 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Shikhar Maheshwari 7 years, 4 months ago

First area of cube=64cm^3. a^3=64 a=8 As two cubes are joined so length will be 2*8. Breadth will be 8 and height will be 8. Now apply TSA=2(lb+bh+hl) Surface area = 640cm cubic

ANSWER

Find the value of k. 2× x - 4× y + 5=0 and k × x -3× y -5=0. By using substitution method

Posted by Kavish Gumber 7 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Formula of isosceles triangle

Posted by Jujhar Singh 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Maitreyee Dave 7 years, 4 months ago

b/4 √4a²-b²

ANSWER

Prove that underroot3 is a irrational no

Posted by Naina Chauhan 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Maitreyee Dave 7 years, 4 months ago

Let √3 be rational no. Then it exist in the form p/q where q≠0 √3=p/q. (here slash means upon) (on squaring both side) (√3)²= (p/q)² 3=p²/q² q²=p²/3. -------(1) From (1) we noticed that p² is divisible by 3 therefore p is also divisible by 3 -----(2) Now put p=3r in (1) Therefore q²= (3r)²/3 So, q²= 9r²/3 q²= 3r² (÷3) q²/3= r² OR r²= q²/3-----(3) From (3) we noticed that q² is divisible by 3 therefore q is also divisible by 3 ------(4) So by (2) & (4) it contradicts our suppose that √3 is rational but it is irrational because both p and q are divisible by 3 Hence proved

ANSWER

If the sun's angle of elevation is 60° and height of the pole is 9√3 m, then find the lenght of the shadow

Posted by Amatullah Baroda 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Shikhar Maheshwari 7 years, 4 months ago

Sun's elevation is 60° i.e base angle =60° Height 9√3 m Tan60=p/b √3=9√3/b b=9 m( length of shadow)

ANSWER

What is meant by web page

Posted by Ashish Sen 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Anirudh Dabas 7 years, 4 months ago

A hypertext document connected to world wide web

ANSWER

3×2

Posted by Abhishek Deswal 5 years, 8 months ago

CBSE > Class 10 > Mathematics

6 answers

Janani Srinivasan 7 years, 4 months ago

6

Kaushiki Singh 7 years, 4 months ago

6????

Anwaya Kumar Nayak 7 years, 4 months ago

6

Vaishnavi K R 7 years, 4 months ago

6

Elsa B 7 years, 4 months ago

6

Abhishek Deswal 7 years, 4 months ago

6

ANSWER

Page 1027 of 1971

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Google Play

Download myCBSEguide App