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ANSWER

Kx(3x-1) + 25 find the value ofk

Posted by Himanshu Setia 7 years, 3 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Prove that 3+2√5 is irrational

Posted by Bhavya Taparia 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Mitali Sabale 7 years, 4 months ago

Let us assume ,to the contrary that 3+2√5 is rational. That is , we can find coprimr a&b (b not equal to 0) such that 3+2√5=a/b 2√5=a/b 2√5=a/b - 3/1 2√5=a-3b/b Ir not equal to R 3+2√5= Irrational .

ANSWER

Find the area of the sector of the circle of radius 5cm if the corresponding arc length is 3.5cm.

Posted by Bhavya Taparia 7 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Mitali Sabale 7 years, 4 months ago

Working plz

Shiva Yadav Shiva Yadav 7 years, 4 months ago

8.75cm^2

ANSWER

In fig the sides AB,BC and CA of ABC touches the circle at P,Q,R respectively.If PA=4,BP=3 AC=11.FIND BC

Posted by Sahil Mandavkar 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

In triangle ABC, we have
BP = BQ = 3cm
AP = AR = 4cm
(tangents drawn from an external point to the circle are equal).
So, RC = AC - AR
= 11 - 4
= 7 cm
Hence RC = CQ = 7 cm
Then, BC = BQ + QC
= 7 + 3
= 10 cm

ANSWER

7.1 ka 3 q

Posted by Sunny Shing 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Kushal Jain 7 years, 4 months ago

We are given three points A(1,5),B(2,3) and C(-2,-11). We will find distance of AB BC AND CA and WE WILL CHECK THAT if AB +BC=CA.. SO DISTANCE OF AB =root 5.BC=4. CA=3root5.. So,AB+BC IS NOT EQUAL TO CA 4+ROOT5not equal to 3 root5 hence these points are not collinear... ***********Thank. You *************..::

ANSWER

Find two numbers such that the sum of twice the first and thrice the second is 92 and 4 times the first exceeds 7 times the second by 2

Posted by Rahul Yaduvanshi 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Suppose the first and second number be x and y respectively.
According to the question,
{tex}2x + 3y = 92{/tex} .......(i)
{tex}4x - 7y = 2{/tex} .......(ii)
Multiplying equation (i) by 7 and (ii) by 3,
{tex}\Rightarrow 14x + 21y = 644{/tex} .......(iii)
{tex}12x - 21y = 6{/tex} .........(iv)
Adding equations (iii) and (iv),
{tex}\Rightarrow 26x = 650{/tex}
{tex}\Rightarrow x = \frac { 650 } { 26 } = 25{/tex}
Putting {tex}x = 25{/tex} in equation (i),
{tex}\Rightarrow 2 \times 25 + 3 y = 92{/tex}
{tex}\Rightarrow50 + 3y = 92{/tex}
{tex}\Rightarrow 3 y = 92 - 50{/tex}
{tex}y = \frac { 42 } { 3 } = 14{/tex}
y = 14
{tex}\therefore{/tex} the first number is 25 and second is 14

ANSWER

Jklm is a square with sides of length 6unit . Point A and B are the midpoint of side kl and lm respectively. If a point is selected at random from the interior of the square . What is probability that the point will be chosen from the interior of ∆ jab

Posted by Ankush Garg 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Side of square {tex}= 6\ units{/tex}
Since A and B are the mid-point of KL and LM,
{tex}KA = AL = LB =BM = 3 units{/tex}
{tex}\therefore{/tex}Area of square = {tex}6 \times 6 = 36\ sq. units{/tex}
Area of {tex}\triangle{/tex}AJB = area of square - area of {tex}\triangle{/tex}AKJ - area of {tex}\triangle{/tex}BMJ - Area of {tex}\triangle ALB{/tex}
=36 - {tex}\frac{1}{2}{/tex} {tex}\times{/tex} 6 {tex}\times{/tex} 3 - {tex}\frac{1}{2}{/tex} {tex}\times{/tex} 3 {tex}\times{/tex} 3 - {tex}\frac{1}{2}{/tex} {tex}\times{/tex}6 {tex}\times{/tex}3
={tex}36 - 9 - 4.5 - 9{/tex}
={tex}13.5\ square\ units{/tex}
Probability that the point will be chosen from the interior of {tex}\triangle{/tex}AJB {tex}= \frac { \text { Area } \Delta J A B } { \text { Area of square } }{/tex} = {tex}\frac{13.5}{36}{/tex} = {tex}\frac{135}{360}{/tex}= {tex}\frac{3}{8}{/tex}.

ANSWER

Basic concepts of traingle

Posted by Abhishek Kumar 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Check notes from here : <a href="https://mycbseguide.com/cbse-revision-notes.html">https://mycbseguide.com/cbse-revision-notes.html</a>

ANSWER

I need MCQ worksheet

Posted by Nilesh Patil 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Likhitha Jayaram Likhitha 7 years, 4 months ago

Sorry cant be posted

4Thank You

ANSWER

Which term of the AP 3,15,27,34....will be 132 more than it's 54th term ?

Posted by Ayushi Kandpal 7 years, 4 months ago

CBSE > Class 10 > Mathematics

3 answers

Ayushi Kandpal 7 years, 3 months ago

Anyone can solve this question for me... ??

Ayushi Kandpal 7 years, 3 months ago

But kanika 34 - 27 =7 hota h....common difference same nhi aata hai...

Kanika Chauhan 7 years, 4 months ago

a54=639 an=132 639+132=771 65th term is132 more than its 54th term

ANSWER

Proof root 3 irrational??? N plzzz explain it to me clearly with all steps and appropriate explanation?????

Posted by Sankalp Awasthi 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Supriya Tiwari 7 years, 4 months ago

Let us assume that √3 is rational So we can write √3 =a/b where b is not equal to 0 and a and b are co primes On squaring both sides we get 3 =a^2 /b^2 a^2=3b^2 (i) a^2 is divisible by 3 so a is divisible by 3 So we can write a= 3c for any integer c a^2 =9c^2 (ii ) From i and ii we get 3b^2 = 9c^2 b^2= 3c^2 b^ 2 is divisible by 3 so b is divisible by 3 Therefore a and b have atleast 3 as a common factor but this contradicts the fact that a and b have no common factor other than 1 This contradiction has arisen because of our wrong assumption that √3 is rational So we conclude that √3 is irrational.

5Thank You

ANSWER

8.4 9

Posted by Pinki Jayant 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Anjali Pal 7 years, 4 months ago

Which book

ANSWER

Define Thales theorem

Posted by Imran Malik 7 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Sneha Misra 7 years, 4 months ago

If a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points,the other two sides are divided in the same ratio. MAY THIS HELP U MY FRND!!!!!?

Shiva Yadav Shiva Yadav 7 years, 4 months ago

When a line cut the opposite two sides of the triangle which is parallel to the third side is divide the lines in the same ratio

ANSWER

find the value of p for which the numbers 2p-1,3p+4,11 are in AP. Hence,find the numbers

Posted by Faisal Warsi 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Supriya Tiwari 7 years, 4 months ago

3p+4 -2p +1=11-3p-4 ( common difference is same ) p+5=7-3p 4p=2 p= 1/2

ANSWER

If sinA + 2× cosA =1 prove that 2sinA -cosA

Posted by Abhishek Kumar 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Adarsh Singh 7 years, 4 months ago

2sinA-cosA=2

ANSWER

Please make me understand about arithmetic progression

Posted by Zahira Malik 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Anil Kumar Shakya 7 years, 4 months ago

AP means a sequence in which each term differs from its preceding term by a constant.

3Thank You

ANSWER

If tan(a-b)=not defined and tan(a+b)=1/^3 find the value of a and b

Posted by Abhishek Sharma 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Adarsh Singh 7 years, 4 months ago

b=30 and a=60

ANSWER

The sum of first 'q' terms of an A.P is 162. The ratio of its 6th term to its 13th term is 1:2. Find the first and 15th term of the A.P.

Posted by Zin Chaibask 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Let us suppose that 'a' be the first term and 'd' be the common difference of the A.P.
Now according to question it is given that

S₉ = 162.

Using formula for sum to n terms of A.P, we have
{tex}\Rightarrow \frac{9}{2}\left[ {2a + (9 - 1)d} \right] = 162{/tex}
{tex} \Rightarrow \frac{9}{2}\left[ {2a + 8d} \right] = 162{/tex}
{tex}\Rightarrow{/tex} 9a + 36d = 162 ........................(i)
Let a₆ and a₁₃ be the 6^_th and 13^th term of the A.P. respectively.
Therefore, using general form of nth term, we have,a₆ = a + 5d and a₁₃ = a + 12d
Since, {tex}\frac{{{a_6}}}{{{a_{13}}}} = \frac{1}{2}{/tex}
{tex} \Rightarrow \frac{{a + 5d}}{{a + 12d}} = \frac{1}{2}{/tex}
{tex}\Rightarrow{/tex} 2a + 10d = a + 12d
{tex}\Rightarrow{/tex} a = 2d
Now,substituting the value of a = 2d in equation (i), we get,
9(2d) + 36d = 162
{tex}\Rightarrow{/tex} 18d + 36d = 162
{tex}\Rightarrow{/tex} 54d = 162
{tex}\Rightarrow{/tex} d = 3
{tex}\Rightarrow{/tex} a = 2d = 2 {tex}\times{/tex} 3 = 6 = First term

Therefore, 15th term=a+14d=6+14(3)=48

ANSWER

Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°

Posted by Dablu Kumar 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Shiva Yadav Shiva Yadav 7 years, 4 months ago

18.8cm^2

ANSWER

a=5 ,d=2

Posted by Riya Garg 7 years, 4 months ago

CBSE > Class 10 > Mathematics

2 answers

Soham Deshpande 7 years, 4 months ago

What to find

Riya Garg 7 years, 4 months ago

367

ANSWER

If sn denotes the sum of n terms of an AP whose common difference is d and first term is a find sn_2sn_1+sn_2

Posted by Suchitra Suchi 7 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If sum of the squares of zereos of quadratic polynomial f(x)= x2- 8x+k is 40 . Find the value of k

Posted by Mohammad Danish 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Supriya Tiwari 7 years, 4 months ago

α+β=8 αβ=k α^2+β^2=40 (α+β)^2-2αβ =40 8^2-2k=40 64 -2k =40 -2k =40-64 -2k =-24 k=12

ANSWER

How many types of formula for coordinate geometery

Posted by Sarama Mondal 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sarama Mondal 7 years, 4 months ago

6 types of formula they are:1. A-b distance formula 2: midpoint formula 3: intersection formula 4: centroid formula 5: area of triangle ABC 6: 3 points are collinear

ANSWER

Euclid s divion lemma

Posted by Rakesh Raushan 7 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Jassi Midha 7 years, 4 months ago

a=bq+r<=0

ANSWER

Ghjg

Posted by Gaurang Dosar 7 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

If(p-x)and (q-1/2) is factor of px^2+5x+q..find p/q=??

Posted by Mayank Srivastava 7 years, 4 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

A person invested some amount at the rate of 12% simple interest and some other amount at the rate of 10% simple interest. He received yearly interest of Rs. 130. But, if he had interchanged the amounts invested, he would have received Rs. 4 more as interest. How much amount did he invest at different rates?

Posted by Aksha Aksha Memon 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Suppose that he invested ₹ x at the rate of 12% simple interest and ₹ y at the rate 10% simple interest.
Then, according to the question,{tex}\frac{12x}{{100}} + \frac{{10y}}{{100}} = 130{/tex}
{tex}\Rightarrow {/tex} 12x+10y=13000 ..........Dividing throughout by 2
{tex}\Rightarrow {/tex} 6x+5y=6500 .......(1)
and,{tex}\frac{{12y}}{{100}} + \frac{{10x}}{{100}} = 134 {/tex}
{tex}\Rightarrow {/tex} 12y+10x=13400
{tex}\Rightarrow {/tex} 6y+5x=6700 .............Dividing through by 2
{tex}\Rightarrow {/tex} 5x+6y=6700 ...........(2)

Multiplying equation (1) by 6 and equation (2) by 5, we get
36x+30y=39000 ...............(3)
25x+30y=33500 .......(4)
{tex}\Rightarrow {/tex}subtracting (3) and (4) we get x = 500
Substituting this value of x in equation (1), we get 6(500)+5y=6500
{tex}\Rightarrow {/tex} 3000+5y=6500
{tex}\Rightarrow {/tex} 5y=6500-3000
{tex}\Rightarrow {/tex} 5y=3500
{tex}\Rightarrow {/tex} {tex}y = \frac{{3500}}{5} = 700{/tex}

So, the solution of the equation (1) and (2) is x=500 and y=700
Hence, he invested ₹ 500 at the rate of 12% simple interest and ₹ 700 at the rate of 10% simple interest.
verification.Substituting x=500, y=700,
We find that both the equation (1) and (2) are satisfied as shown below:
6x + 5y=6(500)+5(700)=3000+3500=6500
5x+6y=5(500)+6(700)=2500+4200=6700
This verifies the solution.