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Ask QuestionPosted by Tejas Kamble 8 years, 3 months ago
- 1 answers
Posted by Riya Agrawal 8 years, 3 months ago
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Posted by Tanya Bhardwaj 8 years, 3 months ago
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Posted by Shyam Kumar 8 years, 3 months ago
- 2 answers
Soumya Ghoshal 8 years, 3 months ago
If we write,{tex}3=\frac{{30}}{10}{/tex}
and {tex}4= \frac{{40}}{10}{/tex}
Then, we can easily find the number between them. Which are,
{tex}\frac{{31}}{10},\frac{{32}}{10},\frac{{33}}{10},\frac{{35}}{10},\frac{{36}}{10},\frac{{38}}{10}{/tex}
Posted by Prasant Dash 8 years, 3 months ago
- 1 answers
Soumya Ghoshal 8 years, 3 months ago
{tex}125^5=\frac{{1}}{25}^x{/tex}
or, {tex}5^{3×5}=(5²)^{-x}{/tex}
or,{tex}5^{15}=5^{-2x}{/tex}
or,15{tex}=-2x{/tex}
or,{tex}x = -\frac{{15}}{2}{/tex}
Posted by Nithish Nithish 8 years, 3 months ago
- 1 answers
Sahdev Sharma 8 years, 3 months ago
Let a,b,c be the sides of the triangle. Perimeter 2s = a + b + c
Semi-perimeter, s ={tex} a+b+c\over 2{/tex}
Using Heron's formula: Area of the triangle A = {tex}\sqrt {s(s−a)(s−b)(s−c) }{/tex}
Now, if the sides are doubled: 2a, 2b, 2c Let s' be the semi-perimeter.
2s' = 2a + 2b + 2c
s' = a + b + c or s' = 2s
Area of the triangle,
A' = {tex}\sqrt {s′(s′−2a)(s′−2b)(s′−2c) }{/tex}
A' = {tex} \sqrt {(2s)(2s−2a)(2s−2b)(2s−2c)}{/tex}
A'= {tex}\sqrt {16s(s−a)(s−b)(s−c) }{/tex}
A' ={tex} 4\sqrt {s(s−a)(s−b)(s−c) }{/tex}
A' = 4A
A':A = 4:1
Ratio of area of the new triangle and old triangle is 4:1
Posted by Sahil Mandal 8 years, 3 months ago
- 2 answers
Posted by Divyanshu Tiwari 8 years, 3 months ago
- 1 answers
Payal Singh 8 years, 3 months ago
A simple fraction (also known as a common fraction or vulgar fraction) is a rational number written as a/b or {tex}\frac ab {/tex} where a and b are both integers.
Posted by Mayan Chandra 8 years, 3 months ago
- 1 answers
Rashmi Bajpayee 8 years, 3 months ago
Third side of given triangle = 240 - (78 + 50) = 240 - 128 = 112 dm
Semiperimeter of triangle (s) = {tex}{{240} \over 2}{/tex} = 120 dm
Now, Area of triangle = {tex}\sqrt {s\left( {s - a} \right)\left( {s - b} \right)\left( {s - c} \right)} {/tex}
= {tex}\sqrt {120\left( {120 - 78} \right)\left( {120 - 50} \right)\left( {120 - 112} \right)} {/tex}
= {tex}\sqrt {120 \times 42 \times 70 \times 8} {/tex}
= {tex}\sqrt {10 \times 10 \times 7 \times 7 \times 6 \times 6 \times 4 \times 4} {/tex}
= 10 x 7 x 6 x 4
= 1680 sq. dm
Now, again Area of triangle = {tex}{1 \over 2}{/tex}x Base x Height (Perpendicular)
=> 1680 = {tex}{1 \over 2}{/tex}x 50 x Perpendicular
=> Perpendicular = {tex}{{1680 \times 2} \over {50}}{/tex}
=> Perpendicular = 67.2 dm
Posted by Mohammad Qasib Ali 8 years, 3 months ago
- 1 answers
Posted by Shubh Shubh 8 years, 3 months ago
- 0 answers
Posted by Yash Dhoka 8 years, 3 months ago
- 1 answers
Hans Raj 8 years, 3 months ago
x3 + x2 + x + 1
= x2 (x + 1 ) + 1 (x + 1)
= (x + 1)(x2 + 1)
Posted by Arvind Kumar 8 years, 3 months ago
- 2 answers
Posted by Sumit Sarkar 8 years, 3 months ago
- 2 answers
Rashmi Bajpayee 8 years, 3 months ago
{tex}a + b = {a \over b} + {b \over a}{/tex}
=> {tex}a + b = {{{a^2} + {b^2}} \over {ab}}{/tex}
=> {tex}{a^2} + {b^2} = ab\left( {a + b} \right){/tex}
Hans Raj 8 years, 3 months ago
a + b = a/b + b/a
squaring both sides
a2 + b2 + 2ab = a2/b2 + b2/a2 + 2
a2 + b2 = a2/b2 + b2/a2 + 2 - 2ab
Posted by Sumit Sarkar 8 years, 3 months ago
- 1 answers
Soumya Ghoshal 8 years, 3 months ago
{tex}a+b=\frac{{a}}{b}+\frac{{b}}{a}{/tex}
or, {tex}a+b=\frac{{a^2+b^2}}{ab}{/tex}
or, {tex}ab(a+b)=a^2+b^2{/tex}
or, {tex}a^2+b^2=a^2b+ab^2{/tex}
Posted by Azib . 8 years, 3 months ago
- 2 answers
Rashmi Bajpayee 8 years, 3 months ago
If (x - 1) is a factor of p(x), then
p(1) = 0
=> 12 + 1 + k = 0
=> 1 + 1 + k = 0
=> 2 + k = 0
=> k = -2
Posted by Dilpreet Kaur 8 years, 3 months ago
- 1 answers
Shantanu Tandale 8 years, 3 months ago
Posted by Karan Singh 8 years, 3 months ago
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बेबि बीच 8 years, 3 months ago
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Posted by Ujjwal Sharma 8 years, 3 months ago
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Posted by Patel Heli K 8 years, 3 months ago
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Aman Kumar 8 years, 3 months ago
Posted by Harsh Gupta 8 years, 3 months ago
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Posted by Bidya Sagar 8 years, 3 months ago
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Posted by Ayush Kumar 8 years, 3 months ago
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Posted by Lovleen Brar 8 years, 3 months ago
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Minakshi Kapoor 8 years, 3 months ago
the area is the region covered by the closed plane figure, the volume is the amount of space occupied by an object
|
<th>Basis for comparison</th>
|
Area | Volume | |
| 1. Meaning | Area refers to the region or space of the plane figure or object |
Volume refers to the quantity of space contained by an object. |
|
| 2.Shapes | Plane figures | Solids | |
3.
|
Square unit | Cubic unit |
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Soumya Ghoshal 8 years, 3 months ago
A digit is a numeric symbol used in combinations to represent numbers in positional numeral systems.
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