Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Saurabh Srivastava 8 years, 5 months ago
- 2 answers
Posted by Shraddha J 8 years, 5 months ago
- 0 answers
Posted by Nikita Thakuri 8 years, 5 months ago
- 2 answers
Shraddha J 8 years, 5 months ago
Posted by Vanya Mudgil 8 years, 5 months ago
- 0 answers
Posted by Laxmi Pant 8 years, 5 months ago
- 0 answers
Posted by Mayank Singhal 8 years, 5 months ago
- 1 answers
Posted by Vanya Mudgil 8 years, 5 months ago
- 0 answers
Posted by Krishna Mishra 8 years, 5 months ago
- 1 answers
Posted by Hargundeep Sandhu 8 years, 5 months ago
- 1 answers
Om Zankat 8 years, 5 months ago
Posted by Bhartendu Vibhu 8 years, 5 months ago
- 1 answers
Posted by Jensi. C Jensi 8 years, 5 months ago
- 1 answers
Amar Kumar 8 years, 5 months ago
{tex}\eqalign{ & {\left( {x - {1 \over x}} \right)^2} = {x^2} + {1 \over {{x^2}}} - 2x{1 \over x} \cr & \left( {x - {1 \over x}} \right) = \sqrt {18 - 2} \cr & \left( {x - {1 \over x}} \right) = 4 \cr & {x^3} - {1 \over {{x^3}}} = \left( {x - {1 \over x}} \right)\left( {{x^2} + 1 + {1 \over {{x^2}}}} \right) \cr} {/tex}
=4(18+1)
=76
Posted by Jensi. C Jensi 8 years, 5 months ago
- 0 answers
Posted by Gurpreet Singh 8 years, 5 months ago
- 0 answers
Posted by Vaishali Marskole 8 years, 5 months ago
- 2 answers
Amar Kumar 8 years, 5 months ago
Whole numbers are positive numbers, including zero, without any decimal or fractional parts. They are numbers that represent whole things without pieces. The examples of whole numbers are 0, 1, 2, 3, 4, 5.
Rising Angel 8 years, 5 months ago
Posted by Mini Singhal 8 years, 5 months ago
- 0 answers
Posted by Happy Kaushik 8 years, 5 months ago
- 0 answers
Posted by Shwetha Lachu 8 years, 5 months ago
- 0 answers
Posted by Tarun Rana 8 years, 5 months ago
- 0 answers
Posted by Pari Mishra 4 years, 9 months ago
- 1 answers
Sia ? 4 years, 9 months ago
Posted by Aman Kumar 8 years, 5 months ago
- 1 answers
Posted by Anurag Verma 8 years, 5 months ago
- 1 answers
Rahul Sharma 8 years, 2 months ago
Given:
(1) ABCD is a parallelogram.
(2) BE = 2EA
(3) DF = 2FC
To prove: AECF is a parallelogram. whose area is one third the area of parallelogram ABCD.
Construction: Draw AL
DC
Proof: ABCD is a parallelogram.
Therefore, ABDC
Since E and F are points on AB and DC respectively,
AEFC
AB = EA + BE
= EA + 2EA [BE = 2EA]
= 3EA
AE = 
AB (i)
DC = DF + FC
= 2FC + FC [DF = 2 FC]
= 3FC
FC = 
DC (ii)
Since AB = DC (parallel sides of the parallelogram), from (i) and (ii), we have,
AE = FC
Thus, AE = FC and AEFC
AFEC
Therefore, AEFC is a parallelogram.
Now, since AECF and ABCD lie between the same parallel lines, their heights are also equal.
Therefore, area (parallelogram AECF) = FC 
AL
= 
DC 
AL
= 
[area (parallelogram ABCD)]
Posted by Khushnuda Tasmeer 8 years, 5 months ago
- 1 answers
Posted by Nimit Garg 8 years, 5 months ago
- 2 answers
Amar Kumar 8 years, 5 months ago
X+t =4
4 (2x+2t )=4x2(x+t)
4 (2x+2t )=4x2(4)
4 (2x+2t )=32
Posted by Christiano Ronaldo 8 years, 5 months ago
- 2 answers
Posted by Shiva Hello 8 years, 5 months ago
- 0 answers
Posted by #Aditi~ Angel???? 8 years, 5 months ago
- 2 answers
Posted by Ashwani T 8 years, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Shraddha J 8 years, 5 months ago
1Thank You