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Amar Kumar 8 years, 5 months ago
{tex}\eqalign{ & Area\,of\,triangle = {1 \over 2} \times base \times height \cr & A = {1 \over 2} \times 16 \times h \cr & A = 8 \times h \cr & \cr} {/tex}
Given that: equal sides are 10cm. each
As we know that height of an isoseles triangle divides it into two right angle triangles so using Pythogorus theorem we can calculate the height of isoseles triangle
base of right angle triangle=8 cm.
hypo=10
h2=102-82
h=6cm.
so A=8x6
A=48cm2
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Hans Raj 8 years, 5 months ago
let ABC is a rt Ld tri
AC=10
BC= 6
AB=X
AC2=AB2+BC2
100=36 + AB2
AB2=64
AB=8
Area=1/2 x base x height
= 1/2 x 6 x 8 = 24 cm2
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