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Ask QuestionPosted by Pyda Srinivas 8 years, 5 months ago
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Posted by Lakshmi Parvathi 8 years, 5 months ago
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Posted by Prince Rohilla 8 years, 5 months ago
- 2 answers
Hans Raj 8 years, 5 months ago
first of all let us make the denominator equal in both by multiplying 1/4 by 3/3 , and 2/3 by 4/4 to get equal denominator i.e. 12
1/4x3/3 = 1x3 / 4x3 = 3/12
2/3x4/4= 2x4 / 3x4 = 8/12
now rational nos between 1/4 and 2/3 or between 3/12 and 8/12 are 4/12 , 5/12 , 6/12 , 7/12
Remember Rule = Look at the denominators , think the method by which they can be made equal ............. by multiplying numerator and denominator by same number i.e. by 3/3 and 4/4 in this case
Posted by Lucky Ikhar 8 years, 5 months ago
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Posted by Ansh Sharma 8 years, 5 months ago
- 1 answers
Hans Raj 8 years, 5 months ago
let ABC is a an equilateral triangle with side AB=BC=CA= X
and AD = altitude = 3 root 3
AD is perpendicular to BC and BD=DC=X/2
Also ABD is a right Ld triangle with AB=X , BD=X/2 , AD= 3 root 3
AB2 = BD2 + AD2
X2 = (X/2)2 + (3ROOT3)2
3/4 X2= 9X3
X2=36
X=6
AREA=1/2 X BASE X HEIGHT
= 1/2 x BC x AD
= 1/2 x Xx 3root3
= 1/2 x 6 x 3root3
= 9 root3 cm2
Check ur answer by HERON'S RULE s=6+6+6/2 = 9 , area = root 9(9-6)(9-6)(9-6) = root 9x3x3x3 = 9root3 ok r u happy
Posted by Satish Yadav 8 years, 5 months ago
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Posted by Harsha Mallesh Mallesh 8 years, 5 months ago
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Posted by Rifat Jamali 8 years, 5 months ago
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Posted by Grenvel Crasta 8 years, 5 months ago
- 1 answers
Posted by Om Zankat 8 years, 5 months ago
- 1 answers
Posted by Grenvel Crasta 8 years, 5 months ago
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Posted by Grenvel Crasta 8 years, 5 months ago
- 1 answers
Amar Kumar 8 years, 5 months ago
{tex}\eqalign{ & {x^3} - {\left( {{1 \over x}} \right)^3} = {\left( {x - {1 \over x}} \right)^3} + 3x \times {1 \over x}\left( {x - {1 \over x}} \right) \cr & = {3^3} + 3(3) \cr & = 27 - 9 \cr & = 18 \cr & \cr} {/tex}
Posted by Grenvel Crasta 8 years, 5 months ago
- 1 answers
Amar Kumar 8 years, 5 months ago
(x+y+z)2=x2+y2+z2+2xy+2yz+2zx
122=64+2(xy+yz+zx)
144-64=2(xy+yz+zx)
80=2(xy+yz+zx)
xy+yz+zx=40
Posted by Grenvel Crasta 8 years, 5 months ago
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Posted by Grenvel Crasta 8 years, 5 months ago
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Posted by Grenvel Crasta 8 years, 5 months ago
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Posted by Lakshmi Parvathi 8 years, 5 months ago
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Posted by Pranav Kaul 8 years, 5 months ago
- 1 answers
Amar Kumar 8 years, 5 months ago
a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)
a3+b3+c3-3abc=(12)(90-(ab+bc+ca)) eq.(1)
(a+b+c)2 =a2+b2+c2+2ab+2bc+2ca
2ab+2bc+2ca=(a+b+c)2 -(a2+b2+c2)
2(ab+bc+ca)=122-90
2(ab+bc+ca)=144-90
ab+bc+ca=27 eq.(2)
put value of (2) in (1)
a3+b3+c3-3abc=12(90-27)
a3+b3+c3-3abc=756
Posted by Pranav Sharma 8 years, 5 months ago
- 1 answers
Posted by Pranav Sharma 8 years, 5 months ago
- 1 answers
Posted by #Geetika Gupta 8 years, 5 months ago
- 3 answers
Posted by Krishna Soni 8 years, 5 months ago
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Posted by Sharad Patkar 8 years, 5 months ago
- 1 answers
Amar Kumar 8 years, 5 months ago
When two lines are crossed by another line (called the Transversal): The pairs of angles on opposite sides of the transversal but inside the two lines are called Alternate Interior Angles.
Posted by Azra Siddiqui 8 years, 5 months ago
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Posted by Mehakpreet Singh 8 years, 5 months ago
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Posted by Dhiraj Kumar 8 years, 5 months ago
- 2 answers
Amar Kumar 8 years, 5 months ago
Circle is the locus of points equidistant from a given point, the center of the circle. The common distance from the center of the circle to its points is called radius. Thus a circle is completely defined by its center (O) and radius (R). It is a two dimensional shape.
Posted by Shashank S G 8 years, 5 months ago
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Posted by Archita Archita 8 years, 5 months ago
- 3 answers
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