No products in the cart.

Ask questions which are clear, concise and easy to understand.

Ask Question
  • 0 answers
  • 3 answers

Sneha Sneha 8 years, 3 months ago

So now, area of rhombus = 1/2* d1*d2 therefore, 1/2*30*40= 600sq cm

Sneha Sneha 8 years, 3 months ago

Firstly, we know that all sides of a rhombus are equal therefore it's perimeter = 100m so, it's one side = 100/4=25m one diagnol = 30m =30/2 =15m so by pythagorus theorem,we have =20m second diagnol = 2*20 =40m

Naveen Sharma 8 years, 3 months ago

Perimeter of Rhombus = 100 m
Side of Rhombus = {tex}{100\over 4}= 25 m {/tex}

One diagonal of Rhombus (d1) = 30 m
Second diagonal of rhombus = d2

As we know, diagonal of rhombus bisect each other at 90 degree. So,
{tex}​​​​​​​d_1^2+d_2^2= 4(side)^2\\ =>900 + d_2^2 = 4\times 625\\ => d_2^2 = 2500-900=1600\\ => d_2 = 40{/tex}

Area of rhombus = {tex}{1\over 2}\times d_1\times d_2\\ = {1\over 2}\times 30\times 40 \\ = 600 m^2{/tex}

 

 

 

  • 1 answers

Shubham Sharma 8 years, 3 months ago

1+1=2
  • 1 answers

Golua Singham 8 years, 3 months ago

Area of circle is πr^2
  • 1 answers

Golua Singham 8 years, 3 months ago

Yes of course you can put kink on y axis
  • 1 answers

Golua Singham 8 years, 3 months ago

Plz compete you question..........
  • 2 answers

Golua Singham 8 years, 3 months ago

I think you must see example 6 of chapter 10.........I hope you can get your answer

Varun Banda 8 years, 3 months ago

Given : Let ABCD is cyclic quadrilateral. 

To prove : ∠A + ∠C = 180° and ∠B + ∠D = 180°. 

Construction: join OB and OD.

Proof :

∠BOD = 2 ∠BAD ∠BAD = 1/2∠ BOD 

Similarly∠BCD = 1/2 ∠DOB ∠BAD + ∠BCD

= 1/2∠BOD + 1/2 ∠DOB

=1/2(∠ BOD + ∠DOB)

= (1/2)X360° = 180°

Similarly ∠B + ∠D = 180°

  • 1 answers

Golua Singham 8 years, 3 months ago

TSA=6(78)^2 =6(6084)=36504 LSA=4(78)^2 =4(6084)=24336
S
  • 0 answers
  • 1 answers

Siddharth Murali 8 years, 3 months ago

468
  • 1 answers

Shivam Malik 8 years, 3 months ago

First we have to divide it in two parts square root of 4 and square root of 3 then represent.
  • 1 answers

Alisha Akhtar 8 years, 3 months ago

8.9 is mid point theorem
  • 1 answers

Shivangi Singhal 8 years, 3 months ago

U can take help of rd sharma.
  • 1 answers

Golua Singham 8 years, 3 months ago

Sorry ,I think.......your question is wrong because in triangle a+b>c
  • 1 answers

Happy Sharma 8 years, 3 months ago

It is a type of graph in which data is arranged in the form of pictures.
  • 3 answers

Gautam Kumar 2 years, 8 months ago

Ya is it possible try again

Gautam Kumar 8 years, 3 months ago

Ya answer is a=3 b=4

Gunjan Kumar 8 years, 3 months ago

No it is not possible to find answer by using formula.but a=4 and b=3
  • 2 answers

Abhi Yadav 8 years, 3 months ago

Let 3:5:7 be x 3x+5x+7x=300m 15x=300 X=300/15 X=20 3x=3×20=60 5x=5×20=100 7x=7×20=140 ?

Golua Singham 8 years, 3 months ago

Let 3:5:7 be 3x ,5x,7x respectively 3x+5x+7x=300 15x=300 x=300/15 = 20 Hence, 3x=20×3=60 5x=20×5=100 7x=20×7=140
  • 1 answers

Saumya Pandey 8 years, 3 months ago

an oscillatory motion where restoring force is directly proportional to the displacement but acts in opp... direction of displacement
  • 1 answers

Golua Singham 8 years, 3 months ago

If each pair of opposite sides of a quadrilateral is equal ,then it is a parallelogram. Let a quadrilateral ABCD in which there is a diagonal AC. Now, AD=BC DC=AB AC=AC ∆ABC is congruent to ∆CDA By sss congruency criteria AngleBAC = angleDCA ( cpct) Hence, AngleBCA=angleDAC(alternate interior angle) Hence ABCD is a parallelogram
  • 1 answers

Golua Singham 8 years, 3 months ago

See.............I hope that you had studied mid point the pram according to it the line segment joining the mid points of two side of triangle is pareelel to the third side. In this case of trapezium the diagonal divides it in two triangles . Mid point of one diagonal of trapezium also bisects one side of trapezium,hence mid point of diagonal of trapezium is pareelel to the third side. It is becoming difficult to tell you it's answer but if you understand mid point their am well thank you can get its answer..
  • 1 answers

Surya S 8 years, 3 months ago

Sides are 16 cm,16 cm,16 cm Semi perimeter=a+b+c÷2 16+16+16÷2 48÷2=24 cm. Area of triangle=√s(s-a) (s-b) (s-c) √24(24-16)(24-16)(24-16) √24×8×8×8 √3×8×8×8×8 =64√3 cm2
  • 0 answers
  • 0 answers
  • 0 answers
  • 1 answers

Golua Singham 8 years, 3 months ago

∆ADC and ∆BDC lie on the same base DC and same paralles AB and CD Area(∆ADC)=Area(∆BDC) Subtracting DOC from both= Area(∆ADC)-Area(∆DOC)=Area(∆BDC)-Area(∆DOC) Area(∆AOD)=Area(∆BOD)
  • 0 answers
  • 1 answers

Suraj Prasad 8 years, 3 months ago

WX444P
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App