No products in the cart.

Find the area of rhombus whose …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Find the area of rhombus whose perimeter is 100m and one of whose diagonal is 30m
  • 3 answers

Sneha Sneha 6 years, 3 months ago

So now, area of rhombus = 1/2* d1*d2 therefore, 1/2*30*40= 600sq cm

Sneha Sneha 6 years, 3 months ago

Firstly, we know that all sides of a rhombus are equal therefore it's perimeter = 100m so, it's one side = 100/4=25m one diagnol = 30m =30/2 =15m so by pythagorus theorem,we have =20m second diagnol = 2*20 =40m

Naveen Sharma 6 years, 3 months ago

Perimeter of Rhombus = 100 m
Side of Rhombus = {tex}{100\over 4}= 25 m {/tex}

One diagonal of Rhombus (d1) = 30 m
Second diagonal of rhombus = d2

As we know, diagonal of rhombus bisect each other at 90 degree. So,
{tex}​​​​​​​d_1^2+d_2^2= 4(side)^2\\ =>900 + d_2^2 = 4\times 625\\ => d_2^2 = 2500-900=1600\\ => d_2 = 40{/tex}

Area of rhombus = {tex}{1\over 2}\times d_1\times d_2\\ = {1\over 2}\times 30\times 40 \\ = 600 m^2{/tex}

 

 

 

http://mycbseguide.com/examin8/

Related Questions

Why is line and angle are not equal
  • 0 answers
27²/³÷27¹/³×27-⁴/³
  • 0 answers
2+2(5)²
  • 2 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App