Find the area of rhombus whose …
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Posted by Kashish Taank 6 years, 3 months ago
- 3 answers
Sneha Sneha 6 years, 3 months ago
Naveen Sharma 6 years, 3 months ago
Perimeter of Rhombus = 100 m
Side of Rhombus = {tex}{100\over 4}= 25 m {/tex}
One diagonal of Rhombus (d1) = 30 m
Second diagonal of rhombus = d2
As we know, diagonal of rhombus bisect each other at 90 degree. So,
{tex}d_1^2+d_2^2= 4(side)^2\\
=>900 + d_2^2 = 4\times 625\\
=> d_2^2 = 2500-900=1600\\
=> d_2 = 40{/tex}
Area of rhombus = {tex}{1\over 2}\times d_1\times d_2\\ = {1\over 2}\times 30\times 40 \\ = 600 m^2{/tex}
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Sneha Sneha 6 years, 3 months ago
0Thank You