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  • 1 answers

Rashmi Mirchandani 1 year, 8 months ago

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  • 0 answers
  • 1 answers

Kunwar V.P Singh 1 year, 8 months ago

Where is your question???
  • 5 answers

Ayush Kumar 1 year, 8 months ago

I think are of equilateral triangle is more easy than herons formula

Rahul ._. 1 year, 8 months ago

Because area of equilateral triangle is √3/4a² so it is difficult

Rahul ._. 1 year, 8 months ago

I think we can use heron formula

Rahul ._. 1 year, 8 months ago

Itne tough humko nhi aate

Rahul ._. 1 year, 8 months ago

Sorry
  • 1 answers

Rahul ._. 1 year, 8 months ago

Simple first clear your concept from PW vedios then clear you congruency rule then try to attempt questions
  • 3 answers

Harsh Raj 1 year, 8 months ago

4

Smriti Gupta 1 year, 8 months ago

4

Daksh Shinde 1 year, 8 months ago

What is mean by surface
  • 1 answers

Preeti Dabral 1 year, 8 months ago

Here, a = 6 - √35

{tex}\begin{aligned} & \Rightarrow 1 / a=1 /(6-\sqrt{35}) \\ & \Rightarrow 1 / a=(6+\sqrt{35}) /[(6+\sqrt{35})(6-\sqrt{35})] \end{aligned}{/tex}

[By multiplying (6 + 35) in both numerator & denominator]

{tex}\begin{aligned} & \Rightarrow 1 / a=(6+\sqrt{35}) /\left(6^2-(\sqrt{35})^2\right) \\ & \Rightarrow 1 / a=(6+\sqrt{35})(36-35) \\ & \Rightarrow 1 / a=(6+\sqrt{35}) / 1 \\ & \Rightarrow 1 / a=6+\sqrt{35} \end{aligned}{/tex}

Now we have to find value of a² + 1/a²

{tex}\begin{aligned} & \Rightarrow a^2+1 / a^2=(a)^2+(1 / a)^2 \\ & \Rightarrow(6-\sqrt{ } 35)^2+(6+\sqrt{ } 35)^2 \\ & \Rightarrow\left(6^2-2 \times 6 \sqrt{35}+35\right)+\left(6^2+2 \times 6 \sqrt{35}+35\right) \\ & \Rightarrow 36-12 \sqrt{ } 35+35+36+12 \sqrt{ } 35+35 \\ & \Rightarrow 72+70 \\ & \Rightarrow 142 \end{aligned}{/tex}

  • 2 answers

Debayan Kar 1 year, 8 months ago

0.2 or 2/10, 1/4 are rational number

Vansh Sing 1 year, 8 months ago

O.2
  • 1 answers

Smriti Gupta 1 year, 8 months ago

16
  • 1 answers

Aditya D 1 year, 8 months ago

Length=22m Breadth=16m Area of rectangle= l×b =22×16=352m2 Cost of fencing=₹20.50 Cost = 352×20.50=₹7216 Ans
  • 2 answers

Smriti Gupta 1 year, 8 months ago

6

Su Ka 1 year, 8 months ago

(3+√3)(3-√3)=(3)²-(√3)²=9-3=6
  • 3 answers

Preeti Dabral 1 year, 8 months ago

Smriti Gupta 1 year, 8 months ago

6

Cheran Teja 1 year, 8 months ago

6
  • 1 answers

Dolly Verma 1 year, 8 months ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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  • 1 answers

Preeti Dabral 1 year, 8 months ago

We are given that {tex}AB\parallel CD,\angle APQ = {50^\circ }{/tex} and {tex}\angle{/tex}PRD = 127°
We need to find the value of x and y in the figure.
{tex}\angle{/tex}APQ = x = 50° (Alternate interior angles)
{tex}\angle{/tex}PRD = {tex}\angle{/tex}APR = 127° (Alternate interior angles)
{tex}\angle{/tex}APR = {tex}\angle{/tex}QPR + {tex}\angle{/tex}APQ.
127° = y + 50°
{tex}\Rightarrow{/tex} y = 77°.
Therefore, we can conclude that x = 55° and y = 77°
Alternatively, 127° = y + x (because exterior angle is equal to the sum of interior opposite angles).
so, ​​​​​​127° = y + 50°
which gives, x = 50° and y = 77°

  • 5 answers

Neeraj Kaushik 1 year, 8 months ago

Ans is 66

Debayan Kar 1 year, 8 months ago

Answer is 10648

Rudranshi Thakur 1 year, 8 months ago

(7×22/7)^3

Debayan Kar 1 year, 8 months ago

Akshadeep chup re

Akshadeep Meshram 1 year, 8 months ago

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Few rules to keep homework help section safe, clean and informative.
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  • 3 answers

Debayan Kar 1 year, 8 months ago

5√1/10

Debayan Kar 1 year, 8 months ago

5√10

Akshadeep Meshram 1 year, 8 months ago

√2.5
  • 2 answers

Fatima Zafar 1 year, 8 months ago

Ketan thawari search Pythagoras theorem on google

Ketan Thawari 1 year, 8 months ago

Proof: In ∆ABC AD bisects CB,So BD=CD=10cm AD=15cm AC=12cm BD=BD+CD=10+10=20cm By Pythagoras Therom AB²=BC²-AC² AB²=20²-12² AB²=400-144 AB²=256 AB=√256 AB=16cm Hence,proved😂😂😂🤣
  • 5 answers

Sudhir Kumar 1 year, 8 months ago

We can start from here, 4:4=5:5 4(1:1)=5(1:1) 4=5 2+2=4 Hence, 2+2=5

Subankar Sikdar 1 year, 8 months ago

2+2 = 4

Ayush Kumar Jha 1 year, 8 months ago

0=0 20-20=25-25 4(5-5)=5(5-5) [ both eliminating 5-5] 4=5 We can write 2+2=4 2+2=5

Rahul ._. 1 year, 8 months ago

2+2=4 1+1+1+1=2+1+1 Talking 1 common (1+1)(1+1)=1(2+1)+1 2+2=5

Chanchal Choudhary 1 year, 8 months ago

2+2 =4
  • 0 answers
  • 3 answers

Arihan Barolia 1 year, 9 months ago

(90000)^3 + (3*(90000)*(90000)*(-1)) + (3*(-1)*(-1)*(90000)) + (-1)^3 by the identity: (a+b)^3= a^3+ 3aab+ 3bba+ b^3 So the answer after solving is >>> 728,975,700,269,999

Hardik Saluja 1 year, 9 months ago

728,975,700,269,999

Balwant Yadav 1 year, 9 months ago

728,975,700,269,999
  • 5 answers

Debayan Kar 1 year, 9 months ago

137 is wrong ok

Debayan Kar 1 year, 9 months ago

Real answer is 130 mangoes

Debayan Kar 1 year, 9 months ago

Ans 120 mangoes

Balwant Yadav 1 year, 9 months ago

153-99-25=29 29+99=128

Debayan Kar 1 year, 9 months ago

137 mangoes
  • 4 answers

Akshadeep Meshram 1 year, 8 months ago

π × π × π = π³

Debayan Kar 1 year, 9 months ago

Balwant your answer is wrong

Debayan Kar 1 year, 9 months ago

(22/7)³=10648/343

Debayan Kar 1 year, 9 months ago

We know that π=22/7 or 3.1472.......
  • 2 answers

Balwant Yadav 1 year, 9 months ago

(1,1) (-4,3)

Debayan Kar 1 year, 9 months ago

Ans (1,1) (3.5,0)(5,0) (0,2)
  • 3 answers

Balwant Yadav 1 year, 9 months ago

10!=3628800 20=20 9!=362880 And solve 3628800×20÷362880=200

Debayan Kar 1 year, 9 months ago

Balwant yadav solve this question also

Debayan Kar 1 year, 9 months ago

Ans 200
  • 5 answers

Akshadeep Meshram 1 year, 8 months ago

First understand the concept Then start with easy question then increase your difficulty level

Balwant Yadav 1 year, 9 months ago

Any questions prove Our eligibility

Debayan Kar 1 year, 9 months ago

And find out key words from questions

Debayan Kar 1 year, 9 months ago

Circles, quadrilaterals,

Debayan Kar 1 year, 9 months ago

Understand all questions with read properly

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