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  • 1 answers

Pooja Arya 1 year, 8 months ago

Class 9 8.2 is about mid point theorem It says .. In a triangle, the line segment that joins the mid point of any two sides is parallel to the third side also half of it
  • 1 answers

Preeti Dabral 1 year, 8 months ago

Given: Let ABCD is a quadrilateral.
Let its diagonal AC and BD bisect each other at right angle at point O.

{tex}\therefore {/tex}OA = OC, OB = OD
And {tex}\angle {/tex}AOB = {tex}\angle {/tex}BOC = {tex}\angle {/tex}COD = {tex}\angle {/tex}AOD = {tex}{90^ \circ }{/tex}
To prove: ABCD is a rhombus.
Proof: In {tex}\triangle{/tex}AOD and {tex}\triangle{/tex} BOC,
OA = OC [Given]
{tex}\angle {/tex}AOD = {tex}\angle {/tex}BOC [Given]
OB = OD [Given]
{tex}\therefore {/tex} {tex}\triangle{/tex}AOD {tex} \cong{/tex} {tex}\triangle{/tex}COB [By SAS congruency]
{tex} \Rightarrow {/tex} AD = CB [By C.P.C.T.]……….(i)
Again, In {tex}\triangle{/tex}AOB and {tex}\triangle{/tex}COD,
OA = OC [Given]
{tex}\angle {/tex} AOB = {tex}\angle {/tex}COD [Given]
OB = OD [Given]
{tex}\therefore {/tex} {tex}\triangle{/tex}AOB  {tex} \cong {/tex} {tex}\triangle{/tex}COD [By SAS congruency]
{tex} \Rightarrow {/tex} AB = CD [By C.P.C.T.]……….(ii)
Now In {tex}\triangle{/tex}AOB and {tex}\triangle{/tex}BOC,
OA = OC [Given]
{tex}\angle {/tex} AOB = {tex}\angle {/tex}BOC [Given]
OB = OB [Common]
{tex}\therefore {/tex} {tex}\triangle{/tex}AOB {tex} \cong{/tex} {tex}\triangle{/tex}COB [By SAS congruency]
{tex} \Rightarrow {/tex} AB = BC [By C.P.C.T.]……….(iii)
From eq. (i), (ii) and (iii),
AD = BC = CD = AB
And the diagonals of quadrilateral ABCD bisect each other at right angle.
Therefore, ABCD is a rhombus.

  • 2 answers

Debayan Kar 1 year, 9 months ago

50-√32×√50 =50-4√2×5√2 =50-20×√2×√2 =50-20×2 =50-40 =10

Akshadeep Meshram 1 year, 9 months ago

10
  • 1 answers

Sehajpreet Kaur 1 year, 9 months ago

In Δ ABC, P and Q are the mid-points of sides AB and BC respectively. ∴ PQ || AC and PQ = 1 2 AC ( Using mid-point theorem) …..(1) In Δ ADC, R and S are the mid - points of CD and AD respectively. ∴ RS || AC and RS = 1 2 AC ( Using mid-point theorem) …..(2) From equation (1) and (2) , we obtain PQ || RS and PQ = RS Since in quadrilateral PQRs, one pair of opposite sides is equal and parallel to each other , it is a parallelogram. Let the diagonals of rhombus ABCD intersect each other at point O. In Quadrilateral OMQN, MQ || ON ( ∵ PQ || AC) QN || OM ( ∵ QR || BD) Therefore, OMQN is a parallelogram. ∴ ∠ M Q N = ∠ N O M and ∠ P Q R = ∠ N O M However, ∠ N O M = 90 ∘ (Diagonals of a rhombus are perpendicular to each other) ∴ ∠ P Q R = 90 ∘ Clearly , PQRS is a parallelogram having one of its interior angles as 90 ∘ Hence, PQRS is a rectangle.
  • 2 answers

Akshadeep Meshram 1 year, 8 months ago

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Mohak Yadav 1 year, 9 months ago

Question is wrong
  • 2 answers

Shivang Sharma 1 year, 8 months ago

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Lavesh Sahu 1 year, 9 months ago

17/35
  • 2 answers

Debayan Kar 1 year, 9 months ago

1. Material required are ruler , notebook, pencil with compass and eraser

Abhishek Ranjan 1 year, 9 months ago

Plz give m answer
  • 1 answers

Ansh Raj 1 year, 9 months ago

It is irrational number.
  • 1 answers

Shubh Goyal 1 year, 9 months ago

No
  • 1 answers

Preeti Dabral 1 year, 8 months ago

Angle HYD = 120°

Angle BTG = 60°

Angle YXC = 70°

Angle SXF = 70°

Angle ASE = 70°

  • 5 answers

Shivang Sharma 1 year, 8 months ago

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Shubh Goyal 1 year, 9 months ago

(x+y)(x-y)

Garvit Sharma 1 year, 9 months ago

(x-y)whole squre

Smriti Gupta 1 year, 9 months ago

(x+y)(x-y)

Garvit Chawla 1 year, 9 months ago

(x+y) (x-y)
  • 2 answers

Preeti Dabral 1 year, 9 months ago

{tex}y = \frac{{3x + 10}}{5}{/tex}

Shubh Goyal 1 year, 9 months ago

y=3x+10/5
  • 4 answers

Preeti Dabral 1 year, 9 months ago

Let the radius of the sphere be r cm.
Surface area = 154 cm2
⇒ {tex}4\pi r^2{/tex} = 154
{tex}4\times{22\over7}\times r^2=154{/tex}
⇒ {tex}r^2={{154\times7}\over4\times22}={49\over4}{/tex}
⇒ r = {tex}{\sqrt{49\over4}}={7\over2}{/tex}
⇒ r = 3.5 cm
∴ the radius of the sphere is 3.5 cm.

Smriti Gupta 1 year, 8 months ago

3.5

Siddhi Gupta 1 year, 9 months ago

S.a=154 4πr²=154 r²=154 x 7\4 x 22 r=√49/7 r=7/2 r=3.5cm Radius of sphere is 3.5 cm

Shubh Goyal 1 year, 9 months ago

√10.5=3.24
  • 1 answers

Smriti Gupta 1 year, 9 months ago

(0,13),(11,2),(10,3),(12,1)
  • 5 answers

Smriti Gupta 1 year, 9 months ago

10302

Shubh Goyal 1 year, 9 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x 2 +(a+b)x+ab, we have (100+1)(100+2)=(100) 2 +(1+2)100+(1)(2) =10000+(3)100+2=10000+300+2 =10302

Shivanand Tiwari 1 year, 9 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x 2 +(a+b)x+ab, we have (100+1)(100+2)=(100) 2 +(1+2)100+(1)(2) =10000+(3)100+2=10000+300+2 =10302

Rudra . 1 year, 9 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x2+(a+b)x+ab, we have (100+1)(100+2)=(100)2+(1+2)100+(1)(2) =10000+(3)100+2 =10000+300+2 =10302

Rudra . 1 year, 9 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x 2 +(a+b)x+ab, we have (100+1)(100+2)=(100) 2 +(1+2)100+(1)(2) =10000+(3)100+2=10000+300+2 =10302
  • 3 answers

Adarsh Pal 1 year, 9 months ago

No

Shivanand Tiwari 1 year, 9 months ago

No

Honey Arya 1 year, 9 months ago

No
  • 0 answers
  • 3 answers

Smriti Gupta 1 year, 9 months ago

(x+y) (x²-xy+y²)

Shubh Goyal 1 year, 9 months ago

(x+y) (x²-xy+y²)

Garvit Chawla 1 year, 9 months ago

(x+y) (x²-xy+y²)
  • 3 answers

Md Shaif 1 year, 9 months ago

If two equal chords of a circle intersect with in the circle. Prove that the Segnment of one chord are equal to corresponding Segnment of the other chord

Rahul ._. 1 year, 9 months ago

0/10

Bhramjot Singh 1 year, 9 months ago

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  • 2 answers

Rahul ._. 1 year, 9 months ago

By using threorem

Poojith K Gowda 1 year, 9 months ago

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  • 2 answers

Smriti Gupta 1 year, 9 months ago

root 12 - root18 upon -1

Devansh Yadav 1 year, 9 months ago

Answer is 6 root 2 - root 3 upon -1
  • 1 answers

Shreya Patel 1 year, 9 months ago

Type the question please
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  • 4 answers

Rahul ._. 1 year, 9 months ago

Andrew Tate brother spotted

Sudhir Kumar 1 year, 9 months ago

Be a backbencher like me so you can handle this situation daily without any help

Aaditya Debnath 1 year, 9 months ago

You can be happy by thinking that these are not the last exams of life. These exams are nothing in front of life's exams. Life gives you surprise tests everyday. What matters is where you are after 10 years. Will you be earning a good amount after 10 years? This matters. But marks are just numbers they cannot judge your personality.

Hardik Sharma 1 year, 9 months ago

Because It is were daily mood
  • 2 answers

Hardik Sharma 1 year, 9 months ago

Assertion and reasons

Dhairya Sharma 1 year, 9 months ago

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