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  • 3 answers

Debayan Kar 2 years, 3 months ago

5√1/10

Debayan Kar 2 years, 3 months ago

5√10

Akshadeep Meshram 2 years, 3 months ago

√2.5
  • 2 answers

Fatima Zafar 2 years, 3 months ago

Ketan thawari search Pythagoras theorem on google

Ketan Thawari 2 years, 3 months ago

Proof: In ∆ABC AD bisects CB,So BD=CD=10cm AD=15cm AC=12cm BD=BD+CD=10+10=20cm By Pythagoras Therom AB²=BC²-AC² AB²=20²-12² AB²=400-144 AB²=256 AB=√256 AB=16cm Hence,proved😂😂😂🤣
  • 5 answers

Sudhir Kumar 2 years, 3 months ago

We can start from here, 4:4=5:5 4(1:1)=5(1:1) 4=5 2+2=4 Hence, 2+2=5

Subankar Sikdar 2 years, 3 months ago

2+2 = 4

Ayush Kumar Jha 2 years, 3 months ago

0=0 20-20=25-25 4(5-5)=5(5-5) [ both eliminating 5-5] 4=5 We can write 2+2=4 2+2=5

Rahul ._. 2 years, 3 months ago

2+2=4 1+1+1+1=2+1+1 Talking 1 common (1+1)(1+1)=1(2+1)+1 2+2=5

Chanchal Choudhary 2 years, 3 months ago

2+2 =4
  • 0 answers
  • 3 answers

Arihan Barolia 2 years, 3 months ago

(90000)^3 + (3*(90000)*(90000)*(-1)) + (3*(-1)*(-1)*(90000)) + (-1)^3 by the identity: (a+b)^3= a^3+ 3aab+ 3bba+ b^3 So the answer after solving is >>> 728,975,700,269,999

Hardik Saluja 2 years, 3 months ago

728,975,700,269,999

Balwant Yadav 2 years, 3 months ago

728,975,700,269,999
  • 5 answers

Debayan Kar 2 years, 3 months ago

137 is wrong ok

Debayan Kar 2 years, 3 months ago

Real answer is 130 mangoes

Debayan Kar 2 years, 3 months ago

Ans 120 mangoes

Balwant Yadav 2 years, 3 months ago

153-99-25=29 29+99=128

Debayan Kar 2 years, 3 months ago

137 mangoes
  • 4 answers

Akshadeep Meshram 2 years, 3 months ago

π × π × π = π³

Debayan Kar 2 years, 3 months ago

Balwant your answer is wrong

Debayan Kar 2 years, 3 months ago

(22/7)³=10648/343

Debayan Kar 2 years, 3 months ago

We know that π=22/7 or 3.1472.......
  • 2 answers

Balwant Yadav 2 years, 3 months ago

(1,1) (-4,3)

Debayan Kar 2 years, 3 months ago

Ans (1,1) (3.5,0)(5,0) (0,2)
  • 3 answers

Balwant Yadav 2 years, 3 months ago

10!=3628800 20=20 9!=362880 And solve 3628800×20÷362880=200

Debayan Kar 2 years, 3 months ago

Balwant yadav solve this question also

Debayan Kar 2 years, 3 months ago

Ans 200
  • 5 answers

Akshadeep Meshram 2 years, 3 months ago

First understand the concept Then start with easy question then increase your difficulty level

Balwant Yadav 2 years, 3 months ago

Any questions prove Our eligibility

Debayan Kar 2 years, 3 months ago

And find out key words from questions

Debayan Kar 2 years, 3 months ago

Circles, quadrilaterals,

Debayan Kar 2 years, 3 months ago

Understand all questions with read properly
  • 1 answers

Pooja Arya 2 years, 3 months ago

Class 9 8.2 is about mid point theorem It says .. In a triangle, the line segment that joins the mid point of any two sides is parallel to the third side also half of it
  • 1 answers

Preeti Dabral 2 years, 2 months ago

Given: Let ABCD is a quadrilateral.
Let its diagonal AC and BD bisect each other at right angle at point O.

OA = OC, OB = OD
And AOB = BOC = COD = AOD = 90
To prove: ABCD is a rhombus.
Proof: In AOD and BOC,
OA = OC [Given]
AOD = BOC [Given]
OB = OD [Given]
 AOD COB [By SAS congruency]
AD = CB [By C.P.C.T.]……….(i)
Again, In AOB and COD,
OA = OC [Given]
AOB = COD [Given]
OB = OD [Given]
 AOB   COD [By SAS congruency]
AB = CD [By C.P.C.T.]……….(ii)
Now In AOB and BOC,
OA = OC [Given]
AOB = BOC [Given]
OB = OB [Common]
 AOB  COB [By SAS congruency]
 AB = BC [By C.P.C.T.]……….(iii)
From eq. (i), (ii) and (iii),
AD = BC = CD = AB
And the diagonals of quadrilateral ABCD bisect each other at right angle.
Therefore, ABCD is a rhombus.

  • 2 answers

Debayan Kar 2 years, 3 months ago

50-√32×√50 =50-4√2×5√2 =50-20×√2×√2 =50-20×2 =50-40 =10

Akshadeep Meshram 2 years, 3 months ago

10
  • 1 answers

Sehajpreet Kaur 2 years, 3 months ago

In Δ ABC, P and Q are the mid-points of sides AB and BC respectively. ∴ PQ || AC and PQ = 1 2 AC ( Using mid-point theorem) …..(1) In Δ ADC, R and S are the mid - points of CD and AD respectively. ∴ RS || AC and RS = 1 2 AC ( Using mid-point theorem) …..(2) From equation (1) and (2) , we obtain PQ || RS and PQ = RS Since in quadrilateral PQRs, one pair of opposite sides is equal and parallel to each other , it is a parallelogram. Let the diagonals of rhombus ABCD intersect each other at point O. In Quadrilateral OMQN, MQ || ON ( ∵ PQ || AC) QN || OM ( ∵ QR || BD) Therefore, OMQN is a parallelogram. ∴ ∠ M Q N = ∠ N O M and ∠ P Q R = ∠ N O M However, ∠ N O M = 90 ∘ (Diagonals of a rhombus are perpendicular to each other) ∴ ∠ P Q R = 90 ∘ Clearly , PQRS is a parallelogram having one of its interior angles as 90 ∘ Hence, PQRS is a rectangle.
  • 2 answers

Akshadeep Meshram 2 years, 3 months ago

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Mohak Yadav 2 years, 3 months ago

Question is wrong
  • 2 answers

Shivang Sharma 2 years, 3 months ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
  • Don't post personal information, mobile numbers and other details.
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  • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
  • Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Lavesh Sahu 2 years, 3 months ago

17/35
  • 2 answers

Debayan Kar 2 years, 3 months ago

1. Material required are ruler , notebook, pencil with compass and eraser

Abhishek Ranjan 2 years, 3 months ago

Plz give m answer
  • 1 answers

Ansh Raj 2 years, 3 months ago

It is irrational number.
  • 1 answers

Shubh Goyal 2 years, 3 months ago

No
  • 1 answers

Preeti Dabral 2 years, 3 months ago

Angle HYD = 120°

Angle BTG = 60°

Angle YXC = 70°

Angle SXF = 70°

Angle ASE = 70°

  • 5 answers

Shivang Sharma 2 years, 3 months ago

This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

Few rules to keep homework help section safe, clean and informative.
  • Don't post personal information, mobile numbers and other details.
  • Don't use this platform for chatting, social networking and making friends. This platform is meant only for asking subject specific and study related questions.
  • Be nice and polite and avoid rude and abusive language. Avoid inappropriate language and attention, vulgar terms and anything sexually suggestive. Avoid harassment and bullying.
  • Ask specific question which are clear and concise.

Remember the goal of this website is to share knowledge and learn from each other. Ask questions and help others by answering questions.

Shubh Goyal 2 years, 3 months ago

(x+y)(x-y)

Garvit Sharma 2 years, 3 months ago

(x-y)whole squre

Smriti Gupta 2 years, 3 months ago

(x+y)(x-y)

Garvit Chawla 2 years, 3 months ago

(x+y) (x-y)
  • 2 answers

Preeti Dabral 2 years, 3 months ago

y=3x+105

Shubh Goyal 2 years, 3 months ago

y=3x+10/5
  • 4 answers

Preeti Dabral 2 years, 3 months ago

Let the radius of the sphere be r cm.
Surface area = 154 cm2
⇒ 4πr2 = 154
4×227×r2=154
⇒ r2=154×74×22=494
⇒ r = 494=72
⇒ r = 3.5 cm
∴ the radius of the sphere is 3.5 cm.

Smriti Gupta 2 years, 3 months ago

3.5

Siddhi Gupta 2 years, 3 months ago

S.a=154 4πr²=154 r²=154 x 7\4 x 22 r=√49/7 r=7/2 r=3.5cm Radius of sphere is 3.5 cm

Shubh Goyal 2 years, 3 months ago

√10.5=3.24
  • 1 answers

Smriti Gupta 2 years, 3 months ago

(0,13),(11,2),(10,3),(12,1)
  • 5 answers

Smriti Gupta 2 years, 3 months ago

10302

Shubh Goyal 2 years, 3 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x 2 +(a+b)x+ab, we have (100+1)(100+2)=(100) 2 +(1+2)100+(1)(2) =10000+(3)100+2=10000+300+2 =10302

Shivanand Tiwari 2 years, 3 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x 2 +(a+b)x+ab, we have (100+1)(100+2)=(100) 2 +(1+2)100+(1)(2) =10000+(3)100+2=10000+300+2 =10302

Rudra . 2 years, 3 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x2+(a+b)x+ab, we have (100+1)(100+2)=(100)2+(1+2)100+(1)(2) =10000+(3)100+2 =10000+300+2 =10302

Rudra . 2 years, 3 months ago

101×102=(100+1)(100+2) Now, using identify (x+a)(x+b)=x 2 +(a+b)x+ab, we have (100+1)(100+2)=(100) 2 +(1+2)100+(1)(2) =10000+(3)100+2=10000+300+2 =10302
  • 3 answers

Adarsh Pal 2 years, 3 months ago

No

Shivanand Tiwari 2 years, 3 months ago

No

Honey Arya 2 years, 3 months ago

No
  • 0 answers

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