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  • 1 answers

Yogita Ingle 5 years, 5 months ago

Polynomials = Poly (means many) + nomials (means terms). Thus, a polynomial contains many terms

Thus, a type of algebraic expression with many terms having variables and coefficients is called polynomial.

Example: 3x , 5y2+2x+5, and 2x2+2

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Bhoomika . 5 years, 5 months ago

It can not be proved because (a+b)cube= a3+b3+3ab(a+b)
  • 1 answers

??Sumit Suman?? 5 years, 5 months ago

11/26, 17/36 , 35/72, 37/72 ,41/72,
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Sia ? 5 years, 5 months ago

We need to make the whole numbers as a rational number by multiplying and dividing the numerator and the denominator with the same number
Thus, We have,
-1 = {tex}-\frac{1}{1}=\frac{-1 \times 10}{1 \times 10}=-\frac{10}{10}{/tex}
1 = {tex}\frac{1}{1}=\frac{1 \times 10}{1 \times 10}=\frac{10}{10}{/tex}
So, {tex}-\frac{9}{10}<-\frac{8}{10}<-\frac{7}{10}<-\frac{6}{10}<-\frac{5}{10}<-\frac{4}{10}<-\frac{3}{10}{/tex}
or - 1 {tex}-\frac{9}{10}<-\frac{8}{10}<-\frac{7}{10}<-\frac{6}{10}<-\frac{5}{10}<-\frac{4}{10}<-\frac{3}{10} < 1{/tex}
{tex}\therefore{/tex} four rational numbers between –1 and 1 are
{tex}-\frac{9}{10},-\frac{8}{10},-\frac{7}{10},-\frac{6}{10}{/tex}

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Sanjaykumar Sanjay Kumar 5 years, 5 months ago

001
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  • 2 answers

Khushi Singh 5 years, 5 months ago

Remainder theorem

Rohit Dubey 5 years, 5 months ago

What do u need
  • 3 answers

Mahi Rathod 3 years, 10 months ago

hi I am boss

Ankit Maurya 3 years, 11 months ago

Hello I am Ankita I boss of 9class

Yogita Ingle 5 years, 5 months ago

In ∆ABC, AB = 15 cm , BC = 13 cm and AC = 14 cm.

By Heron's formula ,

S = ( A + B + C ) / 2

S = ( 15 + 13 + 14 ) / 2

S = 42 / 2

S = 21

 Now, area of triangle

= √S (S–A) (S–B) (S–C)

= √21 (21–15) (21–13) (21–14)

= √21 (6) (8) (7)

= √7056

= 84 cm2

Again,area of triangle = 1/2×base×altitude=84 cm2

1/2×14×altitude = 84

7 × altitude=84

altitude = 84/7

Altitude = 12cm

Therefore, the area of ∆ABC is 84cm² and its altitude on AC is 12 cm.

 

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Kanchi Singh 5 years, 5 months ago

x=3.3bar x=3.3333... -I 10x=33.333... -II II-I 10x-x =33.333... -3.333... 9x=30 x=30/9 x=10/3
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Yogita Ingle 5 years, 5 months ago

5x2 -3x+7-(x-1)
= 5x2 - 3x + 7 - x + 1
= 5x2 - 4x + 8

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Sia ? 5 years, 5 months ago

According to the question x is extra milk and y is the expenditure for the month
If the quantity of extra milk be 'x' and expenditure be Rs. 'y' then the given condition.
y = 20x + 500  (As Rs.500 is the fixed expenditure) ...(i)
Put x = 0 in equation (i)
y = 20(0) + 500 = 0 + 500
y = Rs.500

When no extra milk is taken the expenditure remains Rs.500 same
Put y = 1000 in equation (i)
1000 = 20x + 500
1000 - 500 = 20x
500 = 20x
x = {tex}\frac{500}{20}=25 \mathrm{kg}{/tex}

When the 25 kg of milk is taken extra the expenditure increased as Rs.1000
Put x = 2 in equation (i)
y = 20(2) + 500 
y = 40 + 500
y = Rs. 540 
When the 2 kg of milk is taken extra the expenditure increased by Rs.40 i.e. Rs. 540

<th scope="row">x</th> <th scope="row">y</th>
0 25 2
500 1000 540
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Sourav Dash 5 years, 5 months ago

19,20,21,22,23
  • 3 answers

Sia ? 5 years, 5 months ago

  • The mirror image of point (2, 3) is (2, -3) with respect to x-axis.
  • The mirror image of (-4, -6) is (-4,6) with respect to x-axis.

Priya Bhagoria 5 years, 5 months ago

* mirror image of point (2,3) is (2,-3) with respect to x axis. * mirror image of (-4,-6) is (-4,6)

Yogita Ingle 5 years, 5 months ago

In image of a point P(x, y) with respect to x axis, the change in only sign of ordinate of point so the image is Q (x, -y)
So, the mirror image of the point (2,3) is (2 ,-3) and (-4,-6) is (-4,6)

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Samridhi ?? 5 years, 5 months ago

P (-2/3)=4×-2/3 - 12×-2/3 + 14×2/3 - 3 = -8/3 + 8 + 28/3 - 3 =20/3 + 5 = 35/3?
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Sia ? 5 years, 5 months ago

8170

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Annesha Mondal 5 years, 5 months ago

3\2^2=3\4=0.75

45516111? 46 5 years, 5 months ago

? Sorry
  • 1 answers

Namrata Jindal 5 years, 5 months ago

3/4 or 0.75

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