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Aditya Mishra Smhs Chintal, X-A Hyd 6 years, 6 months ago
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Samridhi ?? 6 years, 6 months ago
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Posted by Lal Prabhakar Singh 6 years, 6 months ago
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Yogita Ingle 6 years, 6 months ago
(a + b + c)² = a² + b² + c² +2(ab + bc + ca)
=250 + 2 × 3
= 256
a + b + c = √256
= 16
Dishita Tuteja 6 years, 6 months ago
Posted by Suneel Kumar 6 years, 6 months ago
- 2 answers
Yogita Ingle 6 years, 6 months ago
Given Equation is 2a^3 + 16b^3 - 5a - 10b.
This can be written as
2(a^3 + 8b^3) - 5a - 10b
We know that a 3 + b 3 = (a+b)(a2-ab+b2)
= > 2(a + 2b)(a2 - 2ab + 4b2) - 5a - 10b
= > 2(a + 2b)(a2 - 2ab + 4b2) - 5(a + 2b)
= > (a + 2b)(2(a 2 -2ab + 4b2) - 5)
= > (a + 2b)(2a2 - 4ab + 8b2 - 5)
Therefore the equation can be factorized as (a + 2b)(2a2 - 4ab + 8b2 - 5)
Posted by Adarsh Jain 6 years, 6 months ago
- 1 answers
Yogita Ingle 6 years, 6 months ago
=√50-√98+√162
=5√2-7√2+9√2
Taking root 2 common,
=√2(5-7+9)
=7√2
Posted by Tanisha Rawat 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
According to question, x : y = 11 : 19
Therefore, x = 11a and y = 19 a
Now, AD is parallel to BE
So
{tex}\angle{/tex}BDC = {tex}\angle{/tex}ABD
y = 32
19 a = 32
So a = {tex}\frac{32}{19}{/tex}
Thus x = {tex}11 \times \frac{32}{19}{/tex}
x = 18.52
Since {tex}\angle{/tex}DCE ={tex}\angle{/tex}ADC
So. {tex}\angle{/tex}DCE = x + 32 = 18.52 + 32 = 50.32
Posted by Nikhil Saxena 6 years, 6 months ago
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Posted by Meenakshi Kansal 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
49x2 - b = {tex}\left( {7x + \frac{1}{2}} \right)\left( {7x - \frac{1}{2}} \right){/tex}
49x2 - b = (7x)2 - {tex}{\left( {\frac{1}{2}} \right)^2}{/tex}
49x2 - b = 49x2 - {tex}\frac 14{/tex}
b = {tex}\frac 14{/tex}
Posted by Meenakshi Kansal 6 years, 6 months ago
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Posted by Meenakshi Kansal 6 years, 6 months ago
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Yogita Ingle 6 years, 6 months ago
If f(x) is a polynomial such that f (-1/3) =0
So, f(x) = polynomial with variable x
If f(-1/3) = 0 (it's the value of the polynomial at that point)
So, one factor of f(x) will be (x + 1/3)
Because, if the zero of the polynomial is a negative number, the factor will be a positive number.
Posted by Meenakshi Kansal 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
We know, √3 = 1.732 and √5 = 2.23
Hence, irrational numbers between them are 1.737337333..... or 2.101001000.....
Posted by Praveen Kumar Praveen Kumar 6 years, 6 months ago
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Abhsiehk Kumar 6 years, 6 months ago
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Anusha Jha 6 years, 6 months ago
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