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Ask QuestionPosted by Aayushi..??? The Cutie Pie? 6 years, 6 months ago
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Posted by Aayushi..??? The Cutie Pie? 6 years, 6 months ago
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Yogita Ingle 6 years, 6 months ago
Altitude of equilateral triangle = h cm
Let the side of triangle = x cm
As we all know the altitude bisects the side of triangle .
A.T.Q
Area of angled triangle ADC,
area = 1/2 × base × height
= 1/2 × x/2 ×h
= 2xh/2
= xh cm²
Area of triangle ABC = 2 × area of triangle ADC
= 2xh cm²
Posted by Rinku Jain Dilip Jain 6 years, 6 months ago
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Posted by Sunil Kumar 6 years, 6 months ago
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Posted by Ashi Ramavat 6 years, 6 months ago
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Yogita Ingle 6 years, 6 months ago
1. First, we draw a line OA of length 1
2. Now, we draw a perpendicular of length 1 on point A as AB
3. From, Pythagoras Theorem, OB = √2
4. Now, take an arc of length OB, and draw it on the number line which meets as E.
So, at E, we can represent √2 as shown in the figure.
Posted by Tanvi Chauhan?? 6 years, 6 months ago
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Posted by Harsh Pandey 6 years, 6 months ago
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Posted by Prateek Kumar 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Whole numbers are positive numbers, including zero, without any decimal or fractional parts. They are numbers that represent whole things without pieces. The set of whole numbers is represented mathematically by the set: {0, 1, 2, 3, 4, 5...}.
Posted by Shwetha Shiva 6 years, 6 months ago
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Posted by Love Rathore 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Given, {tex}2 ^ { \frac { 2 } { 3 } } \cdot 2 ^ { \frac { 1 } { 3 } }{/tex}
We know that {tex}a ^ { m } \cdot a ^ { n } = a ^ { ( m +n) }{/tex}.
So, {tex}2 ^ { \frac { 2 } { 3 } } \cdot 2 ^ { \frac { 1 } { 3 } } = ( 2 ) ^ { \frac { 2 } { 3 } + \frac { 1 } { 3 } }{/tex}
{tex}= ( 2 ) ^ { \frac { 2+1} { 3} }\\ = ( 2 ) ^ { \frac { 3 } { 3 } }\\=(2)^1\\=2{/tex}
Therefore, the value of {tex}2 ^ { \frac { 2 } { 3 } } \cdot 2 ^ { \frac { 1 } { 3 } }{/tex} will be {tex}2{/tex}.
Posted by Mahi Vats 6 years, 6 months ago
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Posted by Sugandha Deene 6 years, 6 months ago
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Yogita Ingle 6 years, 6 months ago
The distance of a point from x-axis is equal to its y coordinate.
So, the distance of the point (-3, -2) from x-axis is 2 units.
Posted by Eashen Siddiqui 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
Posted by Møhàmmād Âyãáñ 6 years, 6 months ago
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Sangeeta Tanwar 6 years, 6 months ago
Kashika Khuranaa.. ? 6 years, 6 months ago
Kashika Khuranaa.. ? 6 years, 6 months ago
Posted by Rashika Raj 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
The real numbers is the set of numbers containing all of the rational numbers and all of the irrational numbers. The real numbers are “all the numbers” on the number line. There are infinitely many real numbers just as there are infinitely many numbers in each of the other sets of numbers. But, it can be proved that the infinity of the real numbers is a bigger infinity.
The natural (or counting) numbers are 1,2,3,4,5,1,2,3,4,5, etc. There are infinitely many natural numbers. The set of natural numbers, {1,2,3,4,5,...}{1,2,3,4,5,...}, is sometimes written NN for short. The whole numbers are the natural numbers together with 00.
Posted by Rita Bishoyi 6 years, 6 months ago
- 1 answers
Sia ? 6 years, 6 months ago
We have {tex}0.6 = \frac{6}{{10}}{/tex} ...(1)
Let {tex}x = 0.\bar 7 = 0.777...{/tex} ...(2)
Subtracting (1) from (2), we get
9x = 7 {tex}\Rightarrow x = \frac{7}{9}{/tex} or {tex}0.\bar 7 = \frac{7}{9}{/tex}
Now, let {tex}y = 0.4\bar 7 = 0.4777...{/tex}
{tex}\therefore \;10y = 4.\bar 7{/tex} ...(3)
And {tex}100y = 47.\bar 7{/tex} ...(4)
Subtracting (3) from (4), we get
90y = 43 {tex}\Rightarrow y = \frac{{43}}{{90}}{/tex}
{tex}\therefore \;0.4\bar 7 = \frac{{43}}{{90}}{/tex}
Now, {tex}0.6 + 0.\bar 7 + 0.4\bar 7{/tex}{tex} = \frac{6}{{10}} + \frac{7}{9} + \frac{{43}}{{90}}{/tex}{tex}= \frac{{54 + 70 + 43}}{{90}} = \frac{{167}}{{90}}{/tex}
So, {tex}\frac{{167}}{{90}}{/tex} is of the form {tex}\frac{p}{q}{/tex} and {tex}q \ne 0{/tex}.
Posted by Rita Bishoyi 6 years, 6 months ago
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Posted by Anamika Rajput 6 years, 6 months ago
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Posted by Parth Kumar 6 years, 6 months ago
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