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Sia ? 5 years, 5 months ago

Given: In triangle ABC, {tex}\angle{/tex}B = 45o, {tex}\angle{/tex}C = 45o and AB + BC + CA = 10 cm.
Required: To construct the triangle ABC.
Steps of construction :

  1. Draw a line segment XY = AB + BC + CA = 10 cm.
  2. Construct {tex}\angle{/tex}LXY = {tex}\angle{/tex}B = 45o and {tex}\angle{/tex}MYX = ∠C = 45o
  3. Bisect {tex}\angle{/tex}LXY and {tex}\angle{/tex}MYX. Let these bisectors meet at a point A.
  4. Draw the perpendicular bisectors PQ of AX and RS of AY.
  5. Let PQ intersect XY at B and RS intersect XY at C.
  6. Join AB and AC.


ABC is the required triangle.

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Gulam Rabbani 5 years, 5 months ago

Thanks

Yogita Ingle 5 years, 5 months ago

9992 = (1000 - 1)2
Using identity, (a - b) 2 = a 2 + b 2 -2ab
(1000 - 1)2 =(1000) 2 + (1) 2 - 2(1000×1)
= 1000000 + 1 - 2000
= 1000001 - 2000
= 998001

 

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Sameeksha V H 5 years, 5 months ago

X=a+- root a^2-b /2 14 + root 180 a^2-b = 14^2 - 180 = 16 Root 16 is 4 14+4/2, 14-4/2 9,5 Square root =root 9+ root 5 =3+root 5
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Tishya Jha 5 years, 5 months ago

Dear Friend, The answer should be (x)^2/3*(y)^3
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Tishya Jha 5 years, 5 months ago

√169= 13, thus a rational no.

Rudrani Kumari 5 years, 5 months ago

1√169 =1*13 =13 It is rational

Harpreet Kaur Kaur Dhiman 5 years, 5 months ago

Rational
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Swagatika Mohapatra 5 years, 5 months ago

Triangle is a closed figure which is made up of 3 sides, it have 3sides, 3angles, and 3 vertices
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Adarsh Dwivedi 5 years, 5 months ago

5.1/5 ,5.2/5 ,5.3/5 ,5.4/5 ,5.5/5
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Shambhavi Srivastav 5 years, 5 months ago

x+y =w+z ( given) W+Z)(w+z)=360 2(w+z)=360 w+z=180 This proves that AOB is a line

Shambhavi Srivastav 5 years, 5 months ago

x+y=w+z (given) (w+z)(w+z)=180 2(w+z)=180 (W+z)=90 This proves that AoB is a line
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Lakshya Khandelwal 5 years, 5 months ago

12
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