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Sia ? 5 years, 5 months ago
Given: In triangle ABC, {tex}\angle{/tex}B = 45o, {tex}\angle{/tex}C = 45o and AB + BC + CA = 10 cm.
Required: To construct the triangle ABC.
Steps of construction :
- Draw a line segment XY = AB + BC + CA = 10 cm.
- Construct {tex}\angle{/tex}LXY = {tex}\angle{/tex}B = 45o and {tex}\angle{/tex}MYX = ∠C = 45o
- Bisect {tex}\angle{/tex}LXY and {tex}\angle{/tex}MYX. Let these bisectors meet at a point A.
- Draw the perpendicular bisectors PQ of AX and RS of AY.
- Let PQ intersect XY at B and RS intersect XY at C.
- Join AB and AC.
ABC is the required triangle.
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Yogita Ingle 5 years, 5 months ago
9992 = (1000 - 1)2
Using identity, (a - b) 2 = a 2 + b 2 -2ab
(1000 - 1)2 =(1000) 2 + (1) 2 - 2(1000×1)
= 1000000 + 1 - 2000
= 1000001 - 2000
= 998001
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Shagun Gaur 5 years, 5 months ago
1Thank You