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Bangle Singh 5 years, 4 months ago

How????

Deekshitha Lal 5 years, 5 months ago

√19+√18
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Udit Verma Verma 5 years, 5 months ago

3Г45-75 Answer
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Sia ? 5 years, 5 months ago

In mathematics, a coefficient is a multiplicative factor in some term of a polynomial, a series, or any expression;

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??Sumit Suman?? 5 years, 5 months ago

Your ans is wrong

Amey Om 5 years, 5 months ago

X=2-√3 1/x=1/2-√3*2+√3/2+√3 1/x=2+√3/4-3=2+√3 (X-1/X)^3=(2-√3-2+√3)^3 =(0)^3 =0
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Sia ? 5 years, 5 months ago

A polynomial is an expression consisting of variables (also called indeterminates) and coefficients.
Therefore, x125 = 0 is a polynomial.

Udit Verma Verma 5 years, 5 months ago

Yes. It is a poly nomial

Kritika Singh 5 years, 5 months ago

Yes
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Sia ? 5 years, 5 months ago

The empirical probability of an event is the ratio of the number of outcomes in which a specified event occurs to the total number of trials, not in a theoretical sample space but in an actual experiment.

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Sia ? 5 years, 5 months ago

Given: ABCD is a rhombus

In {tex}\triangle{/tex}ABC and {tex}\triangle{/tex}ADC,
AB = CD [Sides of a rhombus]
BC = DA [Sides of a rhombus]
AC = AC [Common]
{tex}\therefore{/tex} {tex}\triangle{/tex}ABC {tex}\cong{/tex} {tex}\triangle{/tex}ADC [By SSS Congruency]
{tex}\therefore{/tex} {tex}\angle {/tex}CAB = {tex}\angle {/tex}CAD And {tex}\angle {/tex}ACB = {tex}\angle {/tex}ACD
Hence AC bisects {tex}\angle {/tex}A as well as {tex}\angle {/tex}C
Similarly, by joining B to D, we can prove that {tex}\triangle{/tex}ABD {tex}\cong{/tex} {tex}\triangle{/tex}CBD
Hence BD bisects {tex}\angle {/tex}B as well as {tex}\angle {/tex}D

Utkarsh Star 5 years, 4 months ago

Thanx
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Priya Kalra 5 years, 5 months ago

x = -2
f(x) = 4x2-x+k
4(-2)2 - (-2)+ k = 0
4(4) + 4 + k = 0
16 + 4 + k = 0
20 + k = 0
k = -20

You have written 4 but I think here must beinstead of 4

 

 

 

Yogita Ingle 5 years, 5 months ago

x = -2
f(x) = 4x2-x+k
4(-2)2 - (-2)+ k = 0
4(4) + 4 + k = 0
16 + 4 + k = 0
20 + k = 0
k = -20

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Tripti Rawat 5 years, 5 months ago

Coordinates of B will be (1,-1)
and Coordinates of D will be (-1.1)

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Tripti Rawat 5 years, 5 months ago

= 267 - 1
= 1.4757395e+20 

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Shashwanth Shashwanth 5 years, 5 months ago

Sry without knowing

Shashwanth Shashwanth 5 years, 5 months ago

%9%9
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Sia ? 5 years, 5 months ago

We know that there are infinite rational numbers between any two numbers. A rational number is the one that can be written in the form of {tex}\frac{p}{q}{/tex}, where p and q are integers and {tex}q \ne 0{/tex} We know that the numbers all lie between 3 and 4. We need to rewrite the numbers in {tex}\frac{p}{q}{/tex} form to get the rational numbers between 3 and 4. So, we cover it in{tex}\frac{p}{q}{/tex}

{tex}\eqalign{ & {7 \over 1} = {7 \over 1} \times {{10} \over {10}} = {{70} \over {10}} \cr & {9 \over 1} = {9 \over 1} \times {{10} \over {10}} = {{90} \over {10}} \cr} {/tex}

So any six number between {tex}{{70} \over {10}},{{90} \over {10}}{/tex}will be the answer example {tex}{{71} \over {10}},{{73} \over {10}},{{74} \over {10}},{{75} \over {10}},{{77} \over {10}},{{78} \over {10}}{/tex}

 

 

Golu Raza 5 years, 5 months ago

7=7.0 and 9= 9.0 The required numbers are = 7.1,7.2,7.3,7.4,7.5 ,7.6
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Aakash Kumar 5 years, 5 months ago

1 and 2 1×10=10 2×10=20 = 11,12,13,14,15 The five number between 1 and 2
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Anurag Jain 5 years, 5 months ago

= 212,413,314 = 2612,4412,3312 [Making all the powers as like terms] = 26−−√12,44−−√12,33−−√12 = 64−−√12,256−−−√12,27−−√12 Here 256−−−√12 is greater. Therefore, 4–√3 is greater.

Anurag Jain 5 years, 5 months ago

Give me solution

Sonia Chauhan 5 years, 5 months ago

^4√3
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