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  • 1 answers

Mishtee Jadav 6 years, 6 months ago

What to do
  • 4 answers

Preethika Srinivasan 6 years, 5 months ago

24

Aditya Ojha 6 years, 6 months ago

24 is correct

Dk M 6 years, 6 months ago

24 is right ans.

Kawal Jeet 6 years, 6 months ago

24
  • 2 answers

Kashika Khuranaa.. ? 6 years, 5 months ago

K=3/3 K=1

Raj Ranjan 6 years, 6 months ago

K=3 by 3
  • 0 answers
  • 1 answers

Ayush Rajput 6 years, 6 months ago

92675/100000
  • 1 answers

Chhotu Sahu Sahu 6 years, 6 months ago

1,642
  • 1 answers

Pranav Pandey 6 years, 6 months ago

3
  • 1 answers

Sujal Ronaldo 6 years, 6 months ago

=0
  • 1 answers

Sujal Ronaldo 6 years, 6 months ago

= (-15.8)
  • 1 answers

Shalu Kumari 6 years, 6 months ago

X/2-y/3=2, 3x-2y/6=2, 3x-2y=6×2, 3x-2y=12, 3x=12+2y(divide both sides by three) 3x/3=12/3+2y/3, X=4+2/3 y,
  • 1 answers

Vimal Kumar 6 years, 5 months ago

Bc
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Rudrani Kumari 6 years, 6 months ago

Terminating
  • 2 answers

Deepak Mangalore 6 years, 4 months ago

Thank u

Aditya Kaushik 6 years, 6 months ago

4
  • 1 answers

Yash Raval 6 years, 6 months ago

the answer is 122 x solution is p(x)=5x³-2x²+3x-2 = (125x) cube3 -(4x)square2 +(3x)-(2) = 125x-4x and 3x-2 = 121x and 1x = 121x + 1x = 122x ans -
  • 1 answers

Yash Raval 6 years, 6 months ago

answer is x degree is x not 6
  • 3 answers

Priyanshu Ghosh 6 years, 6 months ago

98

Seema Halder 6 years, 6 months ago

Yes or no

Seema Halder 6 years, 6 months ago

2
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Sia ? 6 years, 6 months ago


Construction : Draw EF || AB || CD
As AB || EF and transversal AE cuts them
{tex}\therefore{/tex} {tex}\angle{/tex}BAE + {tex}\angle{/tex}FEA = 180o . . . . . [Interior angles on same side of transversal are supplementary]
{tex}\therefore{/tex} 108o + {tex}\angle{/tex}FEA = 180o
{tex}\therefore{/tex} {tex}\angle{/tex}FEA = 180o – 108o = 72o
As EF || CD and a transversal EC intersects them
{tex}\angle{/tex}FEC + {tex}\angle{/tex}ECD = 180o . . . . . [Interior angles on same side of transversal are supplementary]
{tex}\therefore{/tex} {tex}\angle{/tex}FEC + 112o = 180o
{tex}\therefore{/tex} {tex}\angle{/tex}FEC = 180o – 112o = 68o
{tex}\therefore{/tex} xo = {tex}\angle{/tex}AEC = {tex}\angle{/tex}FEA + {tex}\angle{/tex}FEC = 72o + 68o = 140o
{tex}\therefore{/tex} x = 140o

  • 3 answers

Shalu Kumari 6 years, 6 months ago

Yes ,because it doesn't have any perfect square

Rujul Pawar 6 years, 6 months ago

Yes

Suchitra Khandelwal 6 years, 6 months ago

Yes

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