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103×107=(100+3)(100+7 =(100)Square+(3+7)×100+3×7 [Using the identity (x+a)(x+b)=x Square+(a+b)x+ab] =10000+10×100+21=10000+1000+ 21 =11021 95×96=(90+5)(90+6) =(90)Square+(5+6)×90+5×6 =8100+990+30 =9120

Posted by Rishabh Raoso Pawar 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

45516111? 46 5 years, 5 months ago

✓

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Root 7 on number line root 7 on number line

Posted by Jatin Kohli 5 years, 5 months ago

CBSE > Class 09 > Mathematics

3 answers

Priya Roy 5 years, 5 months ago

Now make √3 on number line first then take it this √3 as base and 2 cm as perpendicular and join the hypotenuse with centre.take this hypotenuse as arc and cut on number line this intersection point shows √7 on number line.

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Priya Roy 5 years, 5 months ago

Which is under root (2)^2+(√3)^2

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Priya Roy 5 years, 5 months ago

First of all make. Sum of squares of factors of 7

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B2/under root a2+b2+a

Posted by Akhtar Khan 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Akhtar Khan 5 years, 5 months ago

simplify by rationalising the denominator: b2 /root(a2+b2)+a

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What is the divide law in exponents and powers....for class 9

Posted by Pratyush Panwar 5 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Pratyush Panwar 5 years, 5 months ago

Thanks..

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45516111? 46 5 years, 5 months ago

Mean

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2 mathematical statement for class 4

Posted by Palmu Tamang 5 years, 5 months ago

CBSE > Class 09 > Mathematics

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Examples sum 21 25 in ch 2 polynomial for grade 9

Posted by Monisha Barveen 5 years, 5 months ago

CBSE > Class 09 > Mathematics

0 answers

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Fotmula of quadrilateral & parallelogram

Posted by Harsha Jv 5 years, 5 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

Is 22/7 which is pie is reccuring or non reccuring number

Posted by Harshith K V 5 years, 5 months ago

CBSE > Class 09 > Mathematics

3 answers

Shashank Sathish 5 years, 5 months ago

It is non-recurring as well as non-terminating, therefore it is an irrational number.

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Power P 5 years, 5 months ago

It ia a irrational number because it is nor a repeating ( terminating) or not non terminating

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Preethika Srinivasan 5 years, 5 months ago

It is a non reccuring number

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Irrational number on number line √13

Posted by Manjula A. Patel 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Manjula A. Patel 5 years, 5 months ago

Irrational no on a no line √13

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The value of k for which x +7 is a factor of p (x )=-x²-k x +7is given as 6. Justify

Posted by Pankhudi Rathod 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Anjali Chandra 5 years, 5 months ago

(x+7) x=-7 -(-7×-7)-k×-7+7 -49+7k+7 -42+7k 7k=42 K=42/7 =6 Ans

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(Root 2-2) the whole square is a rational or irrational number?how?

Posted by Being Supertalented 5 years, 5 months ago

CBSE > Class 09 > Mathematics

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Plots the points P(1,0),q(4,0)and S(1,3).find the coordinate of the points R such that PQRS is a square

Posted by Ankit Khandelwal 5 years, 5 months ago

CBSE > Class 09 > Mathematics

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Plots the points A(0,4)B(-3,0)C(0, -4)and D(3,0).Name the figure obtained by joining the points A,B,C,D in order and find the area of the figure. In Which quadrants the side AB and AD lie

Posted by Ankit Khandelwal 5 years, 5 months ago

CBSE > Class 09 > Mathematics

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4/√7-√3 -2/√5-√3 -2/√7+√5 =0

Posted by Yashika Yadav 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Yashika Yadav 5 years, 5 months ago

Rationalise the denominator

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AOB is a straight line. Find the value of x, hence find <AOC, <COD and <BOD.

Posted by Brizund Momin 5 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Abhijeet Singh 5 years, 4 months ago

In line segment AOB there was not a point X. Hence, the question was wrong

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Gopal Krishna 5 years, 5 months ago

Yes aob is straight line

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329/100

Posted by Onam Vinchhi 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Vritant Jain 5 years, 5 months ago

3.29

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In figure, AOB is a straight line. Find the value of x. Hence, find <AOC, <COD and <BOD.

Posted by Brizund Momin 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 5 years, 5 months ago

AOB is a straight line
{tex}\therefore{/tex} {tex}\angle{/tex}AOC + {tex}\angle{/tex}COD + {tex}\angle{/tex}DOB = 180°
{tex}\Rightarrow{/tex} (3x – 5)° + 55° + (x + 20)° = 180°
{tex}\Rightarrow{/tex} 3x – 5° + 55° + x + 20° = 180°
{tex}\Rightarrow{/tex} 4x + 70° = 180°
{tex}\Rightarrow{/tex} 4x = 180° – 70°
{tex}\Rightarrow{/tex} 4x = 110°
{tex}\Rightarrow{/tex} x =110/4 = 27 ½°
Therefore, {tex}\angle{/tex}AOC = 3x – 5° = 3 {tex}\times{/tex} 27½° – 5 = 77½°
and {tex}\angle{/tex}BOD = x + 20 = 27 ½ + 20 = 47 ½^o