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Sia ? 6 years ago
AOB is a straight line
∴ ∠AOC + ∠COD + ∠DOB = 180°
⇒ (3x – 5)° + 55° + (x + 20)° = 180°
⇒ 3x – 5° + 55° + x + 20° = 180°
⇒ 4x + 70° = 180°
⇒ 4x = 180° – 70°
⇒ 4x = 110°
⇒ x =110/4 = 27 ½°
Therefore, ∠AOC = 3x – 5° = 3 × 27½° – 5 = 77½°
and ∠BOD = x + 20 = 27 ½ + 20 = 47 ½o
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