CBSE > Class 09 > Mathematics | CBSE Board | Homework Help

Let p(x) = x³ + 3x² + 3x + 1
5 + 2x = 0
{tex}\Rightarrow{/tex} 2x = -5
{tex}\Rightarrow{/tex} x = -{tex}\frac{5}{2}{/tex}
= (-{tex}\frac{5}{2}{/tex})³ + 3(-{tex}\frac{5}{2}{/tex})² + 3(-{tex}\frac{5}{2}{/tex}) + 1
= -{tex}\frac{125}{8}{/tex} + {tex}\frac{75}{4}{/tex} - {tex}\frac{15}{2}{/tex} + 1 = -{tex}\frac{27}{8}{/tex}

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If x to the power a/b =1 ,find the value of a

Posted by Ankit Patel 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Lalithakumar Iyer 6 years, 5 months ago

a/b=0whete a can be any integer and b is 0.

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If x3+1/x3=110, then find the value of x+1/x

Posted by Yuvraj Kasana 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 6 years, 5 months ago

Given x³+ 1/x³ =110
Recall that (x+1/x)³= x³+ 1/x³ + 3(x+1/x)
Let (x+1/x)=a
⇒ a³ = 110 + 3a
⇒a³ − 3a −110=0
Put a=5
⇒ 5³ − 3(5) −110
=125 −15 −110=0
Hence (a − 5) is a factor.
On dividing (a³ − 3a −110) with (a − 5) we get the quotient as (a²+5a+22)
∴ a³ − 3a −110 = (a − 5)(a²+5a+22) = 0
Hence (a − 5) = 0 and (a²+5a+22) ≠ 0
⇒(x+1/x) − 5=0
∴ (x+1/x) = 5

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What is Squares and cubes

Posted by Saniya Chokshi 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 6 years, 5 months ago

The square of a number is the number multiplied by itself. So, 2² is 2 × 2 , or two square and is equal to 4 .
In the same way, a number to the power of three is called the cube of the number. So 3³ is 3×3×3, or three cubed and is equal to 27.

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What is even number and odd number

Posted by Saniya Chokshi 6 years, 5 months ago

CBSE > Class 09 > Mathematics

4 answers

Sia ? 6 years, 5 months ago

Any integer that can be divided exactly by 2 is an even number.
The last digit is 0, 2, 4, 6 or 8
Any integer that cannot be divided exactly by 2 is an odd number.
The last digit is 1, 3, 5, 7 or 9

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Ritu Sahu 6 years, 5 months ago

A number ends with 1,3,5,7,9 or that cannot divisible by 2 are called odd numbers

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Ritu Sahu 6 years, 5 months ago

A number ends with 2,4,0,6,8,are called even numbers or number divisible from 2

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Yogita Ingle 6 years, 5 months ago

Even numbers always end with a digit of 0, 2, 4, 6 or 8.
2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30 are even numbers.

Odd numbers always end with a digit of 1, 3, 5, 7, or 9.
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31 are odd numbers.

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Find the l.c.m of the following number 2366 and 1274

Posted by Saniya Chokshi 6 years, 5 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

242/1000 is a rational number or decimalnumber

Posted by Dumpala Jaswanth Reddy 6 years, 5 months ago

CBSE > Class 09 > Mathematics

3 answers

Khushi Sharma 6 years, 5 months ago

Rational number because both number have odd number at thrir end

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Ankit Patel 6 years, 5 months ago

Rational no. As it can be represented in the form of p/q where q is not equal to 0.

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Dumpala Jaswanth Reddy 6 years, 5 months ago

Rational number

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What is the answer of(A+B+C)3

Posted by Shiv Pawadashetti 6 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Sia ? 6 years, 5 months ago

{tex}( a + b + c ) ^ { 3 } = [ a + ( b + c ) ] ^ { 3 }{/tex}

{tex}= a ^ { 3 } + 3 a ^ { 2 } ( b + c ) + 3 a ( b + c ) ^ { 2 } + ( b + c ) ^ { 3 }{/tex}

{tex}= a ^ { 3 } + 3 a ^ { 2 } b + 3 a ^ { 2 } c + 3 a[ \left( b ^ { 2 } + 2 b c + c ^ { 2 } \right)] + \left( b ^ { 3 } + 3 b ^ { 2 } c + 3 b c ^ { 2 } + c ^ { 3 } \right){/tex}

{tex}= a ^ { 3 } + 3 a ^ { 2 } b + 3 a ^ { 2 } c + 3 a b ^ { 2 } + 6 a b c + 3 a c ^ { 2 } + b ^ { 3 } + 3 b ^ { 2 } c + 3 b c ^ { 2 } + c ^ { 3 }{/tex}

{tex}= a ^ { 3 } + b ^ { 3 } + c ^ { 3 } + 3 a ^ { 2 } b + 3 a ^ { 2 } c + 3 b ^ { 2 } c + 3 b ^ { 2 } a + 3 c ^ { 2 } a + 3 c ^ { 2 } b + 6 a b c{/tex}

{tex}= a ^ { 3 } + b ^ { 3 } + c ^ { 3 } + 3 a ^ { 2 } ( b + c ) + = a ^ { 3 } + b ^ { 3 } + c ^ { 3 } + 3 a ^ { 2 } ( b + c ){/tex}

{tex}\therefore{/tex}{tex}( a + b + c ) ^ { 3 } = a ^ { 3 } + b ^ { 3 } + c ^ { 3 } + 3 ( a + b ) ( b + c ) ( c + a ){/tex}

2Thank You

Khushi Sharma 6 years, 5 months ago

(a+b+c)³=(a+b)³+c³+3(a-b)c(a+b+c)

1Thank You

ANSWER

1upon 3 power -3

Posted by Yash Gupta 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Rimpa Goswami Goswami 6 years, 5 months ago

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ANSWER

Express 0.99999......

Posted by Mujeeb Ul Nisa 6 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Surbhii Mittal 6 years, 5 months ago

Let x= 0.9- 1 ( 9 ke uper baar) multiply by 10 ( beca. We hv to shift 9 before the decimal point ) so, 10x=9.9 - 2 subract equation 1 from 2 answer is 9x=9 ,x=1

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A Gautam 6 years, 5 months ago

Let 0.9999... be x x = 0.9999..... 10x = 10*0.9999.... 10x = 9.9999.... 10x-x = 9.9999.. -0.9999.. 9x = 9 x = 9 divided by 9 x = 1

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ANSWER

excercise 2.4

Posted by Vanaja Vanaja 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Khushi Sharma 6 years, 5 months ago

Oof

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How to represent √x on number line????

Posted by Himanshu Kumawat 6 years, 5 months ago

CBSE > Class 09 > Mathematics

3 answers

Ritu Sahu 6 years, 5 months ago

√x is we can write9.3 Drwa a line then cut an arc to the both end points that bisect each other, then draw a semicircle through the point and then draw 99degree then from the 90 degree join it to the line

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Rahul Singh 6 years, 5 months ago

1Thank You

Rohan Saikia 6 years, 5 months ago

Muje bhe batana

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How to represent root3 on numberline

Posted by Chaitanya Madiwalar 6 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Ria Rockstar 6 years, 5 months ago

There are step to construct √3 on numberline . 1) draw a line and mark it as AB. 2) add 1 cm to previous line and mark it as C 3) now, take a base of 2 cm and height 1 cm on numberline and mark it as D . Now draw line from A to D. 4) use pythagoras theoram and remark the line AD as √3 . 5) place a rounder on point B and make an arch , which reaches numberline . Place of intersection of arch at numberline is √3.

1Thank You

Govind Natani 6 years, 5 months ago

It is not typed but the value of√3 is 1.732 aproxx

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ANSWER

Find different five solution of. 2x_3y=6 2x/5+3y/10=3

Posted by Manpreet Singh 6 years, 5 months ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

7 x cube minus 3 X raised to 4 - 0 x + 2 cube + 2 X raised to square - 5 x + x cube + 2 x square

Posted by Laxmi Kannolli 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Prtee Pandey 6 years, 5 months ago

Pata nahi

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ANSWER

Why the euclid's chapter added in mathematics class 9th

Posted by ꧁༒ Shaurya༻ 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Laxmi Kannolli 6 years, 5 months ago

7 raised to 5 - 3 x raised to 4 zero x cube + 2 x square - 5 x divided by X + 2 x square

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ANSWER

What is consecutive interior angle

Posted by Aryan Yadav 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 6 years, 5 months ago

The pairs of angles on one side of the transversal but inside the two lines are called Consecutive Interior Angles.

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ANSWER

x-2y=4

Posted by Rajat Deshmukh 6 years, 5 months ago

CBSE > Class 09 > Mathematics

2 answers

Amritanshu Singh 6 years, 5 months ago

x=4+2y

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Manav M? 6 years, 5 months ago

So what

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Root 2 x minus 3 y whole square

Posted by Shivansh Dubey 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sharvesth Sharma 6 years, 5 months ago

Pta nhi

3Thank You

ANSWER

Proof that root 5 is an irrational number

Posted by Shofia Jha 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

Let {tex}\sqrt 5{/tex} is a rational number.
{tex}\sqrt { 5 } = \frac { a } { b }{/tex}(a, b are co-primes and b{tex}\neq{/tex}0)
or, {tex}a = b \sqrt { 5 }{/tex}
On squaring both the sides, we get
a²=5b² ---------------------------------(1)
Hence 5 is a factor of a²
so 5 is a factor of a
Let a = 5c, (c is some integer)
{tex}\therefore{/tex} a² = 25c²

From equation(1) putting the value of a²
or, 5b² = 25c²

or b²=5c²

so 5 is a factor of b²
or 5 is a factor of b
Hence 5 is a common factor of a and b
But this contradicts the fact that a and b are co-primes.

This is because we assumed that {tex}\sqrt 5{/tex} is rational
{tex}\therefore{/tex} {tex}\sqrt 5{/tex} is irrational.

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ANSWER

Simplify by rationalising the denominator. 2underrot6-5underrot / divided 3 underrot 5-2underrot6

Posted by Ashwani Kumar 6 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

We have,
{tex}\frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}}{/tex} = {tex}\frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}} \times \frac{3 \sqrt{5}+2 \sqrt{6}}{3 \sqrt{5}+2 \sqrt{6}}{/tex}
= {tex}\frac{(2 \sqrt{6}-\sqrt{5})(3 \sqrt{5}+2 \sqrt{6})}{(3 \sqrt{5}-2 \sqrt{6})(3 \sqrt{5}+2 \sqrt{6})}{/tex}
= {tex}\frac{2 \sqrt{6}(3 \sqrt{5}+2 \sqrt{6})-\sqrt{5}(3 \sqrt{5}+2 \sqrt{6})}{(3 \sqrt{5})^{2}-(2 \sqrt{6})^{2}}{/tex}
= {tex}\frac{6 \sqrt{30}+24-15-2 \sqrt{30}}{45-24}{/tex}
= {tex}\frac{4 \sqrt{30}+9}{21}{/tex}
{tex}\therefore{/tex} {tex}\frac{2 \sqrt{6}-\sqrt{5}}{3 \sqrt{5}-2 \sqrt{6}}{/tex} = {tex}\frac{4 \sqrt{30}+9}{21}{/tex}