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Sia ? 5 years, 3 months ago
Here a = {tex}\frac {1} {3}{/tex}, b = {tex}\frac {1} {2}{/tex}, n = 3
{tex}\therefore{/tex} {tex}\frac{b-a}{n+1}=\frac{\frac{1}{2}-\frac{1}{3}}{3+1}{/tex}{tex}=\frac{\frac{3-2}{6}}{4}{/tex}{tex}=\frac{\frac{1}{6}}{4}=\frac{1}{24}{/tex}
{tex}\therefore{/tex} Three rational numbers between {tex}\frac {1} {3}{/tex} and {tex}\frac {1} {2}{/tex} are
{tex}\frac{1}{3}+\frac{1}{24}, \frac{1}{3}+2\left(\frac{1}{24}\right), \frac{1}{3}+3\left(\frac{1}{24}\right){/tex}
{tex}\frac{1}{3}+\frac{1}{24}{/tex}, {tex}\frac{1}{3}+\frac{1}{12}{/tex}, {tex}\frac{1}{3}+\frac{1}{8}{/tex}
{tex}\frac{3}{8}, \frac{5}{12}, \frac{11}{24}{/tex}
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According to the Pythagoras theorem, we can conclude that {tex}{\left( {\sqrt 5 } \right)^2} = {\left( 2 \right)^2} + {\left( 1 \right)^2}{/tex} We need to draw a line segment AB of 1 unit on the number line. Then draw a straight line segment BC of 2 units. Then join the points C and A, to form a line segment BC. Then draw the arc ACD, to get the number {tex}\sqrt 5 {/tex} on the number line.
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Mitochondria are the organelles in which the most important part of the cellular respiration occurs, i.e., the ATP production.
Mitochondria are organelles bounded by two lipid membranes. The inner membrane infolded to the interior of the organelle forming cristae that define the internal space known as mitochondrial matrix and where mitochondrial DNA (mtDNA), mitochondrial RNA (WRNA), mitochondrial ribosomes and respiratory enzymes can be found.
Mitochondria are found in eukaryotic cells in high number and are also more abundant in those cells that use more energy, like muscle cells. Because mitochondrion has its own DNA, RNA, and ribosomes. They can even have the ability to self-replicate.
Posted by Raghav Patidar 5 years, 3 months ago
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Mark the distance 9.3 units from a fixed point A on a given line to obtain a point B such that AB = 9.3 units. From B mark a distance of 1 unit and call the new point as C. Find the mid-point of AC and call that point as O. Draw a semi-circle with centre O and radius OC = 5.15 units. Draw a line perpendicular to AC passing through B cutting the semi-circle at D. Then BD = {tex}\sqrt {9.3} .{/tex}
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Check NCERT Solutions here : https://mycbseguide.com/ncert-solutions.html
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