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  • 4 answers

Vedant Kakade 4 years, 9 months ago

Thanks

Akshat Mohanty 4 years, 9 months ago

It is true

Tarun Singh Bhadouria 4 years, 9 months ago

Yes it is

Newton Madhav 4 years, 9 months ago

Yes
  • 1 answers

V 4591 Vrunda Khadangale 4 years, 9 months ago

Statistics
  • 2 answers

Raj Singh 4 years, 9 months ago

821.33333m3

Utsav Kumar 4 years, 9 months ago

Water displaced = vol of sphere
  • 1 answers

Utsav Kumar 4 years, 9 months ago

Since sq is parllelogram so join all diagonal and congruent all the triangles formad
  • 2 answers

Rishabh Gupta 4 years, 9 months ago

3.54554555455554......... And 5.56556555655556...... And there are many decimal number which can't be terminate and can't be reccuring......

Mahendra Chouhan 4 years, 9 months ago

1 and0
  • 7 answers

Khushi Sharma 4 years, 9 months ago

Semi perimeter

Utsav Kumar 4 years, 9 months ago

Semi peri = p/2

Ruchi Bansal 4 years, 9 months ago

S is semiperimeter S= a+b+c/2

Raj Singh 4 years, 9 months ago

It has not any full form but its means the semiperimeter

Saloni Kumari 4 years, 9 months ago

Semi perimeter

Harvinder Ahlawat 4 years, 9 months ago

Semi perimeter

Om Singh 4 years, 9 months ago

Semi perimeter
  • 1 answers

Yogita Ingle 4 years, 9 months ago

Let us consider two congruent circles (circles of same radius) with centers as O and O

In ΔAOB and ΔCO'D,

AOB = CO'D (Given)

OA = O'C (Radii of congruent circles)

OB = O'D (Radii of congruent circles)

ΔAOB ΔCO'D (SAS congruence rule)

AB = CD (By CPCT)

Hence, if chords of congruent circles subtend equal angles at their centers, then the chords are equal.

  • 4 answers

Vedant Kakade 4 years, 9 months ago

Supplementary

Rishabh Gupta 4 years, 9 months ago

Supplement is correct....

Om Singh 4 years, 9 months ago

Suplementary

Khushi Sharma 4 years, 9 months ago

Sum of them are180 .....I think supplementary
  • 0 answers
  • 7 answers

Utsav Kumar 4 years, 9 months ago

Leave the cbse board

Raj Singh 4 years, 9 months ago

3 who prmoted you in this class

Vansh Kharb 4 years, 9 months ago

3 fool

Ujjawal Verma 4 years, 9 months ago

3 what you are studying.

Khushi Sharma 4 years, 9 months ago

1+2=3 .......are you really a mad..

Ruchi Bansal 4 years, 9 months ago

2+1=3

Anushka . 4 years, 9 months ago

3 You are a stupid
  • 2 answers

Khushi Sharma 4 years, 9 months ago

Area of PQR is 15 because a median divides triangle in2 equal part..

Kritika Dhiman 4 years, 9 months ago

Area of PQS=15 cm sq Area of PQR =15 x 2=30cm sq (PS is median and median divides the triangle into two triangles of equal area)
  • 2 answers

Ruchi Bansal 4 years, 9 months ago

Let angle be x x+35=90 x=90-35 x= 55°

Yogita Ingle 4 years, 9 months ago

When two angles are added together and they total 90 degrees, they are said to be complementary angles.

Let the angle be x

then x + 35° =90°

x = 90° - 35°

x = 55°

  • 2 answers

Ujjawal Verma 4 years, 9 months ago

May be more than 15 marks

Ruchi Bansal 4 years, 9 months ago

20 marks
  • 1 answers

Yogita Ingle 4 years, 9 months ago

{tex}Given ,\\ \\ Area \: \: of \: \: the \: \: equilateral \: \: \\ triangle \: \: is \: \: 36 \sqrt{3} \: cm {}^{2} \\ \\ To \: \: find \: \::- \: \:Height \: of \: \: the \\ equilateral \: \: triangle .\\ \\ \\ We \: \: know \: \: that ,\\ \\ Area \: of \: a \: equilateral \: \\ triangle \: \: = \frac{a {}^{2} }{4} \sqrt{3} \: \: \: \: ; where \: \: \: a \: \: \: \\ is \: \: the \: length \: of \: each \: side \: of \: the \\equlateral \: triangle.\\ \\ \\A.T.Q. \\ \\ \frac{a {}^{2} }{4} \sqrt{3} = 36 \sqrt{3} \\ \\ = > \frac{a {}^{2} }{4} = 36 \\ \\ = > a {}^{2} = 36 \times 4 \\ \\ = > a {}^{2} = (6) {}^{2} \times( 2) {}^{2} \\ \\ = > a = 6 \times 2 \\ \\ = > a = 12 \\ \\ \\ Length \: of \: each \: side \: of \: the \: \\ equilateral \: triangle \: is \: 12 \: cm{/tex}

 

 

  • 1 answers

Khushi Sharma 4 years, 9 months ago

Because they meet only on one point
  • 1 answers

Ruchi Bansal 4 years, 9 months ago

Given: AB=CD To prove: Angle AOB= Angle COD Proof: In ∆ AOB& COD AB=CD( given) OA=OB (radii of same circle) OC=OD(radii of same circle) ∆AOB=~ ∆COD( By ASA) Angle AOB= Angle COD( By cpct) Hence proved.
  • 2 answers

Khushi Sharma 4 years, 9 months ago

Obviously.22×22=484

?Roman ? 4 years, 9 months ago

484
  • 1 answers

Yogita Ingle 4 years, 9 months ago

Steps Of Construction:

1. Draw a line segment AB = 12cm.

2. Draw a ray AX making right angle with AB.

3. Cut a line segment AD of length 18 cm from ray AX.

4. Join BD and make an angle DBY equal to ADB.

5. Let BY intersect AX at C. Join AC and BC.

Triangle ABC is the required triangle.

  • 0 answers

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