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    • Posted by Pawan Kumar 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Shahnawaz Ahmad 5 years, 6 months ago

    Pura question to likho

    2Thank You

    ANSWER

    • Posted by Sahil Singh 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Vansh Bharadawaj 5 years, 6 months ago

    Angle subtentet in the center is double then others angle of the circle

    0Thank You

    ANSWER

    • Posted by Sidhartha Behera 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Laxman I 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Harjit Singh 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Sabhajit Pal 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Yash Lohchab 5 years, 6 months ago

    53,59,61,67,71,73 and 79 are the prime numbers between 50 and 80

    0Thank You

    Yogita Ingle 5 years, 6 months ago

    The prime numbers between 50 and 80 are 53, 59, 61, 67, 71, 73 and 79.

    1Thank You

    ANSWER

    • Posted by Niharika Niki 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Anureet Kaur 5 years, 6 months ago

    II) In ? ABD and CBD. AB =BC, AD =CD (ABCD is square) BD=BD. (common) therefore By SSS criterion ? ABD is congruent to ? CBD. Therefore angle 5=6. And angle 7=8. By cpct. Hence proved

    1Thank You

    Anureet Kaur 5 years, 6 months ago

    Given -ABCD is a rectangle, AC bisects A and C Proof -i) In ? ABC and ? ADC 1=2 (given) 3=4 (given) AC=AC (common) By ASA criterion. ? ABC congruent to ? ADC. Therefore AB =AD...... (1) (cpct) but ABCD is rectangle therefore AB=DC.....(2) BC =AD.......(3) From (1),(2),(3) AB =BC=CD=DA. Therefore ABCD is a square

    1Thank You

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    • Posted by Santosh Rj Maurya 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Santosh Rj Maurya 5 years, 6 months ago

    Lesson 2

    1Thank You

    ANSWER

    • Posted by Lakhwinder Singh Dhalli 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Ankesh Mishra 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Yash Lohchab 5 years, 6 months ago

    Height=3cmm Volume=352/7cm^3

    0Thank You

    Yogita Ingle 5 years, 6 months ago

    Surface area of the sphere=(4π×5×5) cm²
    = (100π) cm².

    Curved surface area of the cone=(π×4×l) cm²
    =(4πl) cm²

    ∴ 100π=5×(4πl) ⇒ l=5 cm.
    Now, l² = h² + r²
    5²= h² + 4²
    h²= 9 
    h= 3 cm.

    Volume of cone = 1/3  πr2h

    = 1/3 × 22/7 × (4)2 × 3

    = 22/7 × 16

    = 50.29cm2

    0Thank You

    ANSWER

    • Posted by Pallavi Agrawal 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Saksham Sharma 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Namrata Jindal 5 years, 6 months ago

    Join 0 and 2 on the number line. Draw a perpendicular of length 1 on 2. Join 0 and the endpoint of the perpendicular. Place the point of the compass on 0 and the other on the endpoint. The place where the curve made by the compass meets the number line represents √5.

    1Thank You

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    • Posted by Om Prakash 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Satyam Singh 5 years, 6 months ago

    Where is the figure??

    1Thank You

    ANSWER

    • Posted by Sabir Sharim 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Sabir Sharim 5 years, 6 months ago

    Number system chapter important question

    3Thank You

    ANSWER

    • Posted by Kanishk Vastav 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Ajay Kushwaha 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Manjeet Singh 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Yogita Ingle 5 years, 6 months ago

    Given : Let ABCD is cyclic quadrilateral.
    To prove : ∠A + ∠C = 180°  and ∠B + ∠D = 180°.
    Construction : join OB and OD.

    Proof : ∠BOD = 2 ∠BAD
         ∠BAD = 1/2∠ BOD
    Similarly ∠BCD = 1/2 ∠DOB
    ∠BAD + ∠BCD = 1/2∠BOD + 1/2 ∠DOB
                       =1/2(∠ BOD + ∠DOB)
                       = (1/2)X360° = 180°
    Similarly ∠B + ∠D = 180°

    1Thank You

    ANSWER

    • Posted by Vansh Sachdeva 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Bro . 5 years, 6 months ago

    X=6√5. x² + 1/x². (6√5)² + 1/(6√5)². 180 + 1/180. 32400+1/180. 32401/180

    1Thank You

    ANSWER

    • Posted by Harneet Kaur 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Yogita Ingle 5 years, 6 months ago

    Let the numerator be x and denominator be 2x +4.

    Fraction is x/(2x +4)

    1Thank You

    ANSWER

    • Posted by Bhargav Barad 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Armaan Nagla 5 years, 6 months ago

    hfcbj

    0Thank You

    ANSWER

    • Posted by Spana Rana 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Ujjawal Verma 5 years, 6 months ago

    X+2=0 Using remainder theorem. X+2=0 X=0-2 X=-2 Now, X^2 - 5 +6 (-2)^2 -5 +6 4 + 1 5 :: so remainder is 5.

    0Thank You

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    • Posted by Shailendra Sharma 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Jyoti Bondu 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Anurag Choudhary 5 years, 6 months ago

    1/4

    1Thank You

    Brajesh Kumar 5 years, 6 months ago

    1/2

    1Thank You

    ANSWER

    • Posted by Mansi Class12 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Divya Thakur 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Prabhansh Gangwar 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Tanishka Patni 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Insha Naaz 5 years, 6 months ago

    Radius=10cm Total surface area of a hemisphere=3π(r)2 =3×3•14\100×10×10 = 942cm2

    0Thank You

    ANSWER

    • Posted by Mkm Arif Sajad 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Kartik Jangid 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Navya Sree 5 years, 6 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Kolli Nuthan Sai 5 years, 6 months ago

    p^2+q^2-2pq+q^2+r^2-2rq+r^2+p^2-2pr 2p^2+2q^2+2r^2-2pq-2rq-2pr 2(p^2+q^2+r^2-pq-rq-pr

    2Thank You

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