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Ask QuestionPosted by Alen Gautam 5 years, 2 months ago
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Posted by Dakshita Panday 5 years, 2 months ago
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Posted by Alok Kumar 5 years, 2 months ago
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Yogita Ingle 5 years, 2 months ago
Probability is the measure of the likeliness that an event will occur.Probability is quantified as a number between 0 and 1 (where 0 indicates impossibility and 1 indicates certainty)
Posted by Rahul Rahul 5 years, 2 months ago
- 1 answers
Yogita Ingle 5 years, 2 months ago
Put x = a
x×x+2x+1 = 0
a × a + 2 (a) + 1 = 0
a2 + 2a + 1= 0
(a + 1) (a + 1) = 0
a + 1 = 0
a = -1
Posted by Saurabh Singh 5 years, 2 months ago
- 1 answers
Yogita Ingle 5 years, 2 months ago
3x-54+(7+17x)
= 3x - 54 + 7 + 17x
= 3x + 17x - 54 + 7
= 20x -47
Posted by Haarish Khan 5 years, 2 months ago
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Posted by kuma****@***** 5 years, 2 months ago
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Posted by Shubham Kaushik 5 years, 2 months ago
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Posted by Ankit Kumar 5 years, 2 months ago
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Yogita Ingle 5 years, 2 months ago
Consider the irrational number x = {tex}\sqrt[4]3{/tex}
Then x2 = √3, which is again an irrational number.
∴ The given statement is false.
Posted by Arshpreet Singh 5 years, 2 months ago
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Posted by Mofid Umar 5 years, 2 months ago
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Posted by Anish Singh 5 years, 2 months ago
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Ayush Gamer17 5 years, 2 months ago
Vedant Shrivastava 5 years, 2 months ago
Posted by Aram Hasan 5 years, 2 months ago
- 1 answers
Yogita Ingle 5 years, 2 months ago
Consider a quadrilateral PQRS.
Join QS.
To prove: ∠P + ∠Q + ∠R + ∠S = 360º
Proof:
Consider triangle PQS, we have,
⇒ ∠P + ∠PQS + ∠PSQ = 180º ... (1) [Using Angle sum property of Triangle]
Similarly, in triangle QRS, we have,
⇒ ∠SQR + ∠R + ∠QSR = 180º ... (2) [Using Angle sum property of Triangle]
On adding (1) and (2), we get
∠P + ∠PQS + ∠PSQ + ∠SQR + ∠R + ∠QSR = 180º + 180º
⇒ ∠P + ∠PQS + ∠SQR + ∠R + ∠QSR + ∠PSQ = 360º
⇒ ∠P + ∠Q + ∠R + ∠S = 360º [Hence proved]
Posted by Kiran Maity 5 years, 2 months ago
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Aram Hasan 5 years, 2 months ago
Posted by Mini Bansal 5 years, 2 months ago
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Posted by Ashu Dabra 5 years, 2 months ago
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Yogita Ingle 5 years, 2 months ago
The Total surface area of a cone includes the curved surface as well as area of its base, which is given as-
Base Area = πr2
Curved Surface Area = πrl
Thus total surface area is given by-
πr2 + πrl = πr(r + l)
Posted by Meet Changani 5 years, 2 months ago
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Posted by Rohan Rauniyar 5 years, 2 months ago
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Yogita Ingle 5 years, 2 months ago
| Using Diagonals | A = ½ × d1 × d2 |
| Using Base and Height | A = b × h |
| Using Trigonometry | A = b2 × Sin(a) |
Posted by Harsh Vardhan Sisodiya 5 years, 2 months ago
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Posted by Shivam Yadav 5 years, 2 months ago
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Tee Kay 5 years, 2 months ago
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Rishabh Gupta 5 years, 2 months ago
Posted by Heema Mawai 5 years, 2 months ago
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