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ANSWER

Find the factors of (1-x^3)

Posted by Yogitha S 4 years, 1 month ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

Factorise y³+y²-y-1

Posted by Mnp Mnp 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Beyon P Binoy 4 years, 1 month ago

(y^3+y^2) (-y-1) y^2(y+1) -1(y+1) (y+1) (y^2-1)

3Thank You

ANSWER

((-2)0 + (5)0 + (-13)0)2

Posted by Kalingapatam Udhaykumar 4 years, 1 month ago

CBSE > Class 09 > Mathematics

2 answers

Kashish Choudhary 4 years, 1 month ago

(0+0+0)2 0

Tiger$ Praful Jawale 4 years, 1 month ago

ANSWER

{(_2) 0+(5) 0+(_13) 0}

Posted by Kalingapatam Udhaykumar 4 years, 1 month ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

What is C.P.C.T?

Posted by Sarita Panda 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years, 1 month ago

The abbreviation of CPCT is “Corresponding Parts of Congruent Triangles”. This theorem states that if we take two or more triangles which are congruent to each other then the corresponding angles and the sides of the triangles are also congruent to each other i.e., their corresponding parts are equal to each other.

ANSWER

Expand using suitable identity (3a-5b+4c)2?

Posted by Geetanshu Tanwar 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Agrima Gupta 4 years, 1 month ago

Identity- (a+b+c)2=a2+b2+c2+2ab+2bc+2ca

(3a)2+(-5b)2+(4c)2+2x3a x (-5b)+2x (-5b)x4c+2x3a x 4c

answer= 9a2+25b2+16c2-30ab-40bc+24ac

ANSWER

bisector of interior angle b and exterior angle acd of a triangle abc intersect at point p if the d is the midpoint of the hypotenuse AC of a right triangle ABC proveq that BD=1/2AC

Posted by 〘』Ֆѧťᵞꭿ『〙 _ 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 3 years, 11 months ago

Given:- ∆ABC is a triangle where BT and CT are internal and external bisectors of <ABC and <ACB respectively and they meet at T.

RTP:- <BTC = 1/2 <BAC

Construction:- Let, BC is produced to D and the external <ACD is formed.

Proof:-

In ∆ABC,

Exterior <ACD = interior opposite angle ( <ABC + <BAC )

=) 1/2 <ACD = 1/2 <ABC+ 1/2 <BAC

=) <TCD = <TBC + 1/2 <BAC ......( 1 )

In ∆TBC,

<TCD = <BTC + <TBC ........( 2 )

From ( 1 ) and ( 2 ),

<TBC + 1/2 <BAC = <BTC + <TBC

=) 1/2 <BAC = <BTC

=) <BTC = 1/2 <BAC

[ PROVED ]

ANSWER

the side of a triangle are 11cm ,15cm and 16 cm .find its area.also fide altitude corresponding to its shortcut side?

Posted by Shivna Chouhan 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years, 1 month ago

area= √(s-a)(s-b)(s-c)
s=11+15+16/2
=21cm
area=√21*(21-11)(21-15)(21-16)
=√ 21*10*6*5
=√ 7*3*5*2*3*2*5
=5*3*2√7
=30√t7
area=1/2*b*h
b=16cm
30√7=1/2*16*h
h=30√7/8
=15√7/4

ANSWER

Find a rational number between 2 and 3 Your answer

Posted by Prathipa Murugan 4 years, 1 month ago

CBSE > Class 09 > Mathematics

2 answers

Kashish Choudhary 4 years, 1 month ago

3/2;5/2

Lav Khator 4 years, 1 month ago

5/2

ANSWER

A cubodial oil tin has 40cm length,30cm breadth and 50cm height.Find the cost of tin required for making 20 such tins if the cost of tin sheet is ₹20 per metre square?

Posted by Subham Mallick 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years, 1 month ago

dimension of cuboidal tin = 30cm×40cm×50cm
let length = 40cm
breath = 30cm
height = 50cm
Total surface area = 2(lb+bh+lh)
= 2(40×30 + 30×50 + 40×50)
= 2(1200 + 1500 + 2000)
= 2(4700)
= 9400 cm²
TSA of one tin box = 9400 cm²
TSA of 20 tin boxes = 9400×20 = 18800 cm² = 1.88m²
Cost of tin = Rs. 20/m²
Total cost = 1.88×20 =Rs. 37.60

ANSWER

Can anyone tell me that what is congruent ?

Posted by Harshita Gupta 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Subham Mallick 4 years, 1 month ago

Two shapes idential or coinciding exactly each other.

ANSWER

Anyone can tell me the answer of question no.2 of chapter 7 of exercise no.7.4 its confusing me??????

Posted by Yash Joshi 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Vidhi Srivastav 4 years, 1 month ago

If you tell that of which class you are asking ,will be better to understand

ANSWER

Expand each of the following, using suitable indentities: (x+2y+4z)^2

Posted by Angshuman Talukdar 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years, 1 month ago

(x + 2y + 4z)² = (x)² + (2y)² + (4z)² + 2(x)(2y) + 2(2y)(4z) + 2(4z)(x)|

Using Identity V

= x² + 4y² + 16z²+ 4xy + 16yz + 8 zx.

ANSWER

Name all the types of quadrilateral..

Posted by Bhumika Jaiswal 4 years, 1 month ago

CBSE > Class 09 > Mathematics

3 answers

Subham Mallick 4 years, 1 month ago

Rectangle,Square,Parallelogram,Rhombus,Trapezium and Kite are different types of quadrilateral.

Yogita Ingle 4 years, 1 month ago

The various types of quadrilaterals are

1. Parallelogram: As the name suggests, a parallelogram is a quadrilateral with parallel opposite sides.

2. Rectangle: The Rectangle is also a type of parallelogram with a little difference in the angles of the sides. In a rectangle, all the sides are at the right angle or to say perpendicular to each other.

3. Square: A square is a quadrilateral with all four sides equal. Every vertex of a square makes a right angle with its sides.

4. Rhombus: A rhombus is also a parallelogram but with all sides equal. In other words, a parallelogram that shows e resemblance to a square as regards its lengths of sides is called a rhombus.

5. Trapezium: Amongst the other types of quadrilaterals, a trapezium shows different characteristics, In a trapezium, only one pair of the four sides are parallel to each other.

Riya Mangang 4 years, 1 month ago

Trapezium, parallelogram, kite, rhombus, square, rectangle,

ANSWER

X⁵ + y⁵

Posted by Keshav Agarwal 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Riya Mangang 4 years, 1 month ago

(x+y)⁵

ANSWER

A cube has numerically equal volume and surface area the volume of such a cube is

Posted by Chanchal . 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Ananya K 4 years, 1 month ago

Let L be the length of the cube as per the given condition, Volume (L 3 )=surface area (6L 2 ) or L=6 So, Volume=6 3 =216

ANSWER

(2+3)-(6+7)

Posted by Md Asif 4 years, 1 month ago

CBSE > Class 09 > Mathematics

5 answers

Subham Mallick 4 years, 1 month ago

It would be -8

Ashirwad Chauhan 4 years, 1 month ago

(2+3)-(6+7) =5-13 =-8

Yogita Ingle 4 years, 1 month ago

(2+3)-(6+7)

= 5 - 13

= - 8

Rajkishor Giri 4 years, 1 month ago

Answer: (2+3)-(6+7) =2+3-6-7 =-8

Md Asif 4 years, 1 month ago

-4 answer

ANSWER

If (1, −2) is a solution of the equation 2x – y = p, then find the value of p.

Posted by Dharmik Girsay 4 years, 1 month ago

CBSE > Class 09 > Mathematics

4 answers

Kashish Choudhary 4 years, 1 month ago

2x-y=p (x=1;y=-2) =2×1-(-2)=p =2+2 =p =4=p The value of p is 4

Ashmit Patel 4 years, 1 month ago

2x-y=p Put the value of x=1 and y= -2, 2×1-(-2)=2+2=4

Jayanti Rawat 4 years, 1 month ago

2(1)-(-2)=2-2=1

Sandeep Singh 4 years, 1 month ago

(x,y)=(1,-2) putting the value of x and y in 2x-y=p =2*1-(-1)=2+1=3 therefore p=3

ANSWER

0.235 BAR WRITE IN THE FROM OF P/Q

Posted by ꧁??Nsg ??꧂ ꧁?? Gaming??꧂ 4 years, 1 month ago

CBSE > Class 09 > Mathematics

2 answers

Kashish Choudhary 4 years, 1 month ago

Let x =0.235235....(1) multiply by 1000 both sides 1000x=235.235....(2) Subtract equation 1 from 2 999x=235 x=235/99 Note: Mene 1000 se multiply isliye kiya kyunki jitne no.ke upar bar hota h utne hum zero lagate h.

Subham Mallick 4 years, 1 month ago

Let x=0.235235.......... -----(1) Multiply 100 on both sides. 100x=235.235235.....------(2) Subtract both equation 1&2 99x=235 x=235/99

ANSWER

2x-3=9

Posted by Shaurya Dwivedi Shaurya Dwivedi 4 years, 1 month ago

CBSE > Class 09 > Mathematics

5 answers

Kashish Choudhary 4 years, 1 month ago

2x-3=9 2x=9+3 2x=12 x=12/2=6

Jiya ??? 4 years, 1 month ago

X=6

Ashirwad Chauhan 4 years, 1 month ago

2x-3=9 2x=9+3 2x=12 x=12÷2=6

Aashna Jaiswal 4 years, 1 month ago

2x-3=9 2x=9+3 2x=12 x=12/2 x=6

Student 10Th 4 years, 1 month ago

2x-3=9 2x=9+3 2x=12 x=12/2 x=6

ANSWER

Perimeter and area of rhombus

Posted by Divya Raina 4 years, 1 month ago

CBSE > Class 09 > Mathematics

4 answers

Jiya ??? 4 years, 1 month ago

P=4×length of sides A=half × d1 × d2

Ashmit Patel 4 years, 1 month ago

Perimeter of rhombus = 4a Area of rhombus =1/2×d1×d2

Student 10Th 4 years, 1 month ago

And perimeter P=4a Where is side

Student 10Th 4 years, 1 month ago

(d¹×d²)/2 is area of rhombus

ANSWER

What and we can do CPCT

Posted by C Abbi 4 years, 1 month ago

CBSE > Class 09 > Mathematics

3 answers

Teena Choudhary 4 years, 1 month ago

CPCT-corresponding parts of congruent triangles (full form-congruent triangles corresponding parts)

Anshul Rana 4 years, 1 month ago

CPCT used when 2 triangle are congurant

Bhumika Jaiswal 4 years, 1 month ago

CPCT - Corresponding Parts of Congruent Triangle

ANSWER

A quadrilateral abcb measures ab=12, bc=5 cd=da=10 ac=4 find the area of quadrilateral abcd

Posted by Pooja Mane 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Ashmit Patel 4 years, 1 month ago

Given , ab =12 bc=5 cd=da=10 ac=4 Area of quadrilater = area of Ist triangle + area of 2nd triangle 1/2×base×height+1/2×base ×height 1/2×10×10+1/2×12×5 5×10+6×5 50+30 80cm Therfore the area of quadrilateral of abcd =80cm

ANSWER

1/2+√3 +1/2-√3

Posted by Gulshan Bhatia 4 years, 1 month ago

CBSE > Class 09 > Mathematics

2 answers

Aashna Jaiswal 4 years, 1 month ago

1/2+√3+1/2-√3 =1/2+1/2+√3-√3 =2/2 =1

Yogita Ingle 4 years, 1 month ago

1/2+√3 +1/2-√3

= 1/2 +1/2 +√3 -√3

= 2/2

= 1

ANSWER

Ex7.1

Posted by Jasvir Kaur 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Chandr Kesh Pal 4 years, 1 month ago

Nice i

ANSWER

In a quadrilateral ABCD ,CO and DO are the bisectors of angle C and angle D respectively. Prove that angle COD= 1\2 (angle A+angle B).

Posted by Trushti Parmar 4 years, 1 month ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 3 years, 11 months ago

Angle COD= 1800- 1/2angle C-1/2 angle D=1800-1/2(angle C+D)----------(1)

Angle (A+B+C+D)=3600

AngleC+D= 3600 - AngleA- angle B--------------(2)

Substituting (2) in (1)

Angle COD= 1800-1/2(3600- angle A- Angle B)

Angle COD= 1800-1800+1/2 Angle A + 1/2 Angle B= 1/2(Angle A+ Angle B)