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Yogita Ingle 4 years ago
1) y = 4x
Put x = -3 and y = a
a= 4 ( -3)
a = - 12
2) y = 4x
Put x = b and y = 4
4 = 4 b
b= 4/4 = 1
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Gaurav Seth 3 years, 11 months ago
1. Is zero a rational number? Can you write it in the form p/q where p and q are integers and q ≠ 0?
Solution:
We know that, a number is said to be rational if it can be written in the form p/q , where p and q are integers and q ≠ 0.
Taking the case of ‘0’,
Zero can be written in the form 0/1, 0/2, 0/3 … as well as , 0/1, 0/2, 0/3 ..
Since it satisfies the necessary condition, we can conclude that 0 can be written in the p/q form, where q can either be positive or negative number.
Hence, 0 is a rational number.
2. Find six rational numbers between 3 and 4.
Solution:
There are infinite rational numbers between 3 and 4.
As we have to find 6 rational numbers between 3 and 4, we will multiply both the numbers, 3 and 4, with 6+1 = 7 (or any number greater than 6)
i.e., 3 × (7/7) = 21/7
and, 4 × (7/7) = 28/7. The numbers in between 21/7 and 28/7 will be rational and will fall between 3 and 4.
Hence, 22/7, 23/7, 24/7, 25/7, 26/7, 27/7 are the 6 rational numbers between 3 and 4.
Posted by Anshika Kumari 4 years ago
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Kanika Kanika 4 years ago
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Gaurav Seth 4 years ago
To find the co-ordinates in the adjoining figure, x-axis represents the plain mirror. M is the point in the rectangular axes in the first quadrant whose co-ordinates are (h, k).
When point M is reflected in x-axis, the image M’ is formed in the fourth quadrant whose co-ordinates are (h, -k). Thus we conclude that when a point is reflected in x-axis, then the x-co-ordinate remains same, but the y-co-ordinate becomes negative.
Thus, the image of point M (h, k) is M' (h, -k).
Therefore answer is (2,-3)
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꧁╾━╤デ╦︻ ℛ??????࿐ 4 years, 1 month ago
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Yogita Ingle 4 years, 1 month ago
(x+5)(x-4)
= x ( x - 4) + 5 (x - 4)
= x2 - 4x + 5x - 5(4)
= x2 + x - 20
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Gaurav Seth 4 years, 1 month ago
If a and b are any two distinct positive rational numbers such that ab is not
a perfect square , then the irrational number √ab lies between a and b.
∴ Irrational number between 2 and 2.5 is √ 2 × 2.5 , i.e √5
Irrational number between 2 and √5 is √2 × √5 = 2(1/2) × 5(1/4)
Irrational number between √5 and 2.5 is √√5 × 2.5 =
Thus the three irrational numbers between 2 and 2.5 are √5 , 2(1/2) × 5(1/4) and (1/2) × 5 3/4 × 21/2 .
Posted by Krish Kumar 4 years, 1 month ago
- 3 answers
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Gaurav Seth 4 years ago
The steps of construction to follow:
Step 1: Draw a ray OP.
Then, take O as the centre and any radius draw an arc cutting OP at Q.
Step 2: Now, taking Q as the centre and with the same radius as before draw an arc cutting the previous arc at R. Repeat the process with R to cut the previous arc at S.
Step 3: Take R and S as centre draw the arc of radius more than the half of RS and draw two arcs intersecting at A. Then, join OA.
Hence, .
Justification:
We need to justify,
So, join OR and OS and RQ. we obtain
By construction OQ = OS = QR.
So, is an equilateral triangle. Similarly is an equilateral triangle.
So,
Now, that means .
Then, join AS and AR:
Now, in triangles OSA and ORA:
(common)
(Radii of same arcs)
(radii of the same arcs)
So,
Therefore,
and
Hence, justified.
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