CBSE > Class 09 > Mathematics | CBSE Board | Homework Help

Given: x=1 and y=3. So,when we put the values in the following eq., 3x-4y+9=0 , We get? 3(1)-4(3)+9=0 => 3-12+9=0 => (3+9)-12=0 => 12-12=0 => 0=0 Thus, x=1 and y=3 satisfies the equation 3x-4y+9=0 Hope it helps:)

0Thank You

ANSWER

The area of an equilateral triangle having side length equal to √3/4cm is: a. 2/27 sq.cm b. 2/15 sq.cm c. 3/16 sq.cm d. 3/14 sq.cm

Posted by Shimpi Saha 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Anushka Agarwal 4 years ago

None of the above. This is because the ans is actually [3(√3)]/64 sq.cm

1Thank You

ANSWER

Supplement or complement meaning

Posted by C Abbi 4 years ago

CBSE > Class 09 > Mathematics

4 answers

Sabnam Patri Sabnam Patri 4 years ago

Supplement angle - If the sum of two angles are 180 degree then it is said to be supplement angle. Complement angle - If the sum of two angle is 90 degree then it is said to be compplement angle .

1Thank You

Seema Cma 4 years ago

If the two line are parallel than their corresponding angles are

1Thank You

Shimpi Saha 4 years ago

Supplementary angles- If the sum of two angles is 180° , then it is known as supplementary angles.. Complementary angles- If the sum of two angles is 90°, then it is known as complementary angles...

1Thank You

Gaurav Seth 4 years ago

Supplementary angles and complementary angles are defined with respect to the addition of two angles. If the sum of two angles is 180 degrees then they are said to be supplementary angles, which forms a linear angle together. Whereas if the sum of two angles is 90 degrees, then they are said to be complementary angles, and they form a right angle together.

2Thank You

ANSWER

In the given figure ,o is the centre of the circle and angle BOD =150 ° . Find the value of X and y .

Posted by Muskan Mishra 4 years ago

CBSE > Class 09 > Mathematics

3 answers

Muskan Mishra 4 years ago

Hiiiii

1Thank You

Gaurav Seth 4 years ago

In the given figure, O is the centre of a circle and ∠BOD =150°. Find the values of x and y.

Answer:

It is given that O is the centre of a circle and ∠BOD =150^o

We know that

Reflex ∠BOD = (360^o – ∠BOD)

By substituting the values

Reflex ∠BOD = (360^o – 150^o)

By subtraction

Reflex ∠BOD = 210^o

Consider x = ½ (reflex ∠BOD)

By substituting the value

x = 210/2

So we get

x = 105^o

We know that

x + y = 180^o

By substituting the values

105^o + y = 180^o

On further calculation

y = 180^o – 105^o

By subtraction

y = 75^o

Therefore, the value of x is 105^o and y is 75^o.

1Thank You

Uchit Patel 4 years ago

Hiiii

1Thank You

ANSWER

Maths lines and angles lesson all question and answer

Posted by Sunil Hadapad 4 years ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

7 1/5 ____ 7 1/3

Posted by Manvir Kular 4 years ago

CBSE > Class 09 > Mathematics

5 answers

Sabnam Patri Sabnam Patri 4 years ago

71/5 is greater.

0Thank You

Tanish Tomar 4 years ago

Big

1Thank You

Aditi Singh 4 years ago

71/5 is a greater

0Thank You

Sakshi Ojha 4 years ago

7 1/5 is greater

0Thank You

Focus Pharma 4 years ago

7 1/5 is greater

2Thank You

ANSWER

Earning rupees 13000-16000 per month and owning more than 2 vehicles

Posted by Niharika Sahoo 4 years ago

CBSE > Class 09 > Mathematics

2 answers

Sasmita Acharya 4 years ago

Please send the full question so we can help you

0Thank You

Ananya K 4 years ago

Can u send the complete question

0Thank You

ANSWER

The mean marks of boys and girls in an examination are 70,73 respectively.If mean marks of all the students in that examination is 71.what is the ratio of no of boys to the of girls.

Posted by Yash Yadav 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Ananya K 4 years ago

11th Economics Measures of Central Tendency Arithmetic Mean in Statistics The mean marks (out of 100 ... STATISTICS The mean marks (out of 100) of boys and girls in an examination are 70 and 73, respectively. If the mean marks of all the students in that examination is 71, find the ratio of the number of boys to the number of girls. MEDIUM Share Study later VIDEO EXPLANATION ANSWER Let the total number of boys be x and the total number of girls br y. Let the sum of the marks of boys be a and the sum of the marks of girls be b. Mean marks of boys are =70 Mean marks of girls are =73 Therefore, ⇒ x a =70 ⇒a=70x and ⇒ y b =73 ⇒b=73y Now, mean marks of all the students is 71 Therfore, ⇒ x+y sum of the marks of all the students =71 ⇒sum of the marks of all the students=a+b ⇒a+b=70x+73y Therefore, ⇒ x+y 70x+73y =71 ⇒70x+73y=71x+71y ⇒2y=x ⇒ y x = 1 2 Hence the ratio is 2:1

1Thank You

ANSWER

Find p (0), p(1),p(2) for each of the polynomials .. 1) p(y)=y square - y+1 2) p(x) = x cube 3) p(t) = 2+t+2t square -t cube 4) p(x) = (x-1) (x+1)

Posted by Pratham Bhat 4 years ago

CBSE > Class 09 > Mathematics

1 answers

🖤 🖤 4 years ago

1)p(0)=1 2)p(0)=0 3)p(0)=2 p(1)=1 p(1)=1 p(1)=4 p(2)=3 p(2)=8 p(2)=4 4)p(0)=-1 p(1)=0 p(2)=3

1Thank You

ANSWER

Write 100 integers

Posted by Amisha Kumari 4 years ago

CBSE > Class 09 > Mathematics

4 answers

Nitin Tripathi 4 years ago

You can write anyone from - infinite to + infinite including 0 also.

0Thank You

Sasmita Acharya 4 years ago

1 to 100 simple ex

0Thank You

Rahul Kumar 4 years ago

You have to simply write no from 1-100

0Thank You

Gaurav Seth 4 years ago

All the no.s from 1 to 100 are integers. Integers are no.s other than decimals, for eg., 5 is an integer, 5.1 is non-integer i.e., decimal. Integers are both positive and negative.

1Thank You

ANSWER

Express linear equation x-y=√3 in standard form ax+by+c=0, find the values of a,b,c.

Posted by Sharanya Rumandla 4 years ago

CBSE > Class 09 > Mathematics

3 answers

Anushka Agarwal 4 years ago

x-y=√3 => x-y-√3=0 => (1)x+(-1)y+(-√3)=0 Thus, value of a is 1. Value of b is -1. Value of c is -√3. Hope it helps:)

0Thank You

Lal Devendra Pratap Singh Deo 4 years ago

Sur

0Thank You

Sharanya Rumandla 4 years ago

Anyone plz reply fast

0Thank You

ANSWER

X^5 - x factorise by identity

Posted by Archit Gourha 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years ago

X⁵ - x

= x ( x⁴- 1)

=x (x² - 1) (x² + 1)

= x ( x - 1) ( x+ 1) (x² + 1)

1Thank You

ANSWER

Which is the biggest prime number?

Posted by Sameer Kumar 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Yash Rajput 4 years ago

2n_1

0Thank You

ANSWER

What is sum of 2+2

Posted by Kuldeep Garg 4 years ago

CBSE > Class 09 > Mathematics

5 answers

Gdfyhbbb Hxtdhhfzh 4 years ago

Obviously 4

0Thank You

Ashirwad Chauhan 4 years ago

Wow! what a lovely question you have asked. I think Einstein would also be not able to solve your problem.

0Thank You

Nandini Sharma 4 years ago

Obiuyously four u r in 9 class and u don't know what is 2+2 O God! ?

0Thank You

Sameer Kumar 4 years ago

2+2= 4

0Thank You

No Name Unknown 4 years ago

0Thank You

ANSWER

Exercise 13.2 Question no. 10' 11

Posted by Shivani Mani 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 3 years, 11 months ago

10. In fig. 13.12, you see the frame of a lampshade. It is to be covered with a decorative cloth.

The frame has a base diameter of 20 cm and height of 30 cm. A margin of 2.5 cm is to be given for folding it over the top and bottom of the frame. Find how much cloth is required for covering the lampshade. (Assume π = 22/7)

Solution:

Say h = height of the frame of lampshade, looks like cylindrical shape

r = radius

Total height is h = (2.5+30+2.5) cm = 35cm and

r = (20/2) cm = 10cm

Use curved surface area formula to find the cloth required for covering the lampshade which is 2πrh

= (2×(22/7)×10×35) cm²

= 2200 cm²

Hence, 2200 cm² cloth is required for covering the lampshade.

11. The students of Vidyalaya were asked to participate in a competition for making and decorating penholders in the shape of a cylinder with a base, using cardboard. Each penholder was to be of radius 3 cm and height 10.5 cm. The Vidyalaya was to supply the competitors with cardboard. If there were 35 competitors, how much cardboard was required to be bought for the competition? (Assume π =22/7)

Solution:

Radius of the circular end of cylindrical penholder, r = 3cm

Height of penholder, h = 10.5cm

Surface area of a penholder = CSA of pen holder + Area of base of penholder

= 2πrh+πr²

= 2×(22/7)×3×10.5+(22/7)×3²= 1584/7

Therefore, Area of cardboard sheet used by one competitor is 1584/7 cm²

So, Area of cardboard sheet used by 35 competitors = 35×1584/7 = 7920 cm²

Therefore, 7920 cm² cardboard sheet will be needed for the competition.

0Thank You

ANSWER

Chapter 9 exercise 9.2 question no. 1

Posted by Sujal Jaiswal 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Devesh More 4 years ago

From which school and subject?

0Thank You

ANSWER

What will be the perimeter of the rhombus if the diagonal of a rhombus is 12 and 16

Posted by Himanshu Tiwari 4 years ago

CBSE > Class 09 > Mathematics

5 answers

Sabnam Patri Sabnam Patri 4 years ago

=1/2×d1×d2 =1/2×12×16 =1/2× 192 =96

0Thank You

Anushka Agarwal 4 years ago

And: 40 units

0Thank You

No Name Unknown 4 years ago

Rhombus perimeter is 1/2 *D1*D2 where d is diagonals

0Thank You

Ankush Kumar 4 years ago

96 is the answer of this question

0Thank You

Ankush Kumar 4 years ago

1/2 ×d1×d2

0Thank You

ANSWER

Under root12/3

Posted by [email protected] Rai 4 years ago

CBSE > Class 09 > Mathematics

4 answers

Sabnam Patri Sabnam Patri 4 years ago

0Thank You

Tanish Tomar 4 years ago

0Thank You

Anushka Agarwal 4 years ago

Ans:2 √12/√3=√3*2*2/√3=√2*2(3 is divided by 3). So, 2 comes out. Hence, Ans is 2.

0Thank You

Sarita Panda 4 years ago

Ans is 2

0Thank You

ANSWER

Ch 14 ex 14. 2 question no 1

Posted by Aditee Chauhan 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Gawri Sunil 4 years ago

Blood group / number of students. A- 9,B- 6,O- 12,AB- 3. TOTAL -30

2Thank You

ANSWER

Perform the following divisions

Posted by Shivendra Parmar Parmar 4 years ago

CBSE > Class 09 > Mathematics

0 answers

ANSWER

12+12+8+9+6+1+1+1++4+747+154245+4+247++476+2+75+4576+26+4+4+61725785+875+577574574545++545454424242782572523+525203256126225652560+5+20102636251360240+4610568132311025+ 1652521243613256+514851256+162458121246+44+++4+4+4+97+95441++4526+

Posted by Rengavadivelammal .C 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Bhavesh B Nair 4 years ago

Do you know the answer

0Thank You

ANSWER

Inequalities in a triangle...

Posted by 《Aruba》°°° 《Sayed》❤ 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Sabnam Patri Sabnam Patri 4 years ago

Inequality in a triangle is- The three side of the triangle is not equal.

1Thank You

ANSWER

Verify (a+b+c)³ -a³-b³-c³ =3(a+b) (b+c) (c+a)

Posted by ꧁╾━╤デ╦︻ ℛ??????࿐ 4 years ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 4 years ago

Prove that (a +b +c)³ -a³ -b³– c³=3(a +b)(b +c)(c +a).

Solution to (a +b +c)³ -a³ -b³– c³=3(a +b)(b +c)(c +a)

2Thank You

ANSWER

What is co linear point

Posted by Yamini Kandpal 4 years ago

CBSE > Class 09 > Mathematics

3 answers

Yamini Kandpal 4 years ago

Thanks

0Thank You

Sabnam Patri Sabnam Patri 4 years ago

The line in which there are 3 point lie in a straight line.

1Thank You

Almi Aami 4 years ago

Three or more points , , , ..., are said to be collinear if they lie on a single straight line . A line on which points lie, especially if it is related to a geometric figure such as a triangle, is sometimes called an axis.

1Thank You

ANSWER

If ∆ABC=~∆ACB then ∆ABC is isosceles or

Posted by Risky Priyanshu 4 years ago

CBSE > Class 09 > Mathematics