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  • 1 answers

Meenkashi Singh 3 years, 9 months ago

Let the radius of the cone be r cm. h=40 cm Volume,V=18480 cm3 31​×22/7×r2×40=18480 r2=441 r=21 cm
  • 3 answers

Simran Nehiniwal 3 years, 9 months ago

(2) let radius of the base = r Curved surface area = 2πrh 110 m² = 2 × 22/7 × r × 10 110 × 7 / 440 = r 77/44 = r 7/4 = r 1.75 = r

Simran Nehiniwal 3 years, 9 months ago

(1) It's costs Rs 2200 to paint the inner cirved surface of a cylindrical vessel 10 m deep . The cost of painting is at the rate of Rs 20 per m² = Inner cirved surface area = Total costs / rate = 2200/20 = 110 m²

Gaurav Seth 3 years, 9 months ago

Given,
Lateral surface area = 94.2cm²
Height (h) = 5cm
Let the radius of the base be ' r '

We know,
Lateral surface area = 2πrh
94.2 = 2 × 3.14 × r × 5
94.2/ 2×3.14×5 = r
r = 3
Thus,
The radius of base is 3cm

Also,
Volume of the cylinder = πr²h
= 3.14 × 3² × 5 cm
= 3.14 × 9 × 5cm
= 141.3cm³


Thus,
The radius of the base is 3cm and the volume is 141.3cm³

  • 1 answers

Gaurav Seth 3 years, 9 months ago

AB and CD are equal chords of a circle whose centre is O. When produced, these chords meet at E. Prove that  EB = ED and AE = CE.

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Given: AB and CD are equal chords of a circle whose centre is O. When produced, these chords meet at E.
To Prove: EB = ED and AE = CE.


 

Construction: From O draw OP ⊥ AB and OQ ⊥ CD. Join OE.
Proof: ∵ AB = CD    | Given
∴ OP = OQ
| ∵ Equal chords of a circle are equidistant from the centre
Now in right ∆s OPE and OQE,
Hyp. OE = Hyp. OE    | Common
Side OP = Side OQ    | Proved above



  PE - PB = QE - QD 
     EB  = ED   Proved.
   BE + AB = ED + CD         
   AE = CE

  • 1 answers

Meenkashi Singh 3 years, 9 months ago

We know that the angle subtended at the centre of the circle by an arc is twice the angle subtended by the same arc at any point on the circumference of the circle.    ∠AOB is the angle at the center and ∠ACB is the angle at the circumference.   ∴∠ACB=21​∠AOB=21​(104o)=52o
  • 1 answers

Gaurav Seth 3 years, 9 months ago

Given,
Diameter = d = 84cm
Radius = r = d/2 = 42cm
Length = l = 120 cm
T.S.A of cylinder = 2πrh
                           = 2 x 22/7 x 42 x 120
                           = 31680 cm²
Area levelled by 500 revolution = Area of playground
= 500 x 31680cm²
= 15840000 cm² [ change into m]
= 1584 m²

  • 1 answers

Gaurav Seth 3 years, 9 months ago

Ans. For an equilateral triangle with side ‘a’, area

       

       ∴ Each side of the triangle = a cm

       ∴ a + a + a = 180 cm

       ⇒ 3a = 180 cm

       

       Now, s = Semi–perimeter 

       ∴ Area of a triangle

           

       ∴ Area of the given triangle

       

       

       Thus, the area of the given triangle

  • 1 answers

Gaurav Seth 3 years, 9 months ago

Answer:

  • Area of triangle = 12 cm²

Step-by-step explanation:

Given:

  • Two equal sides of isosceles triangle = 5 cm
  • Third side = 8 cm.

 

To Find:

  • Area of isosceles triangle by Heron's Formula.

 

  • 1 answers

Gaurav Seth 3 years, 9 months ago

Answer:

50.28 or 352/7

Step-by-step explanation:

Given,

Slant height = 5 cm

Radius =  4 cm

Let Height be x cm

So for finding height we have to use Pythagorean  Theorem,

(5)² = (4)² + (x)²

√25 -16 = x

√9 = x

so, x = 3

Height = 3 cm

Volume of Cone =  1/3πr²h

= 1/3×22/7×4×4×3

= (22×16)/7

= 352/7

If you make this fraction in decimal form answer is

50.28

  • 1 answers

Gaurav Seth 3 years, 9 months ago

Given: In quadrilateral ACBD, AC = AD and AB bisects ∠A.
To Prove: ∆ABC ≅ ∆ABD.
Proof: In ∆ABC and ∆ABD,
AC = AD    | Given
AB = AB    | Common
∠CAB = ∠DAB
| ∵ AB bisects ∠A
∴ ∠ABC ≅ ∠ABD    | SAS Rule
∴ BC = BD    | C.P.C.T,

  • 1 answers

Gaurav Seth 3 years, 9 months ago

The surface area of a sphere of radius r is 4πr 2
 . Half of this is 2πr 2
 .
If you have a hemispherical object then it has a base which is a circle of radius r.
The area of a circle of radius r is πr 2
  and thus if the hemisphere is meant to include the base then the surface area is  2πr 2 +πr 2
 =3πr 2

  • 1 answers

Gaurav Seth 3 years, 9 months ago

 (d) 50°, 50°

Given, QPR is 80 degrees
and PQ=PR
let the other two angles be x,x because it is an isosceles triangle
by triangle sum property
80+x+x=180
2x+80=180
2x=100
x=50
therefore angle R and angle Q are 50 degrees

  • 1 answers

Gaurav Seth 3 years, 9 months ago

We know, The interior angles of a triangle always add up to 180.
So,  statement A, B and C is not correct.
(C) An exterior angle of a triangle is always greater than the opposite interior angles.
 is correct
Answer (C) An exterior angle of a triangle is always greater than the opposite interior angles.

  • 1 answers

Gaurav Seth 3 years, 9 months ago

The angle subtended by the diameter of a semicircle is 90o

To prove : ∠APB=90o

∵ We know angle subtended by an arc at centre is double the angle subtended at any point or circumference.

⇒ Angle subtended by arc AB at O= Double the angle subtended at P

⇒∠AOB=2∠APB

∵AOB is a straight line.

⇒∠AOB=1800

⇒2∠APB=180o

⇒∠APB=90o

∴ Angle subtended by arc AB or semi circle is 90o

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  • 1 answers

Gaurav Seth 3 years, 9 months ago

Given:

  • The sides of the triangle are 8cm,11cm and 13cm.

 

Need to find:

  • Area of the triangle

 

 

a = 8cm

b = 11cm

c = 13cm

 

Perimeter of the  = a+b+c

Semi-perimeter = a+b+c/2

Area of ∆ 

  • 1 answers

Yogita Ingle 3 years, 9 months ago

 9(x+7)-6=9-2(x+9)

9x + 63 = 9 -2x - 18

9x + 2x = 9 - 18 - 63

7x = -9-63

7x = - 72

x = -72/7

x = - 10.28

  • 2 answers

Minku Rani 3 years, 7 months ago

Which num

Kripa Daga 3 years, 9 months ago

Which no. To be classified
  • 1 answers

Gaurav Seth 3 years, 9 months ago

Given - x²+6x+10

 

Find - To show the equation has no zero.

 

Answer - The discriminant is used to check the expression has one solution or does not have solutions.

 

If the answer is zero, then equation will have one solution. If the answer is negative, then equation will have two imaginery numbers as solutions.

 

The discriminant is - b²-4ac.

Keeping the values in equation - =6²-4*1*10

=36-40

=-4.

 

The solution is negative, which is not zero. Hence, it will have two imaginery numbers.

  • 4 answers

Vivek Rana 3 years, 9 months ago

After deleted syllabus of CBSE

Kripa Daga 3 years, 9 months ago

8

Harshika Yadav 3 years, 9 months ago

8

Aarohi Singh 3 years, 9 months ago

8
  • 1 answers

Gaurav Seth 3 years, 9 months ago

In order to answer this question, let us analyse the given data
It says that the depth = 3 metres
                         width = 40 metres
and the rate of flow = 2 km per hour
( converting this into metre per second, we get rate of flow = 2*(1000/3600)=2*(5/18)= 0.55 metre per second)
now we know that volume = length *width*height
similarly, volumetric rate of flow = length*width*rate of flow
which leaves us at v=3*40*0.55= 66.67 metre cube per second.
so the amount of flow per minute would be given by
 66.67*60 = 4000 metre cube per minute

  • 1 answers

Chaitanya Goravar 3 years, 9 months ago

A. 0-2(2)=4 0-4=4 -4=4 B. 2-2(0)=4 2=4 C. 4-2(0)=4 4=4 => This is the solution of equation x-2y=4 E. 1-2(1)=4 1-3=4 2=4
  • 1 answers

Ma Raikwar 3 years, 9 months ago

X=0. Y=14
  • 3 answers

Kripa Daga 3 years, 9 months ago

6cm

Meenkashi Singh 3 years, 9 months ago

Given, area of an equilateral triangle = 9√3 cm2 ∴ Area of an equilateral triangle = √3/4(Side)2 ⇒  √3/4 (Side)2 = 9√3 ⇒  (Side)2 = 36 ∴ Side = 6 cm  [taking positive square root because side is always positive] Hence, the length of an equilateral triangle is 6 cm.

Tanish Jain 3 years, 9 months ago

6 cm
  • 2 answers

Kripa Daga 3 years, 9 months ago

3√3

Meenkashi Singh 3 years, 9 months ago

Given, side of an equilateral triangle is 2√3 cm. Area of an equilateral triangle = √3/4 (Side)2 = √3/4 (2√3)2 = (√3/4) x 4 x 3 = 3√3 = 3 x 1.732 = 5.196 cm2 Hence, the area of an equilateral triangle is 5.196 cm2.
  • 2 answers

Meenkashi Singh 3 years, 9 months ago

Let each side of an equilateral be x. Then, perimeter of an equilateral triangle = 60 m x + x + x = 60 ⇒  3x = 60 ⇒  x = 60/3 = 20 m Area of an equilateral triangle = √3/4 (Side)2 = (√3/4) x 20 x 20 = 100 √3 m2 Thus, the area of triangle is 100√3 m2.

Gaurav Seth 3 years, 9 months ago

Let each side of an equilateral be x.
Then, perimeter of an equilateral triangle = 60 m
x + x + x = 60 ⇒  3x = 60 ⇒  x = 60/3 = 20 m
Area of an equilateral triangle = √3/4 (Side)2 = (√3/4) x 20 x 20 = 100 √3 m2
Thus, the area of triangle is 100√3 m2.

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