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Ask QuestionPosted by Gcm Tamizhan 3 years, 9 months ago
- 5 answers
Posted by Vikash Singh 3 years, 9 months ago
- 1 answers
Posted by Aditya Satwar 3 years, 9 months ago
- 1 answers
Posted by Likhitha N 3 years, 9 months ago
- 1 answers
Gaurav Seth 3 years, 9 months ago
We can do it by using Pythagoras Theorem.
We can write √10 = √(9 + 1)
=> √10 = √(32 + 1)
Construction
1. Take a line segment AO = 3 unit on the x-axis. (consider 1 unit = 2cm)
2. Draw a perpendicular on O and draw a line OC = 1 unit
3. Now join AC with √10.
4. Take A as center and AC as radius, draw an arc which cuts the x-axis at point E.
5. The line segment AC represents √10 units.
Posted by Nisha Murali 3 years, 9 months ago
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Riya Sharma💜🤞 3 years, 9 months ago
Posted by Nisha Murali 3 years, 9 months ago
- 1 answers
Yogita Ingle 3 years, 9 months ago
Total number of trials = 200
(i) P(getting 3 heads) = 
(ii) P(at least two heads) = 
(iii) P(two heads and one tail) = 
Posted by K. K. 3 years, 9 months ago
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Posted by Sana Mohammed Adam 3 years, 9 months ago
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Omveer Sehrawat 3 years, 9 months ago
Posted by Rachana Kumari 3 years, 9 months ago
- 4 answers
Omveer Sehrawat 3 years, 9 months ago
Posted by Manoj . 3 years, 9 months ago
- 3 answers
Kripa Daga 3 years, 9 months ago
Ibrahim Khalil 3 years, 9 months ago
Yogita Ingle 3 years, 9 months ago
Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named as Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°. The sides of a right triangle (say a, b and c) which have positive integer values, when squared, are put into an equation, also called a Pythagorean triple.
Consider the triangle given above:
Where “a” is the perpendicular side,
“b” is the base,
“c” is the hypotenuse side.
According to the definition, the Pythagoras Theorem formula is given as:
| Hypotenuse2 = Perpendicular2 + Base2
c2 = a2 + b2 |
Posted by Rohan King 3 years, 9 months ago
- 0 answers
Posted by Muskan Garg 3 years, 9 months ago
- 2 answers
Gaurav Seth 3 years, 9 months ago
It is given that ,
p = 2 - a -------( 1 )
LHS = a³ + 6ap + p³ - 8
= a³ + 6a( 2 - a ) + ( 2-a )³ - 8 [ from(1)]
= a³ +12a-6a²+2³-3×2²a+3×2a²-a³-8
= a³ + 12a - 6a² + 8 - 12a + 6a²- a³ - 8
= 0
= RHS
Hence proved.
Posted by Hardik Pandey 3 years, 9 months ago
- 1 answers
Yogita Ingle 3 years, 9 months ago
If we draw one diagonal to quadrilateral we will get two triangles i.e. △ABC and △ACD and we know that sum of the angles of a triangle is 180o
Sum of angles of quadrilateral ABCD=sum of angles of △ABC + sum of the angles △ACD
= 180o+180o
= 360o
Posted by P Nagaraju Nagaraju 3 years, 9 months ago
- 5 answers
Posted by Swatantra Yadav 3 years, 9 months ago
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Yogita Ingle 3 years, 9 months ago
Steps of Construction:
1.Draw a line segment PQ = 11 cm.( = AB + BC + CA).
2.At P construct an angle of 60° and at Q, an angle of 45°.
3.Bisect these angles. Let the bisectors of these angles intersect at a point A.
4.Draw perpendicular bisectors DE of AP to intersect PQ at B and FG of AQ to intersect PQ at C.
5.Join AB and AC (see Fig. 11.9). Then, ABC is the required triangle.
Posted by Komal Jaiswal 3 years, 9 months ago
- 1 answers
Yogita Ingle 3 years, 9 months ago
Sin30°=1/2
sin90°=1
cos0°=1
tan30°=1√3
tan60°=√3
now putting these these value on question
so..we find
=1/2-1+2×1/1/√3 ×√3
=1/2-1+2/√3/√3
=1-2+4/2
=3/2
Posted by Kaustuk Sharma 3 years, 9 months ago
- 5 answers
Posted by Yash Yash 3 years, 9 months ago
- 2 answers
Ashmita Das 3 years, 9 months ago
Yogita Ingle 3 years, 9 months ago
A pipe will have two layers as shown in picture.
There is a inner Cylinder and Outer Cylinder.
Inner Radius = Inner Diameter / 2 = 4 / 2 = 2 cm = r
Outer Radius = Outer Diameter / 2 = 4.4/2 = 2.2 cm = R
Height of the pipe = 77 cm = h
Inner Surface area of the Pipe = 2∏rh = 2×22×2×77/7 = 968 Square cm.
Outer Surface area of the pipe = 2∏Rh = 2×22×2.2×77/7 = 1064.8 Square cm.
Total Surface area = Inner Surface area + Outer Surface area + 2 × Cross section surface area.
The cross section suface area is present at two ends of the pipe.
This is the area covered between 2 circles.
Total Surface area = Inner Surface area + Outer Surface area + 2 × Cross section surface area.
= 968 + 1064.8 + 2×∏(R^2 – r^2)
= 2032.8 + 2×22×(2.2×2.2 – 2×2)/7
= 2032.8 + 5.28
= 2038.08 Square cm.
Posted by Vivek Singh 3 years, 9 months ago
- 1 answers
Yogita Ingle 3 years, 9 months ago
84-2n-2n²
= 2(42-n-n²) /* Taking 2 common */
= 2( 42 - 7n + 6n - n²) /* splitting the middle term */
= 2[7(6-n)+n(6-n)]
= 2(6-n)(7+n)
Therefore,.
2, (6-n) and (7+n) are factors of given quadratic expression.
Posted by Damini Damini 3 years, 9 months ago
- 1 answers
Posted by Anish Kumar 3 years, 9 months ago
- 2 answers
Shalini Kumari 3 years, 9 months ago
Posted by Damini Damini 3 years, 9 months ago
- 1 answers
Gaurav Seth 3 years, 9 months ago
Let r be the radius of a vessel.
Given: cost to paint the inner curved surface area= ₹2200
Cost to paint per m²= ₹20 & height of vessel (h)= 10 m
Curved surface area= 2πrh
Inner curved surface area=cost to paint the inner curved surface area/cost of paint per m²
2πrh= 2200/20= 110 m²
2× 22/7×r× 10= 110
r=(110×7)/(2×220)= 7/4= 1.75m
i)
Inner curved surface area of the vessel= 110 m²
ii)
Radius of the base radius of the base= 1.75 m
iii) capacity of The vessel= volume of the vessel
=πr²h= 22/7×7/4×7/4×10= 96.25 m³
= 96.25× 1000 L= 96.25 kL
[ 1 m= 100cm, 1 m³= 100 cm³
1000 cm³= 1L, 1000L= 1kL]
capacity of The vessel= 96.25 kL
Posted by Damini Damini 3 years, 9 months ago
- 1 answers
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Zaid . 3 years, 9 months ago
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