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Ask QuestionPosted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
Ans. For an equilateral triangle with side ‘a’, area
∴ Each side of the triangle = a cm
∴ a + a + a = 180 cm
⇒ 3a = 180 cm
Now, s = Semi–perimeter 
∴ Area of a triangle
∴ Area of the given triangle
Thus, the area of the given triangle
Posted by Neshok Ls 5 years, 1 month ago
- 0 answers
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
Answer:
- Area of triangle = 12 cm²
Step-by-step explanation:
Given:
- Two equal sides of isosceles triangle = 5 cm
- Third side = 8 cm.
To Find:
- Area of isosceles triangle by Heron's Formula.
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
Answer:
50.28 or 352/7
Step-by-step explanation:
Given,
Slant height = 5 cm
Radius = 4 cm
Let Height be x cm
So for finding height we have to use Pythagorean Theorem,
(5)² = (4)² + (x)²
√25 -16 = x
√9 = x
so, x = 3
Height = 3 cm
Volume of Cone = 1/3πr²h
= 1/3×22/7×4×4×3
= (22×16)/7
= 352/7
If you make this fraction in decimal form answer is
50.28
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
Given: In quadrilateral ACBD, AC = AD and AB bisects ∠A.
To Prove: ∆ABC ≅ ∆ABD.
Proof: In ∆ABC and ∆ABD,
AC = AD | Given
AB = AB | Common
∠CAB = ∠DAB
| ∵ AB bisects ∠A
∴ ∠ABC ≅ ∠ABD | SAS Rule
∴ BC = BD | C.P.C.T,
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
The surface area of a sphere of radius r is 4πr 2
. Half of this is 2πr 2
.
If you have a hemispherical object then it has a base which is a circle of radius r.
The area of a circle of radius r is πr 2
and thus if the hemisphere is meant to include the base then the surface area is 2πr 2 +πr 2
=3πr 2
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
(d) 50°, 50°
Given, QPR is 80 degrees
and PQ=PR
let the other two angles be x,x because it is an isosceles triangle
by triangle sum property
80+x+x=180
2x+80=180
2x=100
x=50
therefore angle R and angle Q are 50 degrees
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
We know, The interior angles of a triangle always add up to 180.
So, statement A, B and C is not correct.
(C) An exterior angle of a triangle is always greater than the opposite interior angles.
is correct
Answer (C) An exterior angle of a triangle is always greater than the opposite interior angles.
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
The angle subtended by the diameter of a semicircle is 90o
To prove : ∠APB=90o
∵ We know angle subtended by an arc at centre is double the angle subtended at any point or circumference.
⇒ Angle subtended by arc AB at O= Double the angle subtended at P
⇒∠AOB=2∠APB
∵AOB is a straight line.
⇒∠AOB=1800
⇒2∠APB=180o
⇒∠APB=90o
∴ Angle subtended by arc AB or semi circle is 90o
<section> </section>Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Posted by Neshok Ls 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
Given:
- The sides of the triangle are 8cm,11cm and 13cm.
Need to find:
- Area of the triangle
a = 8cm
b = 11cm
c = 13cm
Perimeter of the ∆ = a+b+c
Semi-perimeter = a+b+c/2
Area of ∆
Posted by Muddassir Faiz 5 years, 1 month ago
- 1 answers
Yogita Ingle 5 years, 1 month ago
9(x+7)-6=9-2(x+9)
9x + 63 = 9 -2x - 18
9x + 2x = 9 - 18 - 63
7x = -9-63
7x = - 72
x = -72/7
x = - 10.28
Posted by Minku Rani 5 years, 1 month ago
- 2 answers
Posted by Prakhar Parashar 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
Given - x²+6x+10
Find - To show the equation has no zero.
Answer - The discriminant is used to check the expression has one solution or does not have solutions.
If the answer is zero, then equation will have one solution. If the answer is negative, then equation will have two imaginery numbers as solutions.
The discriminant is - b²-4ac.
Keeping the values in equation - =6²-4*1*10
=36-40
=-4.
The solution is negative, which is not zero. Hence, it will have two imaginery numbers.
Posted by Vivek Rana 5 years, 1 month ago
- 4 answers
Posted by Warish Saifi 5 years, 1 month ago
- 1 answers
Gaurav Seth 5 years, 1 month ago
In order to answer this question, let us analyse the given data
It says that the depth = 3 metres
width = 40 metres
and the rate of flow = 2 km per hour( converting this into metre per second, we get rate of flow = 2*(1000/3600)=2*(5/18)= 0.55 metre per second)
now we know that volume = length *width*height
similarly, volumetric rate of flow = length*width*rate of flow
which leaves us at v=3*40*0.55= 66.67 metre cube per second.
so the amount of flow per minute would be given by
66.67*60 = 4000 metre cube per minute
Posted by Shravya B L 5 years, 1 month ago
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Chaitanya Goravar 5 years, 1 month ago
Posted by Kshitiz Jain 5 years, 1 month ago
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Posted by Adarsh Dubey 5 years, 1 month ago
- 3 answers
Meenkashi Singh 5 years, 1 month ago
Posted by Adarsh Dubey 5 years, 1 month ago
- 2 answers
Meenkashi Singh 5 years, 1 month ago
Posted by Adarsh Dubey 5 years, 1 month ago
- 2 answers
Meenkashi Singh 5 years, 1 month ago
Gaurav Seth 5 years, 1 month ago
Let each side of an equilateral be x.
Then, perimeter of an equilateral triangle = 60 m
x + x + x = 60 ⇒ 3x = 60 ⇒ x = 60/3 = 20 m
Area of an equilateral triangle = √3/4 (Side)2 = (√3/4) x 20 x 20 = 100 √3 m2
Thus, the area of triangle is 100√3 m2.
Posted by Arza Tomar 5 years, 1 month ago
- 2 answers
Meenkashi Singh 5 years, 1 month ago
Posted by Devansh Mittal 5 years, 1 month ago
- 2 answers
Meenkashi Singh 5 years, 1 month ago
Gaurav Seth 5 years, 1 month ago
- Prove that the line drawn through the center of a circle to bisect a chord is perpendicular to the chord.
Given :-
- O is the center of circle
- AB is chord of circle
- OX bisects AB i.e. AX = BX
To Prove :-
- OX ⊥ AB
Explanation :-
➠ In ∆AOX and ∆BOX,
➠ On line AB,
Hence, ∠AXO and ∠BXO form a linear pair
Hence, Proved.
Posted by Harish Kumar 5 years, 1 month ago
- 1 answers
Posted by Gurmeet Kelawat 5 years, 1 month ago
- 1 answers
Hemang Mittal 5 years, 1 month ago
Posted by Subhendu Mohanta 5 years, 1 month ago
- 2 answers
Gaurav Seth 5 years, 1 month ago
Bhavya has a piece of canvas whose area is 552 m2. She uses it to make a conical tent with a base radius of 7 m. Assuming that all the stiching margins and the wastage incurred while cutting amounts to approximately 2 m2, find the volume of the tent that can be made with it.
r = 7 cm
Posted by Mitali Vani 5 years, 1 month ago
- 2 answers
Gaurav Seth 5 years, 1 month ago
Deleted portion:
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UNIT I-NUMBER SYSTEMS |
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Chapter |
Topics |
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REAL NUMBERS |
· Representation of terminating / non-terminating recurring decimals on the number line through successive magnification. · Explaining that every real number is represented by a unique point on the number line and conversely, viz. every point on the number line represents a unique real number. · Definition of nth root of a real number. |
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UNIT II-ALGEBRA |
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Chapter |
Topics |
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POLYNOMIALS |
· Motivate and State the Remainder Theorem with examples. Statement and proof of the Factor Theorem. · x3+y3+z3-3xyz |
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LINEAR EQUATIONS IN TWO VARIABLES |
Examples, problems on Ratio and Proportion |
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UNIT III-COORDINATE GEOMETRY |
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Chapter |
Topics |
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COORDINATE GEOMETRY |
No deletion |
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UNIT IV-GEOMETRY |
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Chapter |
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INTRODUCTION TO EUCLID'S GEOMETRY |
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LINES AND ANGLES |
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TRIANGLES |
Proof of the theorem deleted- Two triangles are congruent if any two angles and the included side of one triangle is equal to any two angles and the included side of the other triangle (ASA Congruence). Topic Deleted-Triangle inequalities and relation between ‘angle and facing side' inequalities in triangles |
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QUADRILATERALS |
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AREA |
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CIRCLES |
There is one and only one circle passing through three given non-collinear points. If a line segment joining two points subtends equal angle at two other points lying on the same side of the line containing the segment, the four points lie on a circle. |
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CONSTRUCTIONS |
Construction of a triangle of given perimeter and base angles |
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UNIT V- Mensuration |
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Chapter |
Topics |
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UNIT VI-MENSURATION |
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AREA |
Application of Heron’s Formula in finding the area of a quadrilateral. |
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SURFACE AREAS AND VOLUMES |
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UNIT VI-STATISTICS & PROBABILITY |
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Chapter |
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STATISTICS |
· Histograms (with varying base lengths), · Frequency polygons. · Mean, median and mode of ungrouped data. |
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PROBABILITY |
No deletion |
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Gaurav Seth 5 years, 1 month ago
Given,
Diameter = d = 84cm
Radius = r = d/2 = 42cm
Length = l = 120 cm
T.S.A of cylinder = 2πrh
= 2 x 22/7 x 42 x 120
= 31680 cm²
Area levelled by 500 revolution = Area of playground
= 500 x 31680cm²
= 15840000 cm² [ change into m]
= 1584 m²
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