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Ask QuestionPosted by Zakiya Malik 5 years, 3 months ago
- 2 answers
Gaurav Seth 5 years, 3 months ago
1. x/2 – 1/5 = x/3 + ¼
Solution:
x/2 – 1/5 = x/3 + ¼
⇒ x/2 – x/3 = ¼+ 1/5
⇒ (3x – 2x)/6 = (5 + 4)/20
⇒ 3x – 2x = 9/20 × 6
⇒ x = 54/20
⇒ x = 27/10
2. n/2 – 3n/4 + 5n/6 = 21
Solution:
n/2 – 3n/4 + 5n/6 = 21
⇒ (6n – 9n + 10n)/12 = 21
⇒ 7n/12 = 21
⇒ 7n = 21 × 12
⇒ n = 252/7
⇒ n = 36
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<a data-ved="2ahUKEwj3ktPzp9rtAhVDcCsKHRPoA1wQFjAAegQIBBAC" href="https://mycbseguide.com/blog/ncert-solutions-class-8-maths-exercise-2-5/" ping="/url?sa=t&source=web&rct=j&url=https://mycbseguide.com/blog/ncert-solutions-class-8-maths-exercise-2-5/&ved=2ahUKEwj3ktPzp9rtAhVDcCsKHRPoA1wQFjAAegQIBBAC" rel="noopener" target="_blank">NCERT Solutions for Class 8 Maths Exercise 2.5 ...</a>
Posted by Sampada Singh 5 years, 3 months ago
- 1 answers
Pratiksha Singh 5 years, 3 months ago
Posted by Suraj Mishra 5 years, 3 months ago
- 1 answers
Posted by Ajay Saini 5 years, 3 months ago
- 0 answers
Posted by Sneha 5 years, 3 months ago
- 0 answers
Posted by Sundram Jha 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Length of cuboid=8+8-8=24cm
b.=8cm
he.=8cm
area of cuboid=2(lb+BH+hl)
=2(24×8+8×8+8×24)
=2(192+64+192)
=2×448
=896cm2
Posted by Sundram Jha 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Given that hall of Length = 20 m, Breadth = 14 m, Height = 6 m.
∴Volume of the hall = length × breadth × height
= 20 × 14 × 6
= 1680 m3
Volume occupied by 1 man = 7m3
Therefore, number of men that can be accommodated = 1680 /7 = 240.
Posted by Ashwini Vinod 5 years, 3 months ago
- 2 answers
Yogita Ingle 5 years, 3 months ago
M1D1 = M2D2
15 × 12 = M2 × 6
M2 = 15×12/6
M2 = 15×2
m2 =30 men
Gaurav Seth 5 years, 3 months ago
Answer:
30 men
Step-by-step explanation:
In 12 days 15 men can do the work
In 1 day 12*15 men can do the work
In 6 days 12*15/6 men can do the work
so, in 6 days 30 men can do the work
Posted by Payal Sharma 5 years, 3 months ago
- 0 answers
Posted by Manik Kumar Sah 5 years, 3 months ago
- 1 answers
Posted by Ashish Kumar 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
It is given that a rhombus of perimeter 20 cm and one base angle is the supplement of 130 degree
From the given information we get 1 side of rhombus = 20/4 = 5cm
One angle = 130° therefore the adjacent angle = 180 - 130 = 50°
Drawing of rhombus
Step1: draw a line segment AB of 5 cm
Step 2: Draw line AX from A making an angle of 130° with AB and draw a line BY from B making an angleof 50° with AB
Step 3: Mark a point on AX as D such that AD = 5cm
Step 4: Mark a point on BY as C such that BC = 5cm
ABCD is arhombus of perimeter 20 cm and one base angle is the supplement of 130 degree
Posted by Lakshme Ganth 5 years, 3 months ago
- 2 answers
Laxmi Yadav 5 years, 3 months ago
Posted by Akshita Kainthola 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Given that, surface area of cube = 600 cm^2
Let the length of each side of cube be l.
Surface area of cube = 6 (Side)2
600 cm2 = 6 l2
l 2= 100 cm2
l = 10 cm
Thus, the side of the cube is 10 cm.
Posted by Akash P 5 years, 3 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
A n s w e r
6 × 6 × 6 = 2 1 6
Any number with 6 at the unit's place multiplied 3 times give 6 at unit's place in the cube of the number.
Posted by Komal Srishti 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
given,
the area of square is=5184m²
s×s=5184
s²=5184
s=√5184
s=72
according to problem,
l=2x
b=x
we know that,
perimeter of square=perimeter of rectangle
4s=2(l+b)
4×72=2(2x+x)
288=6x
x=288/6
x=48
from problem,
l=2x
=2×48
=96
b=x
=48
therefore length is 96
breadth is 48
area of rectangle = l × b
= 96 × 48
=4608 m²
Posted by Pranamya Nagar 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
As the formula states CP=(100/(100+Gain%))×SP
=(100/(100+12))×1596
=(100/112)×1596
=1425
∴ The cost price is ₹1425
Posted by Nishtha Nimiwal 5 years, 3 months ago
- 1 answers
Posted by Raghu Sharma 5 years, 3 months ago
- 3 answers
Revanth Reddy 5 years, 3 months ago
Posted by Sakshi Chouhan 5 years, 3 months ago
- 1 answers
Sakshi Chouhan 5 years, 3 months ago
Posted by Sakshi Chouhan 5 years, 3 months ago
- 1 answers
Sakshi Chouhan 5 years, 3 months ago
Posted by Sakshi Chouhan 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
When two dice are rolled, the number of outcomes is 36.
The only even prime number is 2.
Let E be the event of getting an even prime number on each die.
∴E={(2,2}
⇒P(E)=1/ 36
Posted by Sakshi Chouhan 5 years, 3 months ago
- 0 answers
Posted by Sakshi Chouhan 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
The general form of Pythagorean triplets
Pythagorean triples are a2+b2 = c2 where a, b and c are the three positive integers. These triples are represented as (a,b,c). Here, a is the perpendicular, b is the base and c is the hypotenuse of the right-angled triangle.
Posted by Praveen Neema 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
As we know 2m, m2+1 and m2−1 from a Pythagorean triplet for any number , m>1
Let us assume 2m=6
Therefore, m =3
And m2+1=32+1=9+1=10
And m2−1=32−1=9−1=8
Test : 62+82=36+64=100=102
Hence the triplet is 6,8, and 10
Posted by Sundram Jha 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
length = 10cm
breadth = 5cm
height = 3cm
here we have to find the cost of the cardboard required to make the open cuboidal box.
so we will use CSA + 1 base formula.
CSA + 1 base of the cuboidal box = 2h (l + b) + lb
= 2 × 3 (10 + 5) + (10 × 5)
= 6 (15) + 50
= 90 + 50
= 140cm²
now we have to find the cost of cardboard @ of 0.5 rupees (50 Paisa) per cm² = 140 × 0.5
= 70 rupees.
Posted by Sundram Jha 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
ABCD be the given trapezium in which AB = 20 cm, DC = AE= 10 cm, BC = 13 cm and AD = 13cm.
Through C, draw CE || AD, meeting AB at E.
Draw CF ⊥ AB.
Now, EB = (AB - AE) = (AB - DC)
EB = (20- 10) cm = 10 cm;
CE = AD = 13 cm; AE = DC = 13 cm.
Now, in ∆EBC, we have CE = BC = 13 cm.
It is an isosceles triangle.
Also, CF ⊥ AB
So, F is the midpoint of EB.
Therefore, EF = ¹/₂ × EB = 1/2× 10= 5cm.
Thus, in right-angled ∆CFE, we have CE = 13 cm, EF = 5 cm.
By Pythagoras’ theorem, we have
CF = [√CE² - EF²]
CF = √(13² - 5²)
CF= √169-25= √144 = √12×12
CF= 12cm
Thus, the distance between the parallel sides is 12 cm.
Area of trapezium ABCD = ¹/₂ × (sum of parallel sides) × (distance between them)
Area of trapezium ABCD = ¹/₂ × (20 + 10) × 12 cm²
Area of trapezium ABCD = 1/2×(30)× 12
Area of trapezium ABCD= 30×6 = 180 cm²
Hence, Area of trapezium ABCD= 180 cm²
Posted by Abhishek Abhinav 5 years, 3 months ago
- 3 answers
Yogita Ingle 5 years, 3 months ago
A triangular prism is polyhedron and a three-dimensional shape that has 5 faces, 6 edges and 9 vertices.
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Kishun Yadav 5 years, 3 months ago
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