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Ask QuestionPosted by Sunaiba Ifat 5 years, 3 months ago
- 3 answers
Posted by Maahi Patel 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
x2+ 4x + 4 = x2 + 2x + 2x + 4
= x (x + 2) + 2 (x + 2)
= (x + 2) (x + 2)
Posted by Maahi Patel 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
x2+ 4x + 4 = x2 + 2x + 2x + 4
= x (x + 2) + 2 (x + 2)
= (x + 2) (x + 2)
Posted by Vansh Sharawat 5 years, 3 months ago
- 3 answers
Nakshi Shah 5 years, 3 months ago
Hardik Garg 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
(7a + 5b)² + (5a + 7b)²
= (7a)2 + (5b)2 + 2(35ab) + (5a)2 + (7b)2 + 2(35ab)
= 49a2 + 25b2 + 70ab + 25a2 + 49b2 + 70ab
= 49a2 + 25a2 + 25b2 + 49b2 + 70ab + 70 ab
= 74a2 + 74b2 + 140ab
Posted by Banarasiya Don???? 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Area of the field
= Area of upper triangle + Area of Lower triangle
= 1/2 ×6×24+ 1/2 × 12× 24
= 3 × 24 + 6 × 24
=72 + 144
=216 sq m
Posted by Falguni Atd 5 years, 3 months ago
- 2 answers
Hardik Garg 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
The one's digit of the square of a no. could be found using the the unit digit of the no. itself .So the one's digits of given no.s are :
- 1234 : 6
- 26387 ; 9
- 52698 ; 4
- 21222 ; 4
- 9106 ; 6
- 99880 ; 0
Posted by Khushi Kaur 5 years, 3 months ago
- 0 answers
Posted by Saloni Badole 5 years, 3 months ago
- 0 answers
Posted by Jeena Bajaj 5 years, 3 months ago
- 3 answers
Posted by Prachi Saxena 5 years, 3 months ago
- 2 answers
Hardik Garg 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
Length of the cuboid = 8 cm
Breadth of the cuboid = 6 cm
Height of the cuboid = 3.5 cm
Volume of the cuboid = length × breadth × height = 8 x 6 x 3.5 = 168cm3
Therefore,volume of the cuboid = 168cm3
Posted by Sundram Jha 5 years, 3 months ago
- 2 answers
Hardik Garg 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
Diameter of cylindrical container(d) = 14 cm
Radius of cylindrical container (r) = 7 cm
Height of cylindrical container (h)= 20 cm
Height of the label (h) = 20 –(2 +2)= 20 – 4= 16
h= 16 cm
Curved surface area of label = 2πrh
= 2 × 22/7× 7× 16
= 44× 16
= 704 cm²
Hence, the area of the label = 704 cm²
Posted by Sundram Jha 5 years, 3 months ago
- 4 answers
Yogita Ingle 5 years, 3 months ago
1 m = 100 cm.
Circumference of Roller = pie × Diameter.
= 22/7 × 98
= 22 × 14
= 308cm.
Length of road = 800 × 308
= 246, 400cm.
Width of Roller = length of roller = 100cm.
Therefore ,
Area of road = l × b
= 246400 × 100
= 24640000 cm2.
=2464 m2.
Garima Singh 5 years, 3 months ago
Garima Singh 5 years, 3 months ago
Posted by Sundram Jha 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Length of room = 25 m
Breadth of room = 18 m
Area of floor =
Area of the ceiling =
Area of four walls = 2(l+b)h=2(25+18)h
So, The sum of the area of the area of the floor and the ceiling is equal to the sum of the four walls of the room
10.465=h
Hence the height of the room is 10.465
Posted by Garima Singh 5 years, 3 months ago
- 2 answers
Garima Singh 5 years, 3 months ago
Posted by Sundram Jha 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
We know that
Area of Closed Cylinder = Curved Surface Area of Cylinder + 2(Area of Circle)
=>
=>
,
Substituting the values in the Formula, we get,
=>
Posted by Sundram Jha 5 years, 3 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
Given that length of the open iron tank = 20 m.
Breadth of the closed iron tank = 10 m
The height of the closed iron tank = 8 m.
Surface Area of the tank = 2[ bh + hl]
= 2[10×8+8×20] = 2×240=480m^2
Area of the rectangular iron sheet = 480m^2
so that length × breadth = 480m^2
But breadth of sheet = 4 m (given)
∴ length = 480 / 4 = 120 m .
Given that cost of iron, the sheet used at the rate of Rs 5 per metre.
The total cost of the sheet = Rs. (120 × 5) = Rs. 600.
Posted by Muskan Malik 5 years, 3 months ago
- 1 answers
Posted by Crazy9 Gaming 5 years, 3 months ago
- 1 answers
Posted by Isha ?? 5 years, 3 months ago
- 1 answers
Richie The Rich 5 years, 3 months ago
Posted by Isha ?? 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
195 *205
= (200 - 5)(200 + 5)
= (200)2 - (5)2 ((a - b) (a + b) = a2 - b2)
= 40000 - 25
= 39,975
Posted by Sunaiba Ifat 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
a²+8a+15
= a²+5a + 3a+15
= a(a+5) + 3 ( a +5)
= (a+3) (a+5)
Posted by Bisla Chingkheimayum 5 years, 3 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
Let ABCD be the rhombus where AC = 10 cm and BD = 24 cm.
Let AC and BD intersect each other at O.
Now, diagonals of rhombus bisect each other at right angles.
Thus, we have
Since AOB is a right angled triangle, by pythagoras theorem, we have
Hence, AB = 13
Thus, length of each side of rhombus is 13 cm.
Posted by Sameer Kumar Chhimpa 5 years, 3 months ago
- 1 answers
Posted by Aaryan Singh Chouhan 4 years, 11 months ago
- 1 answers
Sia ? 4 years, 11 months ago
Posted by Aaryan Singh Chouhan 5 years, 3 months ago
- 2 answers
Gaurav Seth 5 years, 3 months ago
We have P = Rs 8000, R = 5% p.a., T = 2 years
∵ 
∴ 
= 
= Rs (20 
21 
) = Rs 8820
Now, compound interest = A - P
= Rs 8820 - Rs 8000
= Rs 820
Posted by Aaryan Singh Chouhan 5 years, 3 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
We have P = Rs 8000, R = 5% p.a., T = 2 years
∵
∴
=
= Rs (20 21 ) = Rs 8820
Now, compound interest = A - P
= Rs 8820 - Rs 8000
= Rs 820
Posted by Tanishka Meena 5 years, 3 months ago
- 2 answers
Posted by Ritika Yadav 5 years, 3 months ago
- 1 answers
Gaurav Seth 5 years, 3 months ago
Let one supplement angle = x
Twice of supplement angle = 2 x
so we know two supplement angle = 1 8 0°
Then
x + 2 x =1 8 0°
3 x = 180°
x = 180 ÷ 3 = 60°
2 × 6 0 = 1 2 0 °
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Shruti ? 5 years, 3 months ago
1Thank You