Incorrect URL accessed!!!!

ANSWER

Gufy99c9

Posted by Arnab Sandilya 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Sia ? 4 years, 6 months ago

Please ask question with complete information.

ANSWER

a⁴-6a²b²+9b⁴ -(-a⁴-a²b²-4b⁴)

Posted by Ronit Singh 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Divya Chouhan 4 years, 10 months ago

Wrddfh

Shruti ? 4 years, 11 months ago

a⁴+a²b²+b⁴ = (a² +b²)² - 2a²b² + a²b² = (a²+b²)² - a²b² = (a²+b²)² - (ab)² now it is in the form of a² - b² =( a+ b)(a-b) (a²+b²+ab)(a²+b² - ab) 2) a⁴-6a²b²+9b⁴ [(a²)² - 2 × a² × 3b² + (3b²)² ] (a² - 3b²)² Answer - (a²+b²+ab)(a²+b² - ab)(a² - 3b²)²

ANSWER

What should be added to m²+MX+X² to obtain 2m²-3mn

Posted by Ruchi Verma 4 years, 11 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

(4x+5) (4x-1)

Posted by Jyoti Saini 4 years, 11 months ago

CBSE > Class 08 > Mathematics

3 answers

Shruti ? 4 years, 11 months ago

(4x+5)(4x-1) = (x+a)(x+b) = x²+(a+b)x + ab = 4x² + (5-1)4x + 5×(-1) = 16x² + 16x -5

Yogita Ingle 4 years, 11 months ago

(4x+5) (4x-1)

4x ( 4x - 1) + 5 (4x - 1)

= 16x² - 4x + 20x - 5

=16x² + 16x - 5

Gayathri Mohanraju 4 years, 11 months ago

ANSWER

Cost price 73440 profit 8% .find the sp and profit

Posted by Prince Yadav 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 4 years, 11 months ago

Cost price 73440 profit 8% .find the sp and profit

% Profit = Profit/cp × 100

8 = Profit/73440 × 100

8 × 7344/ 10 = profit

Profit = 5,875.20

SP = CP + Profit

= 73440 + 5,875.20

= 79,315.2

ANSWER

The length and the breadth of a rectangle are in the ratio 4:3 .If perimeter 154cm find its length and breadth.

Posted by Uttarkhand Uk 4 years, 11 months ago

CBSE > Class 08 > Mathematics

4 answers

Divyansh Jain 4 years, 11 months ago

Let the length be 4x and breadth be 3x. Given, Perimeter = 154 cm 2 ( Length + Breadth) = Perimeter of Rectangle 2 ( 4x + 3x ) = 154 2 ( 7x ) = 154 2 × 7x = 154 14x = 154 x = 154÷14 x = 11 Length = 4x = 4×11 cm = 44 cm Breadth = 3x = 3×11 cm = 33 cm

Jayanthasena E.L 4 years, 11 months ago

length is 44cm and breadth is 33cm.

Taneesha Bhania 4 years, 11 months ago

Let, l=4x cm and b= 3x cm The perimeter of rectangle= 154cm Perimeter of rectangle=2(l+b) 154 is equals to 2(4x + 3x) 154= 14x X= 154 is divided by 14 X= 11 L= 4x= 4×11= 44 B= 3x= 3×11= 33 So, the write ans. Is 44cm and 33cm

Yogita Ingle 4 years, 11 months ago

Let, the length is 4x cm and the breadth is 3x cm

The perimeter of rectangle is 154 cm

Perimeter of rectangle = 2 ( l + b )

154 = 2 ( 4x + 3x )

154 = 2 ( 7x )

154 = 14x

x = 11

Length = 4x = 4×11 = 44cm

Breadth = 3x = 3×11 =33cm

ANSWER

Find the area of a rhombus whose one side is measure 5cm and other is 8cm.

Posted by Uttarkhand Uk 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Anju Gahlot 4 years, 11 months ago

Yogita Ingle 4 years, 11 months ago

Let ABCD be the given rhombus with diagonals AC and BD which intersect each other at O such that AC = 8 cm.

Since diagonals of a rhombus bisect each other, we get

Let BO = x and AB = 5 cm (given).

We know that diagonals of a rhombus cut each other at right angles. So ΔAOB is a right angled triangle.

Using Pythagoras theorem in ΔAOB, we get

x = 3 cm

Thus the length of another diagonal BD is,

BD = 2x = 6 cm.

Therefore the area of the rhombus is given by,

Area of rhombus =

Area(ABCD) =

Area of a rhombus is 24 .

ANSWER

the area of a rhombus is 16cm ² and the length of its diagonal is 4cm. calculate the length of other diagonal

Posted by Uttarkhand Uk 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Anju Gahlot 4 years, 11 months ago

8cm

Yogita Ingle 4 years, 11 months ago

<pre> Area of rhombus = ½ × d₁× d₂ ⇒ 16 = ½ × 4 × d2 So, d₂= 32/4 = 8 cm</pre>

ANSWER

What is 888888888^2

Posted by Mahitha Gundala 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Sandesh Shirke 4 years, 11 months ago

7.901234552098E17

Saumya Kumar 4 years, 11 months ago

790123455017

ANSWER

X²+xy+8x+8y

Posted by Adishree Bansal 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 4 years, 11 months ago

X²+xy+8x+8y

= x ( x + y) + 8 ( x+ y)

= (x + y) ( x + 8)

ANSWER

How to download video from this video , please tell me

Posted by Sandeep Kumar 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Tanishka Sharma 4 years, 11 months ago

There is no way to download this video in your gallery...or you can record your mobile screen while the video is on...hope you got your answer

Adishree Bansal 4 years, 11 months ago

Who will answer my question

ANSWER

My maths skills are so weak so, please suggest me how I improve my maths

Posted by Asmi Sharma 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Zibiah Gonsalves 4 years, 11 months ago

Solve maths problems for at least half an hour everyday

ANSWER

How much amount does he need to pay to make the field ready for transplantation by ploughing thrice?

Posted by Shylesh Reddy 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Sia ? 4 years, 6 months ago

Please ask question with complete information.

ANSWER

Find the square of the following numbers

Posted by Bhat Irtiqa?? 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Shylesh Reddy 4 years, 11 months ago

Ncert solutions Grade 8 Mathematics Science Chapters in NCERT Solutions - Mathematics , Class 8 Exercises in Squares and Square Roots Question 1 Q1) Find the square of the following numbers. (i) 32 (ii) 35 (iii) 86 (iv) 93 (v) 71 (vi) 46 Solution Transcript Solution: (i) \left(32\right)^2=\left(30+2\right)^2=\left(30\right)^2+2\times30\times2+\left(2\right)^2(32) 2 =(30+2) 2 =(30) 2 +2×30×2+(2) 2 [\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b) 2 =a 2 +2ab+b 2 ] = 900 + 120 + 4 = 1024 (ii) \left(35\right)^2=\left(30+5\right)^2=\left(30\right)^2+2\times30\times5+\left(5\right)^2(35) 2 =(30+5) 2 =(30) 2 +2×30×5+(5) 2 [\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b) 2 =a 2 +2ab+b 2 = 900 + 300 + 25 = 1225 (iii) \left(86\right)^2=\left(80+6\right)^2=\left(80\right)^2+2\times80\times6+\left(6\right)^2(86) 2 =(80+6) 2 =(80) 2 +2×80×6+(6) 2 [\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b) 2 =a 2 +2ab+b 2 = 8100 + 540 + 9 = 8649 (iv) \left(93\right)^2=\left(90+3\right)^2=\left(90\right)^2+2\times90\times3+\left(3\right)^2(93) 2 =(90+3) 2 =(90) 2 +2×90×3+(3) 2 [\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b) 2 =a 2 +2ab+b 2 ] = 8100 + 540 + 9 = 8649 (v) \left(71\right)^2=\left(70+1\right)^2=\left(70\right)^2+2\times70\times1+\left(1\right)^2(71) 2 =(70+1) 2 =(70) 2 +2×70×1+(1) 2 [\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b) 2 =a 2 +2ab+b 2 = 4900 + 140 + 1 = 5041 (vi) \left(46\right)^2=\left(40+6\right)^2=\left(40\right)^2+2\times40\times6+\left(6\right)^2(46) 2 =(40+6) 2 =(40) 2 +2×40×6+(6) 2 [\because\left(a+b\right)^2=a^2+2ab+b^2∵(a+b) 2 =a 2 +2ab+b 2 ] = 1600 + 480 + 36 = 2116

ANSWER

(Y²+7y+10)÷(y+5)

Posted by Khushi Soni 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Khushi Soni 4 years, 11 months ago

(Y²+7y+10)/(y+5) Y(y+5)+2(y+5)/(y+5) (Y+2) Final answer = (y + 2)

Khushi Soni 4 years, 11 months ago

(Y²+7y+10)/(y+5)

ANSWER

2×3×3÷4+5

Posted by Learn Something New 4 years, 11 months ago

CBSE > Class 08 > Mathematics

5 answers

Mohd Talha 4 years, 11 months ago

Soham Mahansaria 4 years, 11 months ago

Mohamed Fazil 4 years, 11 months ago

9.5 is correct answer

Payal Sharma 4 years, 11 months ago

Simple and compound interest

Unnati Singh 4 years, 11 months ago

9.5

ANSWER

Defination of polygon

Posted by Myana Manishka 4 years, 11 months ago

CBSE > Class 08 > Mathematics

5 answers

Nakshi Shah 4 years, 11 months ago

Not three but line segment

Nakshi Shah 4 years, 11 months ago

A closed figure with 3 line segments Is called polygon

Shruti ? 4 years, 11 months ago

A closed figure which is made up of line segment is known as polygon

Yogita Ingle 4 years, 11 months ago

A Polygon is a closed figure made up of line segments (not curves) in a two-dimensional plane. Polygon is the combination of two words, i.e. poly (means many) and gon (means sides).

A minimum of three line segments is required to connect end to end, to make a closed figure. Thus a polygon with a minimum of three sides is known as Triangle and it is also called 3-gon. An n-sided polygon is called n-gon.

@Kashish Sharma 4 years, 11 months ago

A flat shape with atleast 3,and usually 5 or more,angles and straight sides is called a polygon

ANSWER

There is a hexagon MNOPQR of side 5 cm. Aman and Ridhima divided into two different parts. Find the area of this hexagon using both sides.

Posted by Yatan Batth 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 4 years, 11 months ago

There are two ways of finding the area.

1) Dividing the hexagon into 6 equilateral triangles and getting the area of one triangle multiplied by 6.

2) Dividing the hexagon into two trapezium and getting the area of individual trapezium.

First we need the height of the equilateral triangle.

By pythagorean theorem we have :

5^2 - 2.5^2 = 18.75

Square root of 18.75 = 4.330

1) Area of one equilateral triangle :

4.330 × 0.5 × 5 = 10.825

For the six :

6 × 10.825 = 64.95 square centimeters.

2) The area of the trapezium is :

The two parallel sides of the trapezium are 10cm and 5 cm.

The height is 4.30cm

Area :

(10 + 5) /2 × 4.30 = 32.25

We have two trapezium.

2 × 32.28 = 64.5 square centimeter.

ANSWER

How many numbers lie between the square of 25;26

Posted by Srikanth Bittu 4 years, 11 months ago

CBSE > Class 08 > Mathematics

4 answers

Divy Sheokand 4 years, 11 months ago

according to the formulae n² -(n+1)²= 2n therefore ,25² -26²=2×25 =50

Dhruv Pandey 4 years, 11 months ago

Yogita Ingle 4 years, 11 months ago

We know that, 25² = 625
And, 26² = 676
Now, 676 - 625 = 51
So, there are 51 - 1 = 50 numbers lying between 25² and 26²

Shruti ? 4 years, 11 months ago

50 numbers

ANSWER

The scale of a map is given as 1 ratio 330 lacs to CTR 4 cm apart on the map find the actual distance between them

Posted by Gudiya Pandey 4 years, 11 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

A fruit vendor buys oranges at 6 for 10rupees and an equal no. at 10 for 20rupees he mixes them and sells at 21.60rupees per dozen. Find his gin or loss percent

Posted by Mahek Laskar 4 years, 11 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

10 men working for 6 days can complete 5 copies of a book.if there are eight men working to complete for copies of the book....how many days will it take?

Posted by Sanjeevani Goyan 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Yogita Ingle 4 years, 11 months ago

zten men working for 6 days =60 men's labour
working on 5 books
labour required per book = 60÷5
=12 men's labour

for 4 books, it would take =12×4 men's labour
=48 men's labour
men available =8
no. of days required = 48÷8 =6

Shruti ? 4 years, 11 months ago

→ 10 men working for 6 dyas can complete 5 copies of a book → number of copies filled by 10 members in 1 day is 1/6 → work done by 10 numbers on one book is 1/5 → if 8 men work for 4 copies in x days then → work done on one book per one days is 81×41×x1 but work done on one book by one person is same so, 32x=3001 x=9.375 days

ANSWER

PQ and RS are equal chords of a circle whose centre is A .If the chords intersect each other at X inside the circle, show that XP =XR and XQ=XS

Posted by Bisla Chingkheimayum 4 years, 11 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

A godown is in the form of a cuboid of measures 60m × 40m × 30m. How many cuboid boxes can be stored in it if the volume of one boxe is 0.8 m√3

Posted by Shreya Chawla 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Gaurav Seth 4 years, 11 months ago

A n s w e r
volume of godown = 60×40×30 = 72000 m³
volume of a box = 0.8 m³
so,
number of boxes = 72000/0.8 = 720000/8 = 90000 boxes

ANSWER

Expand 1256.249 using exponents

Posted by Reva Chitodkar 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Prasanta Manna 4 years, 11 months ago

Who are adivasis

ANSWER

a farmer buys a plot of agricultural land for rs 4,50,000. he sells one third at the loss of 15% and two fifth at a gain of 20%. at what price he must sell his remaining land so as to make an overall profit at 10%?

Posted by Ramanpreet Kaur 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Mohd Talha 4 years, 11 months ago

CP = 3600000. To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000. 1/3 of the land sold on 20% loss. SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000. SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000. SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000. Second Method SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000. So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000. SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000. Hence, SP of the remaining field = Rs. (396000-96000-180000). = Rs. 120000.

Yogita Ingle 4 years, 11 months ago

First Method

CP = 3600000.

To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.

1/3 of the land sold on 20% loss.

SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.

SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.

SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.

Second Method

SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000.

So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000.

SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000.

Hence,

SP of the remaining field = Rs. (396000-96000-180000).

= Rs. 120000.

ANSWER

Factorise x2 + 8x +16

Posted by Priyanka Longesha 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Priyanka Longesha 4 years, 11 months ago

Thanks

Yogita Ingle 4 years, 11 months ago

x²+8x+16

=x²+2(4)(x)+4²
=(x+4)² ...[∵(a−b)²=a²−2ab+b²]
=(x−4)(x−4)

ANSWER

By selling an article for 1636.25,a Dealer gains Rs 96.25.find his gain percentage

Posted by 8060 Vrinda Gupta 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Yogita Ingle 4 years, 11 months ago

The S.P. of an article = Rs. 1636.25

The dealer makes a profit = Rs. 96.25

We have the formula to calculate the gain and the gain percentage as:

∴ The cost price of the article is,

= S.P. - Gain

= Rs. 1636.25 - Rs. 96.25

= Rs. 1540

Now,

The gain percentage is,

Thus, his gain percentage is 6.25%.

ANSWER

if the length of two diagonals of a rhombus are 16 cm and 30 cm find the area and the length of the side of the rhombus ?

Posted by Khushi Tilani 4 years, 11 months ago

CBSE > Class 08 > Mathematics

2 answers

Raunak Singh 4 years, 11 months ago

area = 1/2 × product of diagonals so area = 1/2 × 30 ×16 = 240 cm² also diagonals bisect each other at right angles so 1/2×30= 15cm,,,, 1/2×16 =8cm therefore by Pythagoras theorem, 15² + 8² = side² √289 = side side = 17 cm thus perimeter = 4 × 17 = 68 cm

Gaurav Seth 4 years, 11 months ago

area = 1/2 × product of diagonals
so area = 1/2 × 30 ×16 = 240 cm²

also diagonals bisect each other at right angles
so 1/2×30= 15cm,,,, 1/2×16 =8cm

therefore by Pythagoras theorem,
15² + 8² = side²
√289 = side
side = 17 cm

thus perimeter = 4 × 17 = 68 cm