CBSE > Class 08 > Mathematics | CBSE Board | Homework Help

Given: Present value= ₹ 31250 Interest rate= 8 % per annum Time=1 ½ year= 3/2 year and compounded half yearly To find the amount we have the formula, Amount (A) = P (1+(R/100)2n Where P is present value, r is rate of interest, n is time in years. Now substituting the values in above formula we get, ∴ A = 31250 (1 + (8/2) /100)3 ⇒ A = 31250 (1+4/100)3 ⇒ A = 31250 (1+1/25)3 ⇒ A = 31250 (26/25)3 ⇒ A = 31250 × 17576/15625 ⇒ A = ₹ 35152 ∴ Compound interest = A – P = 35452 – 31250 = ₹ 3902Read more on Sarthaks.com - https://www.sarthaks.com/737718/find-the-amount-and-the-compound-interest-31250-for-year-per-annum-compounded-half-yearly?show=737720#a737720

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Find the amount and the compound interest on RS 8000 for 1 year at 10% per annum, compounded half-yearly. D) Find the amount and th

Posted by Narendra Choudhary 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Narendra Choudhary 4 years, 11 months ago

It is not

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What is the answer of 2x×5=30

Posted by Sandesh Shirke 4 years, 11 months ago

CBSE > Class 08 > Mathematics

3 answers

Shreya Jha 4 years, 11 months ago

2x * 5 =30 = 2x =30/5 = 2x =6 = x = 6/2 = (x=3) answer

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Divyansh Jain 4 years, 11 months ago

2x × 5 = 30 10x = 30 x = 30 ÷10 , x = 3 ( Answer ) Check - 2× 3 ×5 = 30 30 = 30

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Charvi Harjani 4 years, 11 months ago

x =3

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Write in fraction ‐ 3¾

Posted by Ayush Singh 4 years, 11 months ago

CBSE > Class 08 > Mathematics

4 answers

Shreya Jha 4 years, 11 months ago

15/4 answer

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Himani Choudhary 4 years, 11 months ago

15/4

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Divyansh Jain 4 years, 11 months ago

15/4

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Charvi Harjani 4 years, 11 months ago

15/4

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Solve the cube of 21

Posted by Bhawna Yadav 4 years, 11 months ago

CBSE > Class 08 > Mathematics

5 answers

Shreya Jha 4 years, 11 months ago

(21)3 = 21 x 21 x 21= 9261 answer

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Divyansh Jain 4 years, 11 months ago

9261

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Charvi Harjani 4 years, 11 months ago

21x21x21=9261

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Sandesh Shirke 4 years, 11 months ago

9261 is cube of 21

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Bhawna Yadav 4 years, 11 months ago

Find the cube of 21

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Find the amount and the compound interest on RS 8000 for 1 year at 10% per annum, compounded half-yearly.

Posted by Narendra Choudhary 4 years, 11 months ago

CBSE > Class 08 > Mathematics

3 answers

Divyansh Jain 4 years, 11 months ago

Principal = Rs. 8000 Rate = 10 % half - yearly R ÷ 2 = 10 ÷ 2 = 5 % T ( N or no. of years ) = 2× n = 2 × 1 years = 2 half - years A = P ( 1 + r/100 ) ^n A = Rs. 8000 ( 1 +5/100 ) ^2 A = Rs. 8000 ( 100 +5 /100 ) ^2 A = Rs. 8000 ( 105/100 ) ^2 A = Rs. 8000 ( 21/20 ) ^2 A = Rs. 8000 × 21/20 × 21/20 A = Rs. ( 20 × 441 ) A = Rs. 8820 C.I. = A - P C.I. = Rs. ( 8820 - 8000 ) C.I. = Rs. 220 ( Answer )

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Narendra Choudhary 4 years, 11 months ago

Answer will be in long

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Sandesh Shirke 4 years, 11 months ago

4000 is answer

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2;5 exercise

Posted by शम्भु सुखवाल 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

शम्भु सुखवाल 4 years, 11 months ago

Solve the following linear equation

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The walls and the ceiling of a hall 20 m × 16 × 10 m are to be painted. From each can of paint 130 m sq of area is painted. How many cans of paint are required to paint the room?

Posted by Sundram Jha 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Greeshma Sri K Pandu 4 years, 11 months ago

Area of walls +Area of ceiling =2(lh+bh)+lb 2(20×10+16×10 )+20×16 =2×360 +320=720+320=1040 No.of cans =1040/130 =8 cans of paints

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Total surface area of a cube

Posted by Afdhvn Ghbfj 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Anju Gahlot 4 years, 11 months ago

6.side

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Find the area of rhombus whose diagonals are 18cm and 12cm

Posted by Manan Rathi 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Anju Gahlot 4 years, 11 months ago

108

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The number of boys and girls in a class are in ratio 7:5 the number of boys is 8 more than the number of girls . what is total class strength

Posted by Pushpadant Katrale 4 years, 8 months ago

CBSE > Class 08 > Mathematics

1 answers

Sia ? 4 years, 8 months ago

Hint: Here we are given the ratio of girls and boys. So, we assume boys and girls as 7x and 5x respectively and then make an equation from the given condition. And after solving that equation we will get the value of x.

Complete step-by-step answer:

As we know that the ratio of the number of boys and girls in the class is given as 7 : 5.
So, if the number of boys in a class were 7x.
Then the number of girls should be 5x. Because their ratio is given as 7 : 5.
So, the strength of the class will be = number of boys in class + number of girls in class = 7x + 5x = 12x.
Now, we know that it is given in the question that the number of boys is 8 more than the number of girls.
So,
7x – 5x = 8
<nobr aria-hidden="true">⇒</nobr> $\Rightarrow$ <script type="math/tex" id="MathJax-Element-1">\Rightarrow</script> 2x = 8
On dividing both sides of the above equation by 2, we get,
<nobr aria-hidden="true">⇒</nobr> $\Rightarrow$ <script type="math/tex" id="MathJax-Element-2">\Rightarrow</script> x = 4
So, the number of boys should be equal to 7x =7*4 = 28.
Number of girls will be equal to 5x = 5*4 = 20
And the strength of the class will be 12x = 12*4 = 48.
Hence, the correct option will be A.

Note: Whenever we come up with this type of where we are given the ratio of boys and girls then we assume the number of boys and girls in terms of a variable x. Like if the ratio is a : b then if the number of boys is ax then the number of girls should be bx. And after that we make an equation from the given condition like here boys are 8 more than girls. On solving this equation, we will get the value of x. And after putting the value of x in the number of boys and girls we will get the number of boys and girls in class. So, the total strength of the class will be the sum of that.

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Find the area of a rohmbous whose diagonal are 8 cm and 10 cm

Posted by Abhinav J 4 years, 11 months ago

CBSE > Class 08 > Mathematics

4 answers

Anju Gahlot 4 years, 11 months ago

40sq.cm

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Manav Chohan 4 years, 11 months ago

Ex 9

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Abhinav J 4 years, 11 months ago

Using identity find ( 4.9)2=(5.0-0.1)2

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Gaurav Seth 4 years, 11 months ago

Area of rhombus = 1 / 2 × d 1 × d 2
= 1 / 2 × 8 × 1 0
= 4 × 10
Area of rhombus = 40 sq .cm

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The dimensions of a cuboid are in the ratio of 2:3:4 and its total surface area is 280m2. Find the dimensions.

Posted by Samia Ahmed 4 years, 11 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

Ans. (i)

Posted by Mohammad Saad Khan 4 years, 11 months ago

CBSE > Class 08 > Mathematics

1 answers

Saksham Srivastava 4 years, 11 months ago

Question ❓

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Solve (ଳଟ ହଜଭଜ଼୍ଵଧ ଭଳ ତଝ୍ଵଥ ଦଭ ଯମର୍କୃ )

Posted by Manidipa Mohanty 4 years, 11 months ago

CBSE > Class 08 > Mathematics

0 answers

ANSWER

Find the measure of each exterior angle of a regular polygan of 9 sides

Posted by Sakshi Shah 4 years, 11 months ago

CBSE > Class 08 > Mathematics

4 answers

Anupama Samantaray 4 years, 11 months ago

Sum of all exterior angles of a regular polygon=360° Each angle =360÷9=40°

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Mohd Talha 4 years, 11 months ago

Each exterior angle of a regular polygon of 9 sides =n360o, where n=9=(9360o)o=40o

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Shreya Jha 4 years, 11 months ago

this is an polygon with 9 sides so here n (no of sides) is 9. so the formula for finding the exterior angle of a regular polygon is = 360/n = 360/9 = 40 degree answer. thanks

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Banarasiya Don???? 4 years, 11 months ago

One exterior angle of a regular 9-sided polygon is 40°.

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2+2+10+4+8+9

Posted by Sanchita Nayak 4 years, 11 months ago

CBSE > Class 08 > Mathematics